If condition under dropdown

[ddtpmyra]

Hi I need some help to learn how to do my dynamic dropdown. Basically on my dropdown I have value Others and when the user select this I want to display another text box beside it. Below is my codes but it didn't work I wonder where it went wrong.


Dropdown Menu:

echo "
<tr><td width='100%'><b>Generated By:</b></td>"; 
$res=mysql_query("select Generated_By  from tblGeneratedBy"); 
if(mysql_num_rows($res)==0){ 
echo "there is no data in table.."; 
} else { 
echo '
<td width="100%"><select name="GeneratedBy" id="GeneratedBy" value=\"$GeneratedBy\">'; 
for($i=0;$i<mysql_num_rows($res);$i++) { 
$row=mysql_fetch_assoc($res); 
echo"<option value=\"$row[Generated_By]\" "; 
if($GeneratedBy==$row[Generated_By]) 
echo "selected"; 
echo ">$row[Generated_By]</option>"; 
}
if $row[Generated_By]== ('Others') {
 echo "<input type='text' >";  else 
}echo 
"</select><br></tr></td>"; 
}     
 

[TheServant]

What didn't work? Please be more specific with the problem. Did the whole dropdown box not work or just your input box? Anyway, three things:
Line 17: you should be self closing your input tags ( <input /> not <input> ).
Line 17: You have not closed your if( ){ } statement before you have else.
Line 18: You have closed the previous if statement instead of opening the else statment.

Regards.