Stale data when requerying MySQL w/PHP?

[bodhiSoma]

I've got this weird problem. I'm connecting to MySQL via PHP,
querying a particular table, closing the connection then parsing and
displaying the results. I then modify the table but when I reload the
PHP page, the output does not reflect this change.

Viz:

----[SQL query]----
mysqlselect * from users;
+----------+
| username |
+----------+
| jayds |
+----------+

----[web page output]----
Array ( [username] =jayds )

----[SQL query]----
mysqlinsert into users values ("wes");
Query OK, 1 row affected (0.00 sec)

----[reloaded web page output]----
Array ( [username] =jayds )

....and a rechecking of the db reflects that "wes" IS, in fact, in the
table.

This is the code I'm using (minus the parts that parse and print the
resource):

----[%begin%]----

$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error
connecting to mysql');

mysql_select_db('wes') or die('Could not select database');

$query = "SELECT * FROM users";
$resource = mysql_query($query) or die('Query failed: ' .
mysql_error());
mysql_close($conn);

----[%end%]----

Any ideas on why I'm seeing stale data?

Thanks much in advance!,
Jason

[Jerry Stuckle]

bodhiSoma wrote:

I've got this weird problem. I'm connecting to MySQL via PHP,
querying a particular table, closing the connection then parsing and
displaying the results. I then modify the table but when I reload the
PHP page, the output does not reflect this change.

Viz:

----[SQL query]----
mysqlselect * from users;
+----------+
| username |
+----------+
| jayds |
+----------+

----[web page output]----
Array ( [username] =jayds )

----[SQL query]----
mysqlinsert into users values ("wes");
Query OK, 1 row affected (0.00 sec)

----[reloaded web page output]----
Array ( [username] =jayds )

...and a rechecking of the db reflects that "wes" IS, in fact, in the
table.

This is the code I'm using (minus the parts that parse and print the
resource):

----[%begin%]----

$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error
connecting to mysql');

mysql_select_db('wes') or die('Could not select database');

$query = "SELECT * FROM users";
$resource = mysql_query($query) or die('Query failed: ' .
mysql_error());
mysql_close($conn);

----[%end%]----

Any ideas on why I'm seeing stale data?

Thanks much in advance!,
Jason

Caching - either by your browser or a system between your web server and
your client?

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attglobal.net
==================

[FutureShock]

bodhiSoma wrote:

I've got this weird problem. I'm connecting to MySQL via PHP,
querying a particular table, closing the connection then parsing and
displaying the results. I then modify the table but when I reload the
PHP page, the output does not reflect this change.

Viz:

----[SQL query]----
mysqlselect * from users;
+----------+
| username |
+----------+
| jayds |
+----------+

----[web page output]----
Array ( [username] =jayds )

----[SQL query]----
mysqlinsert into users values ("wes");
Query OK, 1 row affected (0.00 sec)

----[reloaded web page output]----
Array ( [username] =jayds )

...and a rechecking of the db reflects that "wes" IS, in fact, in the
table.

This is the code I'm using (minus the parts that parse and print the
resource):

----[%begin%]----

$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error
connecting to mysql');

mysql_select_db('wes') or die('Could not select database');

$query = "SELECT * FROM users";
$resource = mysql_query($query) or die('Query failed: ' .
mysql_error());
mysql_close($conn);

----[%end%]----

Any ideas on why I'm seeing stale data?

Thanks much in advance!,
Jason

You performed an INSERT not an UPDATE.

Could it be that you have both entires in your DB and only viewing one
of them retrieved?

The code you show is incomplete so its hard to tell.

If you follow the code you have with:

while($user = mysql_fetch_array($resource)) {
echo $user[username]."<br>";
}

Will it show the only one entry?

Also not sure if this is in your actual code or just typed it wrong in
here but:

$resource = mysql_query($query) or die('Query failed: ' .

is missing the last )

Scotty

[bodhiSoma]

On Sep 28, 5:27*pm, FutureShock <[e-mail]:

Could it be that you have both entires in your DB and only viewing one
of them retrieved?

That was precisely it. Thanks!!

Jason

[FutureShock]

bodhiSoma wrote:

On Sep 28, 5:27 pm, FutureShock <[e-mail]:

>Could it be that you have both entires in your DB and only viewing one
of them retrieved?

That was precisely it. Thanks!!

Jason

Glad to help. Don't be a stranger.

Scotty