OK.
I have a mysql database and i have it displaying whats currently there
using php, the problem is that I cannot insert into the database
correctly. please check my code below
<?php
$username = "root";
$password = "************"; //edited
$server = "localhost";
$dbname = "dbname";
$title = $_POST["title"];
$news = $_POST["news"];
$id = $_POST["id"];
$date = "2006-15-11 00:15:15";
$dbc = mysql_connect($server, $username, $password) or die ("ERROR");
$select = mysql_select_db($dbname, $dbc) or die("couldn't connect to
dbname");
$sqlquery = "INSERT INTO tnews VALUES('$id','$title','$news','$date')";
//print "<html><body><center>";
//print "<p>You have just entered this record<p>";
//print "Title : $title<br><hr>";
//print "$news<br>$date";
//print "</body></html>";
print $sqlquery;
$results = mysql_query($sqlquery);
mysql_close($dbc);
?>
this submits the info from a form, the code for the form is below:
<form method="post" action="add.php">
Title: <input name="title" type="text" value="">
<input type="hidden" name="id" />
<br>
News: <input name="news" type="text" value="">
<br>
<br>
<input type="submit" name="submit" value="Submit">
</form>
I can see the insert query fine and it appears to be working however
the data isnt being put in the database. I am hosting php on my home
computer and it is being used with apache I am also hosting mysql on my
own computer and am using SQLyog and the GUI toold from mysql to
administer the db, I am a novice so please go easy but can anyone see a
reason why i cant get this data to appear in my database table?
Please please help me!! 7  1732 
Christo wrote:
$sqlquery = "INSERT INTO tnews VALUES('$id','$title','$news','$date')";
//print "<html><body><center>";
//print "<p>You have just entered this record<p>";
//print "Title : $title<br><hr>";
//print "$news<br>$date";
//print "</body></html>";
print $sqlquery;
$results = mysql_query($sqlquery);
mysql_close($dbc);
?>
Christo,
You should always check the value returned by mysql_query() to ensure
that it did what you think it did. If you find (from the return value)
that there was a problem, a call to mysql_error() should give you the
details.
See the examples here: http://php.net/mysql_query
Also, You should never allow user input ($_POST in your case) to get
sent directly to the database server. See http://www.php.net/mysql_real_escape_string for more info on why and
how to minimize potential problems.
Hope that helps,
Carl.
I discovered that if i enter the id manually then it works, I do have
this field setup as auto inc and as PK and as not null, shouldn't this
field automatically assign its self a value of the next auto inc number
without mee having to input the id raw in the php code?
I would appreciate some help here as this has been an aim of mine for
some time to get mysql qworking and I am so so close.
TIA
Chris
PS - sorry if it appears as top posting, they look nicer on google
groups that way
thanks again
Chris
Christo wrote:
OK.
I have a mysql database and i have it displaying whats currently there
using php, the problem is that I cannot insert into the database
correctly. please check my code below
<?php
$username = "root";
$password = "************"; //edited
$server = "localhost";
$dbname = "dbname";
$title = $_POST["title"];
$news = $_POST["news"];
$id = $_POST["id"];
$date = "2006-15-11 00:15:15";
$dbc = mysql_connect($server, $username, $password) or die ("ERROR");
$select = mysql_select_db($dbname, $dbc) or die("couldn't connect to
dbname");
$sqlquery = "INSERT INTO tnews VALUES('$id','$title','$news','$date')";
//print "<html><body><center>";
//print "<p>You have just entered this record<p>";
//print "Title : $title<br><hr>";
//print "$news<br>$date";
//print "</body></html>";
print $sqlquery;
$results = mysql_query($sqlquery);
mysql_close($dbc);
?>
this submits the info from a form, the code for the form is below:
<form method="post" action="add.php">
Title: <input name="title" type="text" value="">
<input type="hidden" name="id" />
<br>
News: <input name="news" type="text" value="">
<br>
<br>
<input type="submit" name="submit" value="Submit">
</form>
I can see the insert query fine and it appears to be working however
the data isnt being put in the database. I am hosting php on my home
computer and it is being used with apache I am also hosting mysql on my
own computer and am using SQLyog and the GUI toold from mysql to
administer the db, I am a novice so please go easy but can anyone see a
reason why i cant get this data to appear in my database table?
Please please help me!!
