Returning variables

[Odisey]

What is wring with this?

<?php  #Color instrument vars
       # ODC August 4, 2008
 
require_once ('??????.php'); //Connect to database  RESET TO SAFE PATH ONCE IT FUNCTIONS
 
// Define variables
 
$var1 = "Hello"; 
 
// Make selection  
 
$query = "SELECT images FROM movie_images ORDER BY RAND() LIMIT 3";
$result = mysql_query($query);
 
// Table
 
if ($result) {
    $row = mysql_fetch_array ($result, MYSQL_ASSOC);
    $s1 = $row[0];
    $s2 = $row[1];
    $s3 = $row[2];
 
 
echo '<p>'. $s1 . '</p>';
echo '<p>'. $s2 . '</p>';
echo '<p>'. $s3 . '</p>';
echo '<p>'. $var1 . '</p>';
}
 
 
 
mysql_close(); // Close database connection
 
?>
 
 
 

Thank you!

[Markus]

We don't guess.

Please be more descriptive.

What happens? What doesn't happen?

[Odisey]

The test variable Hello prints.... Other than that nothing happens...


Nothing obviously wrong with the syntax?


Thatnk you,
Marc

[Markus]

The test variable Hello prints.... Other than that nothing happens...


Nothing obviously wrong with the syntax?


Thatnk you,
Marc

You should always do some error checking; add an ELSE to your IF and an OR DIE() to your mysql query

$query = "SELECT images FROM movie_images ORDER BY RAND() LIMIT 3";
$result = mysql_query($query) or die(mysql_error());
 
// Table
 
if ($result) {
    $row = mysql_fetch_array ($result, MYSQL_ASSOC);
    $s1 = $row[0];
    $s2 = $row[1];
    $s3 = $row[2];
 
 
echo '<p>'. $s1 . '</p>';
echo '<p>'. $s2 . '</p>';
echo '<p>'. $s3 . '</p>';
echo '<p>'. $var1 . '</p>';
} else {
echo 'There was a problem...';
}

Please remember to use code tags when posting in the forum!

[Odisey]

I usually do.

It prints the test var Hello..... Nothing else...


The error message does not print.

[pbmods]

Heya, Odisey.

There might be no error; your query might just have returned no results.

[Odisey]

There is one that is there.... Look at ASSOC. It should be NUM.

There are results... 8 AMF.


TYFR