in_array() question

[paul brown]

hello,

I have this code sample:

class Sexboard extends Master
{
var $userid;
var $errormessage;
var $dc_metro = array(20, 46, 51);

....

function get_select_by_user_online_sql($stateid, $cityid)
{
...

if( in_array( $stateid, $this->$dc_metro ) )
{
...
}

}

}

My question is why do I get a warning message saying the wrong data type
for the second parameter?

Thanks,

Paul

[Garp]

"paul brown" <pa**@paulbrown.net> wrote in message
news:1n***************@newssvr21.news.prodigy.com. ..

hello, <snip> if( in_array( $stateid, $this->$dc_metro ) )

My question is why do I get a warning message saying the wrong data type
for the second parameter?

Lose the second dollar when using object's members (and read the docs for
why):
if( in_array( $stateid, $this->dc_metro ) )

HTH
Garp

[paul brown]

paul brown wrote:

hello,

I have this code sample:

class Sexboard extends Master
{
var $userid;
var $errormessage;
var $dc_metro = array(20, 46, 51);

...

function get_select_by_user_online_sql($stateid, $cityid)
{
...

if( in_array( $stateid, $this->$dc_metro ) )
{
...
}

}

}

My question is why do I get a warning message saying the wrong data type
for the second parameter?

Thanks,

Paul

OK, I figured it out on my own... That dollar_sign before the dc_metro
was not needed... hooray for documentation!

Paul

[paul brown]

Garp wrote:

"paul brown" <pa**@paulbrown.net> wrote in message
news:1n***************@newssvr21.news.prodigy.com. ..

hello,

<snip>

if( in_array( $stateid, $this->$dc_metro ) )

My question is why do I get a warning message saying the wrong data type
for the second parameter?

Lose the second dollar when using object's members (and read the docs for
why):
if( in_array( $stateid, $this->dc_metro ) )

HTH
Garp

Hi, and yes this would have helped, had I not found the answer in the docs.

Thanks, though, for your response,

Paul

[Garp]

"paul brown" <nn**@paulbrown.net> wrote in message
news:ON***************@newssvr21.news.prodigy.com. ..

Garp wrote:

"paul brown" <pa**@paulbrown.net> wrote in message
news:1n***************@newssvr21.news.prodigy.com. ..

hello,
<snip>

if( in_array( $stateid, $this->$dc_metro ) )

My question is why do I get a warning message saying the wrong data type
for the second parameter?

Lose the second dollar when using object's members (and read the docs for why):
if( in_array( $stateid, $this->dc_metro ) )

HTH
Garp

Hi, and yes this would have helped, had I not found the answer in the

docs.
Thanks, though, for your response,

Paul

I'm still claiming credit. 8P

Garp