Parse error: syntax error, unexpected '"' in ....

First thanks Scooby for your help.
I am trying to post data from 2 different scripts to the query you see below

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 $query = 'SELECT * FROM BIZ_APARTMENTS WHERE ((bizState="' . mysql_real_escape_string($_POST['b']) .

'"&&(bizCity="' . mysql_real_escape_string($_POST['c']) . '")';

the post data is coming from 2 different pages.

This one generates a drop down

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 <?php

/*  Program name: buildSelect.php

 *  Description:  Program builds a selection list

 *                from the database.

 */

?>

<html>

<head><title>Building info by state</title></head>

<body>

<?php

  $user="XXXXXXXXXXt";

  $host="XXXXXXXXXXXX";

  $password="XXXXXXXXX";

  $database = "XXXXXXXXXXXX";
 
  $cxn = mysqli_connect($host,$user,$password,$database)

         or die ("couldn't connect to server");

  $query = "SELECT DISTINCT bizState FROM BIZ_APARTMENTS ORDER BY bizState";

  $result = mysqli_query($cxn,$query)

            or die ("Couldn't execute query.");
 
 /* create form containing selection list */

  echo "<form action='processform41.php' method='POST'>

        <select name='b'>\n";
 
  while ($row = mysqli_fetch_assoc($result))

  {

     extract($row);

     echo "<option value='$bizState'>$bizState\n";

  }

  echo "</select>\n";

  echo "<input type='submit' value='Select State in which building is located'>

        </form>\n";

?>

</body></html>

and passes the info post [b] to this script

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 <?php
 
$username="XXXXXXXXX";

$password="XXXXXXXXXX";

$database="XXXXXXXXXXt";

$table="BIZ_APARTMENTS";

$column="bizState";
 
error_reporting(E_ALL);

mysql_connect("localhost",$username,$password);

@mysql_select_db($database) or die( "Unable to select database");
 
$query = "SELECT DISTINCT bizCity FROM BIZ_APARTMENTS WHERE bizState='" . mysql_real_escape_string($_POST['b']) . "'";
 
$result=mysql_query($query);

$ret = mysql_query($query) or die(mysql_error());

$num=mysql_numrows($result);
 
 echo "<b><center>Cities in State</center></b><br><br>";
 
 /* create form containing selection list */

  echo "<form action='city.php' method='POST'>

        <select name='c'>\n";
 
  $i=0;

  while ($i < $num) {
 
  $city=mysql_result($result,$i,"bizCity");
 
     echo "<option value='$city'>$city\n";

     $i++;

  }

  echo "</select>\n";

  echo "<input type='submit' value='Select City in which building is located'>

        </form>\n";

 print_r($result);
 
 ?>

which in turn should pass both post[b] and post[c] to this form for output

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 <?

$username="xxxxxxxxxx";

$password="xxxxxxxxxxx";

$database="xxxxxxxxx";

$table="xxxxxxxxx";

$column="bizState";

error_reporting(E_ALL);
 
mysql_connect("localhost",$username,$password);

@mysql_select_db($database) or die( "Unable to select database");
 
$query = 'SELECT * FROM BIZ_APARTMENTS WHERE ((bizState="' . mysql_real_escape_string($_POST['b']) .

'"&&(bizCity="' . mysql_real_escape_string($_POST['c']) . '")';
 
$result=mysql_query($query);

$ret = mysql_query($query) or die(mysql_error());

$num=mysql_numrows($result);
 
  mysql_close();
 
 echo "<b><center>Buildings in City</center></b><br><br>";
 
$i=0;

while ($i < $num) {

$name=mysql_result($result,$i,"bizName");

$address=mysql_result($result,$i,"bizAddr");

$city=mysql_result($result,$i,"bizCity");

$state=mysql_result($result,$i,"bizState");

$zip=mysql_result($result,$i,"bizZip");

$phone=mysql_result($result,$i,"bizPhone");

$email=mysql_result($result,$i,"bizEmail");
 
 echo "<b>Name: $name</b><br>Phone: $phone<br>Type: $type<br>Address: $address<br>City: $city<br>State: $state<br>Zip: $zip<br>Email:$email<br>";
 
$i++;

 }

print_r($city);

 ?>

BUT I am getting error message

Notice: Undefined index: b in /home/attorney/public_html/in-url.com/bigdump/city.php on line 15
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

thanks again, the help i have received from this forum has been priceless..

