HELP: I got a "Parse error" when try to get data from form

[Steven]

I got a "Parse error: parse error in ..." in this line:

if(empty($_POST['ssn']){
.....

But if I fist assign $ssn=$_POST['ssn']; and then if(empty($ssn){ ... it is
working.

Any advice? Thanks in advance.

Reards,
-Steven

[Marcus]

So it still isn't working?

Steven wrote:

The error I got is:

Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or
`T_NUM_STRING'

Thanks.

"Steven" <xu*****@attbi.com> wrote in message
news:oqRLa.61294$R73.8171@sccrnsc04...

I got a "Parse error: parse error in ..." in this line:

if(empty($_POST['ssn']){
....

But if I fist assign $ssn=$_POST['ssn']; and then if(empty($ssn){ ... it

is

working.

Any advice? Thanks in advance.

Reards,
-Steven

[Steven]

Thanks !! My first post is a typo (missing the parenthesis ). But I just
make it work by using double quote for ssn:

if(empty($_POST["ssn"])){
....

The single quote will work if I assign the variable first, but won't work if
I don't. But it is working fine now with the double quote... Some kind of
type casting ?

-Regards,
Steven
"Marcus" <Ju********@aol.com> wrote in message
news:3E**************@aol.com...

So it still isn't working?

Steven wrote:

The error I got is:

Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or
`T_NUM_STRING'

Thanks.

"Steven" <xu*****@attbi.com> wrote in message
news:oqRLa.61294$R73.8171@sccrnsc04...

I got a "Parse error: parse error in ..." in this line:

if(empty($_POST['ssn']){
....

But if I fist assign $ssn=$_POST['ssn']; and then if(empty($ssn){ ... it

is

working.

Any advice? Thanks in advance.

Reards,
-Steven