variable

[Gandalf]

I don't understand why this expression doesn't work:

$var= '$_POST';

$name= ${$var}[name];
the ${$var}[name] expression wont return the same expression of
$_POST[name].
why does it happens, and how can i solve it?

thanks

[Gandalf]

On Sep 15, 10:32 am, Gandalf <[e-mail]:

I don't understand why this expression doesn't work:

$var= '$_POST';

$name= ${$var}[name];

the ${$var}[name] expression wont return the same expression of
$_POST[name].
why does it happens, and how can i solve it?

thanks

i meant to write $var ='_POST',
and the that ${$var}[name] wont return the same value as $_POST[name]

[gosha bine]

Gandalf wrote:

On Sep 15, 10:32 am, Gandalf <[e-mail]:

>I don't understand why this expression doesn't work:

$var= '$_POST';

$name= ${$var}[name];

the ${$var}[name] expression wont return the same expression of
$_POST[name].
why does it happens, and how can i solve it?

thanks

i meant to write $var ='_POST',
and the that ${$var}[name] wont return the same value as $_POST[name]

hi

this should work as expected. Care to post more code?

--
gosha bine

extended php parser ~ http://code.google.com/p/pihipi
blok ~ http://www.tagarga.com/blok

[Gandalf]

On Sep 15, 11:07 am, gosha bine <[e-mail]:

Gandalf wrote:

On Sep 15, 10:32 am, Gandalf <[e-mail]:

I don't understand why this expression doesn't work:

$var= '$_POST';

$name= ${$var}[name];

the ${$var}[name] expression wont return the same expression of
$_POST[name].
why does it happens, and how can i solve it?

thanks

i meant to write $var ='_POST',
and the that ${$var}[name] wont return the same value as $_POST[name]

hi

this should work as expected. Care to post more code?

--
gosha bine

extended php parser ~http://code.google.com/p/pihipi
blok ~http://www.tagarga.com/blok

$var gets the value '_POST'
function create_par($var){
global $_COOKIE, $_POST, $active;

if(${$var}[no_win_from]!=0 || ${$var}[no_win_to]!=${$var}[games])
$active[0]="no_win"; else die(${$var}[games]);
if(${$var}[out_win_from]!=0 || ${$var}[out_win_to]!=${$var}[games])
$active[1]="out_win";

if(${$var}[yedaActive_2]=="true"){
if(${$var}[range_yeda1_from]!=0 || ${$var}[range_yeda1_to]!=${$var}
[games])$active[2]="range_yeda1";
}
if(${$var}[yedaActive_3]=="true"){
if(${$var}[range_yeda2_from]!=0 || ${$var}[range_yeda2_to]!=${$var}
[games]) $active[3]="range_yeda2";
}
if(${$var}[home_win_from]!=0 || ${$var}[home_win_to]!=${$var}[games])
$active[4]="home_win";
}

[Michael Fesser]

..oO(Gandalf)

>$var gets the value '_POST'
function create_par($var){
global $_COOKIE, $_POST, $active;

$_COOKIE, $_POST etc. are always available, no need to use 'global' on
them. But:

| Please note that variable variables cannot be used with PHP's
| Superglobal arrays within functions or class methods.

Micha

[Sanders Kaufman]

Michael Fesser wrote:

| Please note that variable variables cannot be used with PHP's
| Superglobal arrays within functions or class methods.

I read that, and re-read it, and re-read it... and I can't figure out
what it means. Can you re-phrase it?

I was good right up to "within functions...". I use super globals
within functions all the time.

[Michael Fesser]

..oO(Sanders Kaufman)

>Michael Fesser wrote:

>| Please note that variable variables cannot be used with PHP's
| Superglobal arrays within functions or class methods.

I read that, and re-read it, and re-read it... and I can't figure out
what it means. Can you re-phrase it?

I was good right up to "within functions...". I use super globals
within functions all the time.