Jan 18 '10 #3

Scooby10

Could it be the && in the query? Try replacing that with AND..

Jan 18 '10 #4

8,658

Expert Mod 8TB

that’s not it, there’s simply no field named "b" in the last script.

Jan 18 '10 #5

so how do I transfer data from the field [b] in the first script into the 3rd script so the query in the 3rd script can use fields 'b' and 'c'?

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 $query = 'SELECT * FROM BIZ_APARTMENTS WHERE ((bizState="' . mysql_real_escape_string($_POST['b']) .

'"&&(bizCity="' . mysql_real_escape_string($_POST['c']) . '")';

Jan 18 '10 #6

8,658

Expert Mod 8TB

you could add a hidden field to pass down the b value

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echo '<input type="hidden" name="b" value="' . $_POST["b"] . '">';

Jan 18 '10 #7

First, let me say thank you again to both of you for you time and effort in helping me.
In my 3rd script, I am still getting the error:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

this is the script:

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 <?

$username="xxxxxxxxxx";

$password="xxxxxxxxx";

$database="xxxxxxxxxx";

$table="BIZ_APARTMENTS";

$column="bizState";
 
mysql_connect("localhost",$username,$password);

@mysql_select_db($database) or die( "Unable to select database");
 
$query = 'SELECT * FROM BIZ_APARTMENTS WHERE ((bizState="' . mysql_real_escape_string($_POST['b']) .

'"&&(bizCity="' . mysql_real_escape_string($_POST['c']) . '")';
 
$result=mysql_query($query);

$ret = mysql_query($query) or die(mysql_error());

$num=mysql_numrows($result);
 
  mysql_close();
 
 echo "<b><center>Buildings in City</center></b><br><br>";
 
$i=0;

while ($i < $num) {

$name=mysql_result($result,$i,"bizName");

$address=mysql_result($result,$i,"bizAddr");

$city=mysql_result($result,$i,"bizCity");

$state=mysql_result($result,$i,"bizState");

$zip=mysql_result($result,$i,"bizZip");

$phone=mysql_result($result,$i,"bizPhone");

$email=mysql_result($result,$i,"bizEmail");
 
 echo "<b>Name: $name</b><br>Phone: $phone<br>Type: $type<br>Address: $address<br>City: $city<br>State: $state<br>Zip: $zip<br>Email:$email<br>";
 
$i++;

 }

print_r($city);

 ?>

Also I am not getting any output either.

Thank you very much,
Josh

Jan 18 '10 #8

8,658

Expert Mod 8TB

there are 2 closing parentheses missing in the SQL.

Jan 18 '10 #9

Dormilich
Dude you are awesome, thanks ever so much. It always amazes when the s*** actually works.
Danke

Jan 18 '10 #10

8,658

Expert Mod 8TB

thinking like a parser helps. and experience.

Jan 18 '10 #11

Sorry about the profanity, it the Bronx in me that just comes out sometimes :-)

Jan 18 '10 #12

8,658

Expert Mod 8TB

that’s why there is an "edit" link.

Jan 18 '10 #13

How many years have you been programming?

Jan 18 '10 #14

8,658

Expert Mod 8TB

started with HTML and JS about 10 years ago and doing PHP for about 5 years. but that’s not much since I do it for a hobby.

Jan 18 '10 #15

I wish I kept up with it all from when I started.
I bought a TRS80 model1 in 1980, I was 13 and started doing BASIC.
The hard drive was a cassette recorder LOL.

Nowadays my motivation is business, and the use of php mysql to generate large dynamic sites for seo/marketing. I have five kids to feed.

Whats the best way (MAYBE THIS SHOULD BE A NEW THREAD) to convert those ugly urls with all those funky characters such as'?' into something much cleaner and seo friendly?

Jan 18 '10 #16

8,658

Expert Mod 8TB

"?" is not a funky character … but yes, that should be asked in another thread.

Jan 18 '10 #17

Atli

5,058

Expert 4TB

@riverdale1567
For Apace servers: mod_rewrite. There have been a few discussion on this here already, but you may want to start by checking this article out.

If you have any questions about this then I would appreciate it if you started a new thread. It's just better that way :)

Jan 18 '10 #18

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