shell script - to not change working directory to that of the script

[John]

Hi,

I'm running a PHP script from a shell (bash, ...) - not from a web
server.

So I use a script of the form:

#!/usr/bin/php
<?php
var_dump($argv);
?>

and then I can run the script directly, rather than:
[user]# php -f script_name

Running the script this way changes the current directory to that of
the script.

I don't want this behaviour - I want the current directory to be from
where I run the script, so I can write the PHP code to work on 'local'
files (./*) - just like it should for CLI SAPI interface.

I can't use the -C option (PHP throws an error) like:

#!/usr/bin/php -q -C

Anyone know how to do what I want ?

System: Linux Fedora Core 1, PHP Version 4.3.8

Thanks,
John.

[Gert]

> I don't want this behaviour - I want the current directory to be from

where I run the script, so I can write the PHP code to work on 'local'
files (./*) - just like it should for CLI SAPI interface.

John,

Can't you simply give your script a parameter of the needed working
directory and then
use the chdir()-command to change the script's current directory?

regards,

Gert.