Image problem with $_FILES and $_POST

[Karl]

Hello again.
I have a form for posting news articles.

Form one is the "register" form.
Then I go to the preview form were I can select edit or accept

If I select edit, I got the "edit form" and if I select accept, I
receive a message that say:

The news article "headline" are posted into the database.

When I use the file field and browse to "my photos", select an image
and post it. I can see it in the priview form/page and can also show
it in the article.

But if I select the "edit" button I can't see the image.
I am using <input type="hidden" name="article_photo"
value="$article_foto"field to preserve the value of the field:
<input type="file" name="article_photo">

Well. I discover that if I not have anything in the field <input
type="file" name="article_photo"...
but still have the image.jpg in the hidden field. It use the
$_POST["article_photo"] insted of
$_FILES["article_photo"];

So I was thinking that this below should do the trick:

if(!isset($_FILES["article_photo"])){
$article_photo = $_POST["article_photo"];
} else {
$article_photo = $_FILES["article_photo"];
}

But still the image are not avaible in the edit or preview pages in
the variable $article_photo
BUT if I use the file field and browse, select an image and post it.
Then it show up in those pages.

How can I fix this? Is it better to use setcookie("article_photo",
$_POST['article_photo'] time()+30);

Thanks for all advice. (and sorry my weak english)

Karl

[Jerry Stuckle]

Karl wrote:

Hello again.
I have a form for posting news articles.

Form one is the "register" form.
Then I go to the preview form were I can select edit or accept

If I select edit, I got the "edit form" and if I select accept, I
receive a message that say:

The news article "headline" are posted into the database.

When I use the file field and browse to "my photos", select an image
and post it. I can see it in the priview form/page and can also show
it in the article.

But if I select the "edit" button I can't see the image.
I am using <input type="hidden" name="article_photo"
value="$article_foto"field to preserve the value of the field:
<input type="file" name="article_photo">

Well. I discover that if I not have anything in the field <input
type="file" name="article_photo"...
but still have the image.jpg in the hidden field. It use the
$_POST["article_photo"] insted of
$_FILES["article_photo"];

So I was thinking that this below should do the trick:

if(!isset($_FILES["article_photo"])){
$article_photo = $_POST["article_photo"];
} else {
$article_photo = $_FILES["article_photo"];
}

But still the image are not avaible in the edit or preview pages in
the variable $article_photo
BUT if I use the file field and browse, select an image and post it.
Then it show up in those pages.

How can I fix this? Is it better to use setcookie("article_photo",
$_POST['article_photo'] time()+30);

Thanks for all advice. (and sorry my weak english)

Karl

Do you have the image file name in a <img...tag?

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attglobal.net
==================

[Karl]

On 29 Des, 15:54, Jerry Stuckle <[e-mail]:

Karl wrote:

Hello again.
I have a form for posting news articles.

Form one is the "register" form.
Then I go to the preview form were I can select edit or accept

If I select edit, I got the "edit form" and if I select accept, I
receive a message that say:

The news article "headline" are posted into the database.

When I use the file field and browse to "my photos", select an image
and post it. I can see it in the priview form/page and can also show
it in the article.

But if I select the "edit" button I can't see the image.
I am using <input type="hidden" name="article_photo"
value="$article_foto"field to preserve the value of the field:
<input type="file" name="article_photo">

Well. I discover that if I not have anything in the field <input
type="file" name="article_photo"...
but still have the image.jpg in the hidden field. It use the
$_POST["article_photo"] insted of
$_FILES["article_photo"];

So I was thinking that this below should do the trick:

if(!isset($_FILES["article_photo"])){
$article_photo = $_POST["article_photo"];
} else {
$article_photo = $_FILES["article_photo"];
}

But still the image are not avaible in the edit or preview pages in
the variable $article_photo
BUT if I use the file field and browse, select an image and post it.
Then it show up in those pages.

How can I fix this? Is it better to use setcookie("article_photo",
$_POST['article_photo'] time()+30);

Thanks for all advice. (and sorry my weak english)

Karl

Do you have the image file name in a <img...tag?

Yes, I have.

