JSON member access issue

[Logos]

I am using PHP with the JSON extension function json_decode.

I have a JSON with a member named "1" (ie) { "1":"somedata" }

Trying to access this via the -operator doesn't work, nor does
["1"].

Putting the JSON into a foreach loop DOES access the member:

foreach($json as $key=>$value) {
echo("$key<br />");
}
//outputs '1'

Is this an error on my part, an oversight in the PHP JSON
implementation, or something else? Why can foreach grab the members,
but I can't access them?

Thanks for your time!

Tyler

[Rik Wasmus]

On Tue, 22 Apr 2008 20:32:28 +0200, Logos <ty*********@gmail.comwrote:

I am using PHP with the JSON extension function json_decode.

I have a JSON with a member named "1" (ie) { "1":"somedata" }

Trying to access this via the -operator doesn't work, nor does
["1"].

Putting the JSON into a foreach loop DOES access the member:

foreach($json as $key=>$value) {
echo("$key<br />");
}
//outputs '1'

Is this an error on my part, an oversight in the PHP JSON
implementation, or something else? Why can foreach grab the members,
but I can't access them?

The problem is that while json_decode is able to extract it:
object(stdClass)#1 (1) {
["1"]=>
string(8) "somedata"
}

"1" is not a valid property name to use directly.

Workarounds:
Option 1, suitable for single known variable:
<?php
$var = json_decode('{ "1":"somedata" }');
$name = '1';
echo $var->$name;
?>

Option 2, suited for more generic processing:
<?php
function json_object_to_named_array($var){
if(!is_object($var)){
trigger_error('No object given');
return;
}
$return = get_object_vars($var);
foreach($return as &$value){
if(is_object($value)) $value = json_object_to_named_array($value);
}
return $return;
}
$test = array('foo' ='bar','foz' =array('fox' ='bax'));
$json = json_encode($test);
var_dump($json);
$var = json_decode($json);
var_dump($var);
$var = json_object_to_named_array($var);
var_dump($var);
?>
Output:
string(33) "{"foo":"bar","foz":{"fox":"bax"}}"
object(stdClass)#1 (2) {
["foo"]=>
string(3) "bar"
["foz"]=>
object(stdClass)#2 (1) {
["fox"]=>
string(3) "bax"
}
}
array(2) {
["foo"]=>
string(3) "bar"
["foz"]=>
array(1) {
["fox"]=>
string(3) "bax"
}
}
--
Rik Wasmus

[Logos]

On Apr 22, 3:14 pm, "Rik Wasmus" <[e-mail]:

On Tue, 22 Apr 2008 20:32:28 +0200, Logos <[e-mail]:

I am using PHP with the JSON extension function json_decode.

I have a JSON with a member named "1" (ie) { "1":"somedata" }

Trying to access this via the -operator doesn't work, nor does
["1"].

Putting the JSON into a foreach loop DOES access the member:

foreach($json as $key=>$value) {
echo("$key<br />");
}
//outputs '1'

Is this an error on my part, an oversight in the PHP JSON
implementation, or something else? Why can foreach grab the members,
but I can't access them?

The problem is that while json_decode is able to extract it:
object(stdClass)#1 (1) {
["1"]=>
string(8) "somedata"

}

"1" is not a valid property name to use directly.

Workarounds:
Option 1, suitable for single known variable:
<?php
$var = json_decode('{ "1":"somedata" }');
$name = '1';
echo $var->$name;
?>

Option 2, suited for more generic processing:
<?php
function json_object_to_named_array($var){
if(!is_object($var)){
trigger_error('No object given');
return;
}
$return = get_object_vars($var);
foreach($return as &$value){
if(is_object($value)) $value = json_object_to_named_array($value);
}
return $return;}

$test = array('foo' ='bar','foz' =array('fox' ='bax'));
$json = json_encode($test);
var_dump($json);
$var = json_decode($json);
var_dump($var);
$var = json_object_to_named_array($var);
var_dump($var);
?>
Output:
string(33) "{"foo":"bar","foz":{"fox":"bax"}}"
object(stdClass)#1 (2) {
["foo"]=>
string(3) "bar"
["foz"]=>
object(stdClass)#2 (1) {
["fox"]=>
string(3) "bax"
}}

array(2) {
["foo"]=>
string(3) "bar"
["foz"]=>
array(1) {
["fox"]=>
string(3) "bax"
}}

--
Rik Wasmus

Ah, I thought it might be something like that then. The JSON notation
is perfectly fine, but PHP's grammar won't let me directly access the
incompatible JSON format. I shall just have to live with it then.

Thanks!

Tyler

[Alexey Kulentsov]

Logos wrote:

Ah, I thought it might be something like that then. The JSON notation
is perfectly fine, but PHP's grammar won't let me directly access the
incompatible JSON format. I shall just have to live with it then.

:)

Try echo $var->{1};

[Logos]

On Apr 23, 6:18 pm, Alexey Kulentsov <[e-mail]:

Logos wrote:

Ah, I thought it might be something like that then. The JSON notation
is perfectly fine, but PHP's grammar won't let me directly access the
incompatible JSON format. I shall just have to live with it then.

:)

Try echo $var->{1};

YOU, sirrah, are my HERO! Thank you much much much!!!

:D

Tyler

[Dave Benjamin]

Logos wrote:

I am using PHP with the JSON extension function json_decode.

I have a JSON with a member named "1" (ie) { "1":"somedata" }

Trying to access this via the -operator doesn't work, nor does
["1"].

Looks like you're already on your way, but just FYI, the json_decode
function takes an optional second argument that will, if true, cause
objects to be returned as associative arrays instead. Then, the usual
array notation (["1"]) should work.

Dave

[Rik Wasmus]

On Wed, 30 Apr 2008 03:39:16 +0200, Dave Benjamin
<ra***@lackingtalent.comwrote:

Logos wrote:

>I am using PHP with the JSON extension function json_decode.
I have a JSON with a member named "1" (ie) { "1":"somedata" }
Trying to access this via the -operator doesn't work, nor does
["1"].

Looks like you're already on your way, but just FYI, the json_decode
function takes an optional second argument that will, if true, cause
objects to be returned as associative arrays instead. Then, the usual
array notation (["1"]) should work.

D'OH! Going through all that trouble writing a recursive function...
--
Rik Wasmus

[Logos]

On Apr 29, 6:39 pm, Dave Benjamin <[e-mail]:

Logos wrote:

I am using PHP with the JSON extension function json_decode.

I have a JSON with a member named "1" (ie) { "1":"somedata" }

Trying to access this via the -operator doesn't work, nor does
["1"].

Looks like you're already on your way, but just FYI, the json_decode
function takes an optional second argument that will, if true, cause
objects to be returned as associative arrays instead. Then, the usual
array notation (["1"]) should work.

Dave

Keen - I may try that too. Good to know for future reference, in any
event!

Tyler