returning an array

[Jeff]

I'd like to do this:

function makeAnArray(){
$array = array('one'=>'1','two'=array('more than one'=>'dimension'));

return $array;
}

$a = makeAnArray();

// $a is ('one'=>'1','two'=array('more than one'=>'dimension'))

But with the right syntax. How do I do this?

(in perl I'd return a reference and then do a type conversion)

Jeff

[=?UTF-8?B?SXbDoW4gU8OhbmNoZXogT3J0ZWdh?=]

Jeff wrote:

$array = array('one'=>'1','two'=array('more than one'=>'dimension'));

$array = array('one'=>'1','two'=>array('more than one'=>'dimension'));
--
----------------------------------
Iván Sánchez Ortega -ivansanchez-algarroba-escomposlinux-punto-org-

A bus station is where buses stop. A train station is where trains stop. On
my desk, there is a workstation...

[Jeff]

Iván Sánchez Ortega wrote:

Jeff wrote:

>$array = array('one'=>'1','two'=array('more than one'=>'dimension'));

$array = array('one'=>'1','two'=>array('more than one'=>'dimension'));

Yes, a typo. The actual code though is drawing from an unserialized
file, so I know the syntax php generated is corrected is correct. I also
checked the array just before it got returned and it looked fine.

Are you saying that I can return an array that way?

Jeff

[Captain Paralytic]

On Jun 20, 4:12*pm, Jeff <jeff@spam_me_not.comwrote:

Iván Sánchez Ortega wrote:

Jeff wrote:

$array = array('one'=>'1','two'=array('more than one'=>'dimension'));

* $array = array('one'=>'1','two'=>array('more than one'=>'dimension'));

Yes, a typo. The actual code though is drawing from an unserialized
file, so I know the syntax php generated is corrected is correct. I also
checked the array just before it got returned and it looked fine.

* *Are you saying that I can return an array that way?

Yes, didn't you think of trying it?

I find it a lot quicker to try simple things like this out instead of
writing a post to a forum such as this.

[Erwin Moller]

Jeff schreef:

Iván Sánchez Ortega wrote:

>Jeff wrote:

>>$array = array('one'=>'1','two'=array('more than one'=>'dimension'));

$array = array('one'=>'1','two'=>array('more than one'=>'dimension'));

Yes, a typo. The actual code though is drawing from an unserialized
file, so I know the syntax php generated is corrected is correct. I also
checked the array just before it got returned and it looked fine.

Are you saying that I can return an array that way?

Jeff

Yes,

$myArr = array (
1 =12,
50 ="hello fifty",
"IamAssoc" =array(23,45,77),
"meToo" =array("one" =1, "two" =2)
)

is perfectly fine.

Regards,
Erwin Moller

[Jeff]

Captain Paralytic wrote:

On Jun 20, 4:12 pm, Jeff <jeff@spam_me_not.comwrote:

My apologies...

>Iván Sánchez Ortega wrote:

>>Jeff wrote:
$array = array('one'=>'1','two'=array('more than one'=>'dimension'));
$array = array('one'=>'1','two'=>array('more than one'=>'dimension'));

Yes, a typo. The actual code though is drawing from an unserialized
file, so I know the syntax php generated is corrected is correct. I also
checked the array just before it got returned and it looked fine.

Are you saying that I can return an array that way?

Yes, didn't you think of trying it?

I tried this in a function in a class, and sprinkled in some echos to
track the data to see where the problem was.

When I try the very same script now, it works. Perhaps I made some
other mistake... Unfortunately, it's not the craziest thing (not
programming though) that's happened today!

Jeff

>
I find it a lot quicker to try simple things like this out instead of
writing a post to a forum such as this.