PHP functions and arrays

[meekotherogue]

Just a quick question:
Are arrays in php pass by reference?

So if I had two functions:

function A($arr) { $arr[5]++; }
 
function B() { 
$arr = array();
$arr[5] = 0;
A($arr);
echo "The new value is: ".$arr[5];
}

Should print:
The new value is: 1;

??

[dlite922]

No they are not pass by reference,

The above code will out put: The new value is: 0

Thanks for playing,

Dan

[paulrajj]

If u want to print the result as 1, then u should use pass by reference.

function A($arr) { $arr[5]++; }
 
function B() { 
$arr = array();
$arr[5] = 0;
A(&$arr);  // pass by reference
echo "The new value is: ".$arr[5];
}
B();
 
 

Hence the output will be 1.

PHP References