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capturing query result

P: 333
how can I capture the query result in PHP?

I have two queries below:
[PHP]# Fetch the file information
$query ="update filestorage set approved ='Y' where FileID = {$id}";
$query1 ="select from members, filestorage where = members.username and FileID = {$id}" ;[/PHP]

then execute the query using command below:
[PHP] $result = @mysql_query($query) or die("Error! Query failed: <pre>". mysql_error($dbLink) ."</pre>");
$result1 = @mysql_query($query1) or die("Error! Query failed: <pre>". mysql_error($dbLink) ."</pre>");[/PHP]

assigning var $result1:
[PHP] echo "$result1";
$to = "$result1";[/PHP]

and when I tried to print the $result1 it shows
"Resource id #3"
where I'm expecting "email address" ( as a result :( Please anyone can show me how to do this in a right way.
Oct 25 '08 #1
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1 Reply

Expert 5K+
P: 6,050
You have to run it through one of mysql's functions such as mysql_fetch_array().

Expand|Select|Wrap|Line Numbers
  1. $result1 = @mysql_query($query1)  or die("Error! Query failed: <pre>". mysql_error($dbLink) ."</pre>");
  3. while($output = mysql_fetch_array($result1))
  4. {
  5.     echo $output['email'];
  6. }
Oct 25 '08 #2

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