How to get all set $_post ?

[Alino]

So I have a javascript on my page, which makes me able to add another input text field when I click on a button. And it's named "test" when I click the button it creates another input named test1, on another click it creates test2 and so on... But I have a problem on my form processing page, I need to get know which is the last "test" and also I need to set variables for each of them. I imagine some small code which will make something like this for me:

$test = $_POST('test');
$test2 = $_POST('test2');
$test3 = $_POST('test3');
$test4 = $_POST('test4');

And it will go on until last test. Thanks for helping me.

[Markus]

@Alino
There is a solution to this problem of yours - you can have your input elements become an array, that is to say, you can access them as an array inside the post array. To do this, you simply name the elements the same, and append '[]' to them, like so:

<input name="my_array[]" value="1" />
<input name="my_array[]" value="2" />
<input name="my_array[]" value="3" />
<input name="my_array[]" value="4" />
 

And to access those elements in PHP, you do something like so:

print_r($_POST['my_array']);
 
foreach($_POST['my_var'] as $key => $my_var) {
    printf("Key #%d has the value <strong>%s</strong>", $key, $my_var);
}
 

Mark.

[Alino]

thank you man, it works

[Markus]

@Alino
No problamo.

Mark.

[Alino]

now I have problem with imploding it

implode(" ", $pod_albumom_photo_id);

I receive the following error message then:

Warning: implode() [function.implode]: Invalid arguments passed in /storage/www1/9/site46049/wwwroot/xxx/process.php on line 90

what's wrong? ;[ how to fix it?

[Markus]

Seems like $pod_albumom_photo_id is not an array. What does var_dump($pod_albumom_photo_id); produce?

[Alino]

it produces

string(4) "12"

thats number of my inputs (4) and value from the last. "12"

[Markus]

@Alino
No, that can't be right; 4 should be the length of the string, and it says 'string' not 'array'. :S

[Alino]

so what i have to do to have it in array? :P

[dlite922]

@Alino
put empty brackets at the html form input name.

[Alino]

i have done that already, my code looks like

<script type="text/javascript">
 
function addfile()
{
var obj = document.getElementById("sprytextfield2").cloneNode(true);
document.getElementById('upfiles').appendChild(document.createElement('br') );
document.getElementById('upfiles').appendChild(obj);
}
 
</script>

        <fieldset class="border" id="upfiles">
        <legend>Vymazať fotku v profile pod albumom:</legend>
        <label for="pod_albumom_photo_id[]">ID fotky:</label><br />
        <span id="sprytextfield2">
        <input type="text" name="pod_albumom_photo_id[]" value="" onKeyPress="ipt_onkeypress()" />
<span class="textfieldInvalidFormatMsg">Iba cifry prosím. </span></span>
        <input class="button" type="button" value="Pridať pole" onclick="return addfile()" />
        </fieldset>

and in my form process page:

            foreach($_POST['pod_albumom_photo_id'] as $key => $pod_albumom_photo_id)
            {
            printf("Foto s ID <strong>%s</strong> bude vymazaná<br />", $pod_albumom_photo_id);
            }
            $x = implode(" ", $pod_albumom_photo_id);

now i just need to get it work, that implode.

[dlite922]

When you do a foreach, you're already "imploding" in a sense.

$_POST['pod_albumom_photo_id'] /is/ an array (do a var dump if you don't' believe me)

What do foreach's do? traverse arrays? to what? strings. thus $pod_albumom_photo_id is a string.

If you want it to be an array, just assign what's in the post:

$pod_albumom_photo_id = $_POST['pod_albumom_photo_id'];

TADA! you've got an array now you can implode.



Dan

[Alino]

man thank you, you make my day :) it just works !!! :D:D

[Alino]

my next problem is creating link of this $pod_albumom_photo_id
I wanted it to implode to be able to make link like

implode($iframe_part1 . "http://www.mywebpage.com/x.php?action=100&uid=" .$user_id. "&iid=", $pod_albumom_photo_id);

but then i noticed that i am not able to make those links because i can't add

$iframe_part2

after array. How to solve this?

[dlite922]

I don't get your question. Why can't you add a variable?

It looks like you're doing complex string building, why not stick with the foreach?

What is your expected results? What are your inputs and what do you want output? Give sample data.

Thanks,




Dan

[Alino]

that form on my page creates new html page, and in that html should be iframes with urls and in those urls are values from $pod_albumom_photo_id

so i was trying to implode that array to create those iframes, but it didnt close each iframe correctly only the last.

i am using this to write to new html file

...
$handle = fopen("$filepath", 'w+');
        if($handle)
{
 
    $all_what_to_do =
             "<html>
             <head><title>new html file</title></head>
             <body>
 
            </body>
            </html>"
            ;
 
            if(!fwrite($handle, "$all_what_to_do"))
            die("couldn't write to file.");
...

it works pretty good but
i don't know what to put inside body tag, to create those iframes with url in which are those values from $pod_albumom_photo_id

[Alino]

I am still seeking for help

[Alino]

nah i don't need help anymore, i found myself stupid and now i know how to do that, thanks to all for helping me guys, you are all really cool.