PHP 5 Includes are not working

[chromis]

Hi there,

I am trying to include a php file with an argument and having rather alot of trouble with it.

This is my code:

include_test.php?storeID=22

<?php 
 // File to include into
 session_start();
 include_once("http://website.com/echo.php?storeID=".$_GET['storeID']);
?>
 

echo.php

<?php 
 echo "hello" . $_GET['storeID'];
?>
 

I get the following error though:

Warning: include_once(http://threebox.turntool.com/coventgarden/functions/js/echo.php?storeID=22) [function.include-once]: failed to open stream: HTTP request failed! HTTP/1.1 401 Unauthorized in c:\Inetpub\wwwroot\website.com\include_test.php on line 3
 
Warning: include_once() [function.include]: Failed opening 'http://website.com/echo.php?storeID=22' for inclusion (include_path='.;c:\php\includes;c:\Inetpub\wwwroot\website.com\') in c:\Inetpub\wwwroot\website.com\include_test.php on line 3
 

I have enabled fopen wrappers to see if that would help but it didnt. I've also added a new include dir to the include_path in php.ini and the correct php.ini is being displayed in phpinfo().

I've also tryed to include the file like this:

<?php 
 // File to include into
 session_start();
 include_once("echo.php?storeID=".$_GET['storeID']);
?>
 

That doesn't work either, any ideas?
I'm running PHP 5 in ISAPI mode on IIS.

Thanks,

Chromis


-

[nathj]

Hi,

Whenever I want to do something like this I don't bother with the query string on the end of the URL as like you I've never got that to work and I don't know if it's supposed to work.

What I do is to simply define the variables I want to use before I issue the include. The include effectively sucks all the code into the position where the include line is and so the variables are available.

Psuedo Code
[php]
$Var1 = "TestVar1";
$var2 = 3 ;
include("include/testpage.php") ;
//rest of file
[/php]

In the included file you can simply use these as $var1 and $var2.

I hope this helps you out
Cheers
nathj

[chromis]

Hi NathJ,

Thanks for your help that definately works now. I would be still interested to know if anyone else has got it to work in this particular way?

Thanks again,

Chromis

[nathj]

Hi NathJ,

Thanks for your help that definately works now. I would be still interested to know if anyone else has got it to work in this particular way?

Thanks again,

Chromis

Hi Chromis,

I'm glad it's working for you, I am also interested to know if anyone else has made it work in the way you outlien - an included file with a query string. I think the issue is that the include reads the whole thing as the file name and as the file name doesn't include a query string the function fails because it can't find the file.

That's my understanding of it - but I'm keen to hear if anyone else knows differently.

Cheers
nathj

[Markus]

Hi Chromis,
I think the issue is that the include reads the whole thing as the file name and as the file name doesn't include a query string the function fails because it can't find the file.

That makes sense to me, it searchers for the file you specify including whatever params you add to the file name.

[zotrik]

Hi,

Thanks, it helped me.

There's only one thing I don't understand; on PHP 4 if you write something like:

include 'file.php' . $_SERVER['QUERY_STRING'];

it actually works... I wonder...

But it all makes sense that it doesn't work because of the file extension on PHP 5

[Dormilich]

include/require are not functions, but language constructs, thus they may be called without parentheses.

From the Manual:

Because include() is a special language construct, parentheses are not needed around its argument. Take care when comparing return value.

[Markus]

@zotrik
I highly doubt that it works.

As I have said before in this thread, whatever you pass to include*, require*, etc., is what is looked for on the file system. That is, if, you pass it "/var/www/includes/file.php?var1=10" it will look for that exact file name, including the '?var=10'. Ergo, unless that file *does* exist on your system, it won't work as expected.