I'm developing a wap site with wml and php.
my php code is retrievig and displaying blob image from database.
but i cannot include any wml part to this page.
actually i want to display image from database with some links.
is it possible ? plz help me....
my php code is.... -
<?php
-
function db_connect($user='root', $password='admin', $db='example')
-
{
-
mysql_connect('localhost', $user, $password) or die('I cannot connect to db: ' . mysql_error());
-
mysql_select_db('example');
-
}
-
db_connect();
-
$sql = "select imgdata from pix where title=2";
-
-
-
$result = mysql_query("$sql");
-
while($row = mysql_fetch_assoc($result))
-
{
-
$bytes = $row['imgdata'];
-
}
-
header("Content-type: image/jpeg");
-
echo $bytes;
-
exit ();
-
mysql_close();
-
?>
-
8  1538 
Is is possible - everything is possible with PHP; even interstellar domination!
I have no idea what WML is - wireless markup language?
Actually, re-looking at your code, you display an image page.. not a html/whateverelse type. The only way you can put text onto this page is if make a html page and echo the image onto it.
thanks 4 replay.
but if i give one single echo ( eg : echo"hellow world";)
before header("Content-type: image/jpeg");
i m getting the following output...
-----------------------------------------------------------------------------------------------------
hellow world
Warning: Cannot modify header information - headers already sent by
(output started at C:\web\htdocs\show\image.php:7) in C:\web\htdocs\show\image.php on line 15
ÿØÿàJFIF``ÿá ExifMM*bj(1 r2Ž‡i¤Ð¦'
H¼—«ÿ?îÛ„ætºDûiÇ?cùÛòÿæöý:+¡tÿ㇦fäâàg.....
----------------------------------------------------------------------------------------------------------
actually my requrement to display image from database with some links.(its a wap site)
thanks 4 replay.
but if i give one single echo ( eg : echo"hellow world";)
before header("Content-type: image/jpeg");
i m getting the following output...
-----------------------------------------------------------------------------------------------------
hellow world
Warning: Cannot modify header information - headers already sent by
(output started at C:\web\htdocs\show\image.php:7) in C:\web\htdocs\show\image.php on line 15
ÿØÿàJFIF``ÿá ExifMM*bj(1 r2Ž‡i¤Ð¦'
H¼—«ÿ?îÛ„ætºDûiÇ?cùÛòÿæöý:+¡tÿ㇦fäâàg.....
----------------------------------------------------------------------------------------------------------
actually my requrement to display image from database with some links.(its a wap site)
Like I said: you cannot echo anything apart from image data because this is an image data page.
actually i want to display an image from database with a link to another php file.
how can i do this ?
can u tell me any idea ? / (any sample code ?)
 actually i want to display an image from database with a link to another php file.
how can i do this ?
can u tell me any idea ? / (any sample code ?)
Something like this (you'll have to fill in the variables yourself):
html page - -
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
-
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
-
<head>
-
</head>
-
-
<body>
-
-
<a href="img.php?id=some_id" />
-
<img src="img.php?id=some_id" />
-
</a>
-
-
</body>
-
img.php - -
$id = $_GET['id']; #escape this
-
-
function db_connect($user='root', $password='admin', $db='example')
-
{
-
mysql_connect('localhost', $user, $password) or die('I cannot connect to db: ' . mysql_error());
-
mysql_select_db('example');
-
}
-
db_connect();
-
$sql = "select imgdata from pix where title='{$id}'";
-
-
-
$result = mysql_query($sql);
-
while($row = mysql_fetch_assoc($result))
-
{
-
$bytes = $row['imgdata'];
-
}
-
header("Content-type: image/jpeg");
-
echo $bytes;
-
exit ();
-
mysql_close();
-
This is just an example.
ok. i tried this , when i click the link its displaying image .
but there is no " link " in the image page....(image is displaying without any link)
then how can i go to next page after displaying the image ?
ok. i tried this , when i click the link its displaying image .
but there is no " link " in the image page....(image is displaying without any link)
then how can i go to next page after displaying the image ?
OK.
Have a page, img.php, that does all the pulling of the image data.
Then have another page, display.php, that is dynamic. By that I mean, the page is passed a parameter through the URL - display.php?id=some_id
You then use this id and pass it to img.php so it can output the image. You would then create a link that gets the next image id - display.php?id=another_id
its working....
Thank u very much...
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