problem with implode() function

[tokcy]

Hi,
I am having a problem with implode() function in PHP.
whenever i am running my code it display an error like.

Warning: implode() [function.implode]: Bad arguments. in D:\xampp\htdocs\admin\addspecs.php on line 8

and my code is

$as = $_POST;
$i=1;
while($i<=16)
{
$ad = $as['txtRow'.$i];
$aw = implode(",",$ad);
$qw = "#".$aw;
echo $qw;
$i++;
}
 

what is the error in this code can anybody tell me.

[Dormilich]

the problem is that $ad is not an array (it's the value of a POST element). further you should call implode() outside the while-loop.

you can create arrays like

// repeat
$array[] = $value;
// or
$array[$key] = $value;

or use some of the array functions

[tokcy]

hi,

still i am not getting the solution. and how we can put the implode to outside of the while loop because all the text field name are unique and i can take the value of text fields without while loop.

[Dormilich]

what I wanted to say is, you need to change the code structure

while (…)
{
    // …
    $array[] = $_POST[$key];
}
$string = implode(",", $array);

[tokcy]

Now its not giving an error, but when i am trying to print the value it showing only array like this:
Array,Array,Array,Array,Array,Array,Array,Array,Ar ray,Array,Array,Array,Array,Array,Array,Array,Arra y,Array

$i=0;
while($i<=$count)
{
$arr[] = $_POST['txtRow'.$i];
$i++;
}
$str = implode(",",$arr);
echo $str;
 

[Dormilich]

looks like $_POST['txtRow'.$i] is an array. if you set error reporting to E_ALL you should get the according notices.

[hsriat]

I too think there's some problem with $_POST thingie itself. You should see what you are actually POST'ing to the page. Use

echo"<pre>"; print_r($_POST); echo "</pre>";

in the starting of the page. Then you can see what's going wrong.

Also, if you have to iterate through the POST'ed array anyhow, then you can just concat the POST variable instead of imploding it after converting it to another array.

while (condition) 
{
    $str .= $_POST[whatever];
    //increment thing
}
echo $str;