New problem ;). I got script running and showing projects, now i'm trying to
show category for every project from another table. I want to do this in new
page. Everything is fine except ;))... it shows the data in according with
how many projects i have. So if i have 3 project da data from category table
is shown three times, if two projects it's shown two times etc.
The code is following:
<?php
require('config.php');
$conn = mysql_connect(SQL_HOST, SQL_USER, SQL_PASS) or
die ('Could not connect to MySQL database.' .mysql_error());
mysql_select_db (SQL_DB, $conn);
$display_block = "<h1>$project_name</h1>
<P>Select a Category to see details.</P>";
//validate category
$cat_id_info = isset($_GET['id']) ? intval($_GET['id']) : 0;
$get_info = "SELECT
category.id,
category.project_id,
category.cat_name,
category.cat_desc,
project.project_name,
project.id
FROM
category,
project
WHERE
category.project_id = $cat_id_info
ORDER BY category.cat_name";
$result = mysql_query($get_info) or die (mysql_error());
$num_category = mysql_num_rows($result);
$display_block .= "<a href=\"proba_link.php\">Back</a></strong></p>";
if (mysql_num_rows($result) < 1) {
$display_block = "<P><em>BLABLA.</em><br>
<a href=\"proba_link.php\">Back</a></strong></p>";
} else {
while ($cat = mysql_fetch_array($result)) {
$cat_id = $cat[id];
$cat_name = strtoupper(stripslashes($cat[cat_name]));
$cat_desc = stripslashes($cat[cat_desc]);
$display_block .= "<p><strong>$cat_name</strong>
<br>$cat_desc</p>";
}
}
?>
<HTML>
<HEAD>
<TITLE>Navtec Marine</TITLE>
</HEAD>
<BODY>
<?
print $display_block;
?>
</BODY>
</HTML>
Tnx in advance, best regards
Igor Slivka
