$_GET variables into <a href> tags

[The1corrupted]

Alright, I know this is basic but I can't figure it out. Whenever I try to make a $_GET variable into a link like this:

<a href='php?command=quit'>
 

the browser reads it as a separate page. I'm stuck.

[ronverdonk]

Alright, I know this is basic but I can't figure it out. Whenever I try to make a $_GET variable into a link like this:

<a href='php?command=quit'>
 

the browser reads it as a separate page. I'm stuck.

Úsually the href <a> tag is used to pass control to the in 'href' specified script, along with the specified (GET) parameter, after that link has been clicked. So this statement
[html]<a href='myscript.php?command=quit'>Click me!</a>[/html]
displays the text 'Click me!' on the screen. When clicked control is passed to program myscript.php with the GET parameter command=quit.

Ronald :cool:

[The1corrupted]

Úsually the href <a> tag is used to pass control to the in 'href' specified script, along with the specified (GET) parameter, after that link has been clicked. So this statement
[html]<a href='myscript.php?command=quit'>Click me!</a>[/html]
displays the text 'Click me!' on the screen. When clicked control is passed to program myscript.php with the GET parameter command=quit.

Ronald :cool:

Aha! Now it works. Thanks!

[ronverdonk]

You are welcome.

Ronald :cool:

[Jekyl1]

Hi, This is along the same lines so I thought I'd post my question here.
Keep in mind, I have NO idea what I'm doing with PHP. I am taking over managing a website that was built by someone else.

So, on one page, index.php, there are small thumbnail images. These all have links like:

[PHP]href="viewpic.php?image=7[/PHP]

I understand that when clicked, this link will go to the page "viewpic.php" and try to display the image with the variable value of 7.

On the viewpic.php page, in the </head> section there is this code:

[PHP]<?php
$url = "http://www.mandykaplan.com/images/headshots/small/mandy0";
$file = ".jpg";
$loc = "$url$image$file";
?>[/PHP]

and then, down on the page, where the image should be displayed is this:

[PHP]<img src="<?PHP print($loc);?>" name="<?PHP print($query);?>" width="32" height="32"> [/PHP]

However, the viewpic.php page only shows a broken image placeholder. :-(
I guess my question is how do I assign variable values to things like image files?
And, shouldn't this code work properly?

Thank you!

[The1corrupted]

Hi, This is along the same lines so I thought I'd post my question here.
Keep in mind, I have NO idea what I'm doing with PHP. I am taking over managing a website that was built by someone else.

So, on one page, index.php, there are small thumbnail images. These all have links like:

[PHP]href="viewpic.php?image=7[/PHP]

I understand that when clicked, this link will go to the page "viewpic.php" and try to display the image with the variable value of 7.

On the viewpic.php page, in the </head> section there is this code:

[PHP]<?php
$url = "http://www.mandykaplan.com/images/headshots/small/mandy0";
$file = ".jpg";
$loc = "$url$image$file";
?>[/PHP]

and then, down on the page, where the image should be displayed is this:

[PHP]<img src="<?PHP print($loc);?>" name="<?PHP print($query);?>" width="32" height="32"> [/PHP]

However, the viewpic.php page only shows a broken image placeholder. :-(
I guess my question is how do I assign variable values to things like image files?
And, shouldn't this code work properly?

Thank you!

Actually, you should make it all one base page and not separate pages. Therefore, you run a little script that's a case statement like so

[php]
switch ("image") {
case 7:
echo "Do this";
break;
}
[/php]

Then all you have to do is make an onclick function in javascript to make image=7 then transfer it to php.

[Jekyl1]

While that sounds dandy, you need to talk to me like I'm a 3 year old.
Seriously.
Pretend I'm a little baby and walk me through it step by step. (If you have the time, of course.)

Things like, "make an onclick function in javascript... then transfer it to php," mean almost nothing to me.

Thank you very very very much for your time. I really appreciate it.