And it works if I use the <input type="file" name="article_photo">
field.
$article_photo = $_FILES["article_photo"]; make it work.
But when I have the image.jpg registred in a <input type="hidden"...
field, it does not work.

I think that this hidden field use the $_POST["article_photo"]
instead of $_FILES["article_photo"] because if i "comment out" the
$_FILES... line and insted use $_POST["article_photo"] I can find it..
But then the file field not work..

Karl

[Jerry Stuckle]

Karl wrote:

On 29 Des, 15:54, Jerry Stuckle <[e-mail]:

>Karl wrote:

>>Hello again.
I have a form for posting news articles.
Form one is the "register" form.
Then I go to the preview form were I can select edit or accept
If I select edit, I got the "edit form" and if I select accept, I
receive a message that say:
The news article "headline" are posted into the database.
When I use the file field and browse to "my photos", select an image
and post it. I can see it in the priview form/page and can also show
it in the article.
But if I select the "edit" button I can't see the image.
I am using <input type="hidden" name="article_photo"
value="$article_foto"field to preserve the value of the field:
<input type="file" name="article_photo">
Well. I discover that if I not have anything in the field <input
type="file" name="article_photo"...
but still have the image.jpg in the hidden field. It use the
$_POST["article_photo"] insted of
$_FILES["article_photo"];
So I was thinking that this below should do the trick:
if(!isset($_FILES["article_photo"])){
$article_photo = $_POST["article_photo"];
} else {
$article_photo = $_FILES["article_photo"];
}
But still the image are not avaible in the edit or preview pages in
the variable $article_photo
BUT if I use the file field and browse, select an image and post it.
Then it show up in those pages.
How can I fix this? Is it better to use setcookie("article_photo",
$_POST['article_photo'] time()+30);
Thanks for all advice. (and sorry my weak english)
Karl

Do you have the image file name in a <img...tag?

Yes, I have.

And it works if I use the <input type="file" name="article_photo">
field.
$article_photo = $_FILES["article_photo"]; make it work.
But when I have the image.jpg registred in a <input type="hidden"...
field, it does not work.

I think that this hidden field use the $_POST["article_photo"]
instead of $_FILES["article_photo"] because if i "comment out" the
$_FILES... line and insted use $_POST["article_photo"] I can find it..
But then the file field not work..

Karl

OK, did you write this yourself? Or is this someone else's script?

If the latter, that's who you should be asking.

And <input type="file"...and <input type="hidden"...have two
entirely different uses.

And sure - if you comment out the $_FILES line, there is no way for the
file field will work.

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attglobal.net
==================

[Karl]

On 29 Des, 19:51, Jerry Stuckle <[e-mail]:

>
OK, did you write this yourself? Or is this someone else's script?

No it's mine :)

>
If the latter, that's who you should be asking.

And <input type="file"...and <input type="hidden"...have two
entirely different uses.

Yes, I know.

And sure - if you comment out the $_FILES line, there is no way for the
file field will work.

Yes, of course. I do it just to try what would happen.

Anyway. If I select to post the image.jpg by the file field on the
"edit" page. It work.
I had hoped to find a way to "transfer" it through this different view
of forms without post it a second time.

Karl

[Jerry Stuckle]

Karl wrote:

On 29 Des, 19:51, Jerry Stuckle <[e-mail]:

>OK, did you write this yourself? Or is this someone else's script?

No it's mine :)

>If the latter, that's who you should be asking.

And <input type="file"...and <input type="hidden"...have two
entirely different uses.

Yes, I know.

>And sure - if you comment out the $_FILES line, there is no way for the
file field will work.

Yes, of course. I do it just to try what would happen.

Anyway. If I select to post the image.jpg by the file field on the
"edit" page. It work.
I had hoped to find a way to "transfer" it through this different view
of forms without post it a second time.

Karl

OK, this is a little more clear now.

The only way you can get data from one page to another is either via a
form field or the $_SESSION variable.

In a case like this, I'd just use the hidden field to pass the old name.
If the user uploads a new file, use it. Otherwise just use the old
file (the one passed in the hidden field).

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attglobal.net
==================