I thought that
print $sqlquery was the same thing, I can see the query string in one
case it looks like this
INSERT INTO tnews (id, Title, Body, Date) VALUES
('null','12345678ppp','ppp87654321','Wed, 15 Nov 2006 01:20:01 +0000')
the reason its longer is a friend suggested i try doing the query like
that
one thing is though if i do this
INSERT INTO tnews (id, Title, Body, Date) VALUES
('45','12345678ppp','ppp87654321','Wed, 15 Nov 2006 01:20:01 +0000')
and assign 45 where previously the id was blank or null ( i tried both
blank and null)
the above works and the code is almost identical the only difference is
that 45, so anyone got any ideas, my table id field is set as primary
key and auto increment and not null, so why isnt it auto incrementing?
TIA
Chris
Carl wrote:
Christo wrote:
$sqlquery = "INSERT INTO tnews VALUES('$id','$title','$news','$date')";
//print "<html><body><center>";
//print "<p>You have just entered this record<p>";
//print "Title : $title<br><hr>";
//print "$news<br>$date";
//print "</body></html>";
print $sqlquery;
$results = mysql_query($sqlquery);
mysql_close($dbc);
?>
Christo,
You should always check the value returned by mysql_query() to ensure
that it did what you think it did. If you find (from the return value)
that there was a problem, a call to mysql_error() should give you the
details.
See the examples here: http://php.net/mysql_query
Also, You should never allow user input ($_POST in your case) to get
sent directly to the database server. See
http://www.php.net/mysql_real_escape_string for more info on why and
how to minimize potential problems.
Hope that helps,
Carl.
cm*****@googlemail.com says...
I thought that
print $sqlquery was the same thing, I can see the query string in one
case it looks like this
INSERT INTO tnews (id, Title, Body, Date) VALUES
('null','12345678ppp','ppp87654321','Wed, 15 Nov 2006 01:20:01 +0000')
the reason its longer is a friend suggested i try doing the query like
that
one thing is though if i do this
INSERT INTO tnews (id, Title, Body, Date) VALUES
('45','12345678ppp','ppp87654321','Wed, 15 Nov 2006 01:20:01 +0000')
and assign 45 where previously the id was blank or null ( i tried both
blank and null)
the above works and the code is almost identical the only difference is
that 45, so anyone got any ideas, my table id field is set as primary
key and auto increment and not null, so why isnt it auto incrementing?
Just leave the id column out of the insert altogether, as it is
autoincrement it doesn't need to be (and shouldn't be) included in the
statement.
Geoff M
Christo wrote:
I discovered that if i enter the id manually then it works, I do have
this field setup as auto inc and as PK and as not null, shouldn't this
field automatically assign its self a value of the next auto inc number
without mee having to input the id raw in the php code?
I would appreciate some help here as this has been an aim of mine for
some time to get mysql qworking and I am so so close.
TIA
Chris
PS - sorry if it appears as top posting, they look nicer on google
groups that way
thanks again
Chris
Christo wrote:
>>OK.
I have a mysql database and i have it displaying whats currently there
using php, the problem is that I cannot insert into the database
correctly. please check my code below
<?php
$username = "root";
$password = "************"; //edited
$server = "localhost";
$dbname = "dbname";
$title = $_POST["title"];
$news = $_POST["news"];
$id = $_POST["id"];
$date = "2006-15-11 00:15:15";
$dbc = mysql_connect($server, $username, $password) or die ("ERROR");
$select = mysql_select_db($dbname, $dbc) or die("couldn't connect to
dbname");
$sqlquery = "INSERT INTO tnews VALUES('$id','$title','$news','$date')";
//print "<html><body><center>";
//print "<p>You have just entered this record<p>";
//print "Title : $title<br><hr>";
//print "$news<br>$date";
//print "</body></html>";
print $sqlquery;
$results = mysql_query($sqlquery);
mysql_close($dbc);
?>
this submits the info from a form, the code for the form is below:
<form method="post" action="add.php">
Title: <input name="title" type="text" value="">
<input type="hidden" name="id" />
<br>
News: <input name="news" type="text" value="">
<br>
<br>
<input type="submit" name="submit" value="Submit">
</form>
I can see the insert query fine and it appears to be working however
the data isnt being put in the database. I am hosting php on my home
computer and it is being used with apache I am also hosting mysql on my
own computer and am using SQLyog and the GUI toold from mysql to
administer the db, I am a novice so please go easy but can anyone see a
reason why i cant get this data to appear in my database table?
Please please help me!!
As Carl said. Check the result of mysql_query() and, if it is false,
call mysql_error(). This will tell you what your problem is.
--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp. js*******@attglobal.net
==================
Auto increment values don'd need to be declared in your insert
statement so take it out.
Obiron
Thanks its working now that i removed the id
:)
frothpoker wrote:
Auto increment values don'd need to be declared in your insert
statement so take it out.
Obiron
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