A variable variable is something like that:

$foo = 'bar';
$bar = 42;

print ${$foo}; // prints 42

This means the name of the variable is taken from another (string)
variable. The same can be done with superglobals, but not if you're
inside a function or method:

function test() {
$foo = '_GET';
var_dump(${$foo}); // throws a notice
}

Micha

[Sanders Kaufman]

Michael Fesser wrote:

A variable variable is something like that:

$foo = 'bar';
$bar = 42;

print ${$foo}; // prints 42

This means the name of the variable is taken from another (string)
variable. The same can be done with superglobals, but not if you're
inside a function or method:

function test() {
$foo = '_GET';
var_dump(${$foo}); // throws a notice
}

I think that what's confusing me is that double-dollar thing.
I've seen it before, but thought it was a typo.

Could you tell me what it means, or where to look in the docs to find
out about it.

[Michael Fesser]

..oO(Sanders Kaufman)

>I think that what's confusing me is that double-dollar thing.
I've seen it before, but thought it was a typo.

Could you tell me what it means, or where to look in the docs to find
out about it.

It's called a variable variable. As said - instead of accessing a
variable directly, it's done by taking the name of the variable from
_another_ string variable:

$foo = 42;
print $foo; // prints 42
$bar = 'foo';
print ${$bar}; // prints 42, too

The latter accesses a variable whose name is stored in another variable.

http://www.php.net/manual/en/languag...s.variable.php

Usuallly it's considered bad style to use variable variables, in most
cases there's a better way. But there's a similar thing that can be
really helpful - variable class names, i.e. the class name is stored in
a variable:

$foo = 'TMyClass';
$bar = new $foo(); // creates an instance of the class TMyClass

Micha

[Sanders Kaufman]

Michael Fesser wrote:

It's called a variable variable. As said - instead of accessing a
variable directly, it's done by taking the name of the variable from
_another_ string variable:

Oh, WOW!!! That is so cool.
I was kinda thinkin about doing something like that all hodge-podge with
"eval" statements, but figured it was too hair-brained.

Usuallly it's considered bad style to use variable variables, in most
cases there's a better way.

So... it is a little hair-brained, eh? :)
Still - I'll have some fun exploring that.

But there's a similar thing that can be
really helpful - variable class names, i.e. the class name is stored in
a variable:

$foo = 'TMyClass';
$bar = new $foo(); // creates an instance of the class TMyClass

Now I'm confused again.
Maybe I'm applying Java logic here or something.
Why doesn't that just create a new string containing, 'TMyClass'?

[Michael Fesser]

..oO(Sanders Kaufman)

>Michael Fesser wrote:

>But there's a similar thing that can be
really helpful - variable class names, i.e. the class name is stored in
a variable:

$foo = 'TMyClass';
$bar = new $foo(); // creates an instance of the class TMyClass

Now I'm confused again.
Maybe I'm applying Java logic here or something.
Why doesn't that just create a new string containing, 'TMyClass'?

Because PHP is not Java. ;)

In this case the name of the class is taken from the variable (notice
the parentheses after the variable name). The same can also be done with
functions, which is a common way to implement callback functions in PHP.

Micha

[Jerry Stuckle]

Sanders Kaufman wrote:

Michael Fesser wrote:

>A variable variable is something like that:

$foo = 'bar';
$bar = 42;

print ${$foo}; // prints 42

This means the name of the variable is taken from another (string)
variable. The same can be done with superglobals, but not if you're
inside a function or method:

function test() {
$foo = '_GET';
var_dump(${$foo}); // throws a notice
}

I think that what's confusing me is that double-dollar thing.
I've seen it before, but thought it was a typo.

Could you tell me what it means, or where to look in the docs to find
out about it.

Sanders,

Not unusual. It is confusing, and IMHO not a good programming
technique, IMHO.

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attglobal.net
==================

[Sanders Kaufman]

Jerry Stuckle wrote:

Sanders Kaufman wrote:

>I think that what's confusing me is that double-dollar thing.
I've seen it before, but thought it was a typo.

Could you tell me what it means, or where to look in the docs to find
out about it.

Not unusual. It is confusing, and IMHO not a good programming
technique, IMHO.

Yeah - after contemplating it, I think maybe it's an accident that the
PHP dev guys just decided to feature, rather than fix.