Weird parse error

[Alvaro G Vicario]

The following code produces a parse error:

$res=mysql_query($sql) or return('There was an error');

However, this works fine:

$res=mysql_query($sql) or die('There was an error');

I can't understand why. In case of SQL error I only want to stop executing
current function, not the whole script.
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-- Álvaro G. Vicario - Burgos, Spain
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[michel]

if(!$res=mysql_query($sql)) return("There was an error");

Denada,

Michel

"Alvaro G Vicario" <al******************@telecomputeronline.com> wrote in
message news:l6****************************@40tude.net...

The following code produces a parse error:

$res=mysql_query($sql) or return('There was an error');

However, this works fine:

$res=mysql_query($sql) or die('There was an error');

I can't understand why. In case of SQL error I only want to stop executing
current function, not the whole script.
--
--
-- Álvaro G. Vicario - Burgos, Spain
--

[Chung Leong]

"Alvaro G Vicario" <al******************@telecomputeronline.com> wrote in
message news:l6****************************@40tude.net...

The following code produces a parse error:

$res=mysql_query($sql) or return('There was an error');

However, this works fine:

$res=mysql_query($sql) or die('There was an error');

I can't understand why. In case of SQL error I only want to stop executing
current function, not the whole script.
--
--
-- Álvaro G. Vicario - Burgos, Spain
--

return is a operator, that's why. Same thing would happen if you do " ... or
echo $error."

[Alvaro G Vicario]

*** Chung Leong wrote/escribió (Tue, 15 Jun 2004 18:07:32 -0400):

return is a operator, that's why. Same thing would happen if you do " ... or
echo $error."

You are right: it happens with echo, exit... I didn't have the faintest
idea that you couldn't use them this way.
--
--
-- Álvaro G. Vicario - Burgos, Spain
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