problem with time script

[_Skare_Krow_]

In my script main_date = 2007-01-24
and I'm getting this as my result for the due date 2007 04 06
what am I doing wrong here?

Aaron

<?
$maint_date = date(' Y m d', $maint_date);
if ($maint_interv = "monthly")
{
$interval = //mktime(0, 0, 0, date("m")+ 1, 1, date("Y"));
"1 week";
}
$interval = strtotime($interval);
$due_date = $maint_date + $interval;
echo date(' Y m d', $due_date);
echo "<br>$interval";
?>

[mds]

_Skare_Krow_ wrote:

$due_date = $maint_date + $interval;

this adds int to string.

[_Skare_Krow_]

mds wrote:

_Skare_Krow_ wrote:

>$due_date = $maint_date + $interval;

this adds int to string.

ok so how do I add something to a date?

[Hendri Kurniawan]

_Skare_Krow_ wrote:

In my script main_date = 2007-01-24
and I'm getting this as my result for the due date 2007 04 06
what am I doing wrong here?

Aaron

<?
$maint_date = date(' Y m d', $maint_date);
if ($maint_interv = "monthly")
{
$interval = //mktime(0, 0, 0, date("m")+ 1, 1, date("Y"));
"1 week";
}
$interval = strtotime($interval);
$due_date = $maint_date + $interval;
echo date(' Y m d', $due_date);
echo "<br>$interval";
?>

do not put this line on:
$maint_date = date(' Y m d', $maint_date);
instead if $maint_date is a string "2007-01-24", do this:
$maint_date = strtotime($maint_date);

remove the reference to interval.
How to calculate interval:
"monthly": interval is 60 sec * 60 minutes * 24 hours * 30 days
so that is: $interval = 60 * 60 * 24 * 30;
assuming 1 month is 30 days of course.

So $due_date is simply $maint_date + $interval

[Toby A Inkster]

_Skare_Krow_ wrote:

$interval = strtotime("1 week");

This doesn't do what you think it does. strtotime() doesn't output
intervals; it outputs timestamps; here is it returning the timestamp for
the date one week from today.

You need to calculate the interval by yourself:

$interval = 7 * 24 * 60 * 60; // seconds in one week

--
Toby A Inkster BSc (Hons) ARCS
Contact Me ~ http://tobyinkster.co.uk/contact
Geek of ~ HTML/SQL/Perl/PHP/Python*/Apache/Linux

* = I'm getting there!

[Kimmo Laine]

"_Skare_Krow_" <pe*******@gmail.comwrote in message
news:lY******************************@sysmatrix.ne t...

mds wrote:

>_Skare_Krow_ wrote:

>>$due_date = $maint_date + $interval;

this adds int to string.

ok so how do I add something to a date?

$original_date = '2007-03-07';
echo date('Y-m-d', strtotime('+1week', strtotime($original_date)));

OR

$original_date = '2007-03-07';
list($Y,$m,$d) = explode('-',$original_date);
echo date('Y-m-d', mktime(12,0,0,$m,$d+7,$Y));

--
"Ohjelmoija on organismi joka muuttaa kofeiinia koodiksi" - lpk
http://outolempi.net/ahdistus/ - Satunnaisesti päivittyvä nettisarjis
sp**@outolempi.net | rot13(xv***@bhgbyrzcv.arg)

[_Skare_Krow_]

Hendri Kurniawan wrote:

_Skare_Krow_ wrote:

>In my script main_date = 2007-01-24
and I'm getting this as my result for the due date 2007 04 06
what am I doing wrong here?

Aaron

<?
$maint_date = date(' Y m d', $maint_date);
if ($maint_interv = "monthly")
{
$interval = //mktime(0, 0, 0, date("m")+ 1, 1, date("Y"));
"1 week";
}
$interval = strtotime($interval);
$due_date = $maint_date + $interval;
echo date(' Y m d', $due_date);
echo "<br>$interval";
?>

do not put this line on:
$maint_date = date(' Y m d', $maint_date);
instead if $maint_date is a string "2007-01-24", do this:
$maint_date = strtotime($maint_date);

remove the reference to interval.
How to calculate interval:
"monthly": interval is 60 sec * 60 minutes * 24 hours * 30 days
so that is: $interval = 60 * 60 * 24 * 30;
assuming 1 month is 30 days of course.

So $due_date is simply $maint_date + $interval

Many thanks I can now nest the "intervals" and go on... strtotime just
isn't working quite the way I thought it would.

Aaron