{SOLVED} newbie - some values not passing, some are ?syntax

[cassbiz]

I have been wondering if someone can see where my error is. I have been reading a lot of different tutorials and just cannot find my error.

? Should I be using 'isset'

I can get all of the information to display but am not able to pass all of the information on to the next page just some of it. I am confused.

<?
        include $include_path."cust_kopf.php";
        include $include_path."links.php";
        $andatum2 = $HTTP_GET_VARS['andatum'];
        $abdatum = $HTTP_GET_VARS['abdatum'];
        $zimmer = $HTTP_GET_VARS['zimmer'];
        $andatum2 = $andatum;
        $andatum=$_POST['andatum'];
        $abdatum=$_POST['abdatum'];
        $zimmer=$_POST['zimmer'];
?>
<? include("$_SERVER[DOCUMENT_ROOT]/css/menu.inc"); ?>
<form action="<?php echo $PHP_SELF ?>" method="post">
<label>Please type in your billing Zip Code:<br />
<input type="text" name="zip" />
<?php
while (list($name, $value) = each($HTTP_GET_VARS))
  {
   echo "<input type=\"hidden\" value=\"$value\" name=\"$name\">\n";
  }
?>
</label><br />
<input type="submit" value="Get City and State" />
</form>
<?
 $zip = $_POST['zip'];
     $city=$_POST['city'];
        $plz=$_POST['zip'];
        $stadt=$_POST['state'];
$sql = ("SELECT zip, city, state FROM zip WHERE zip='$zip'");
 echo '<p>Zip Code:</p>';
 // Request Zip Code Information
 $result = @mysql_query($sql);
 if (!$result) {
   echo('<p>Error performing query: ' .   mysql_error() . '</p>');
   echo $sql;
   exit();
 }
 // Display the text of zip in a paragraph
 while ($row = mysql_fetch_array($result)) {
 if ($zip == 0) {
 echo "<p> Please enter your Zip Code in the above box or press the continue button to manually enter your information</p>";
        }
else {
 echo "<p> Your billing Zip Code is <b>{$row['zip']}</b> which is located in <b>{$row['city']},   {$row['state']}</b>.  Please press the continue button to enter your information.</p>";
 }
 }
 $row['zip'] = $plz;
 $stadt=$row['state'];
 $city=$row['city'];
  echo '<a href="cust_card.php?andatum='.$andatum.'&abdatum='.$abdatum.'&plz='.$plz.'&city='.$city.'&stadt='.$stadt.'&zimmer='.$zimmer.'&eingabe=1'.'">Continue to enter address</a>';
?>
 
 

The last line contains all of the information except for $stadt & $city.

Thanks in advance.

[ronverdonk]

It would help if you tell us what the error is you run into. Now we have to guess!

(by the way: don't use HTTP_GET_VARS because it is deprecated and is gone in PHP6, use $_GET instead.)

Ronald :cool:

[cassbiz]

On the last link to cust_card.php (end of code), all of the values are retrieved and put into the string except for stadt and city. Though they show up initially when you run the first part of the script.

It would help if you tell us what the error is you run into. Now we have to guess!

(by the way: don't use HTTP_GET_VARS because it is deprecated and is gone in PHP6, use $_GET instead.)

Ronald :cool:

[cassbiz]

On the last link to cust_card.php (end of code), all of the values are retrieved and put into the string except for stadt and city. Though they show up initially when you run the first part of the script.

Below is an example of the output.

./cust_card.php?andatum=1162573200&abdatum=1162616400&plz=97526&city=&stadt=&zimmer=Space%202&eingabe=1
 

[cassbiz]

I cleaned up the code to get rid of the "$HTTP_GET_VARS"

The output string is on line 54 and it is not retrieving all of the values. The only ttwo that are not showing is 'city' and 'stadt'.

<?
        include $include_path."cust_kopf.php";
        include $include_path."links.php";
        $andatum2 = $_GET['andatum'];
        $abdatum = $_GET['abdatum'];
        $zimmer = $_GET['zimmer'];
        $andatum2 = $andatum;
        $andatum=$_POST['andatum'];
        $abdatum=$_POST['abdatum'];
        $zimmer=$_POST['zimmer'];
?>
<form action="<?php echo $PHP_SELF ?>" method="post">
<label>Please type in your billing Zip Code:<br />
<input type="text" name="zip" />
<?php
while (list($name, $value) = each($_GET))
  {
   echo "<input type=\"hidden\" value=\"$value\" name=\"$name\">\n";
  }
?>
</label><br />
<input type="submit" value="Get City and State" />
</form>
<?
 $zip = $_POST['zip'];
        $city=$_POST['city'];
        $plz=$_POST['zip'];
        $stadt=$_POST['state'];
$sql = ("SELECT zip, city, state FROM zip WHERE zip='$zip'");
 echo '<p>Zip Code:</p>';
 // Request Zip Code Information
 $result = @mysql_query($sql);
 if (!$result) {
//   exit('<p>Error performing query: ' .   mysql_error() . '</p>');
   echo('<p>Error performing query: ' .   mysql_error() . '</p>');
   echo $sql;
   exit();
 }
 // Display the text of zip in a paragraph
 while ($row = mysql_fetch_array($result)) {
 if ($zip == 0) {
 echo "<p> Please enter your Zip Code in the above box or press the continue button to manually enter your information</p>";
        }
else {
 echo "<p> Your billing Zip Code is <b>{$row['zip']}</b> which is located in <b>{$row['city']},   {$row['state']}</b>.  Please press the continue button to enter your information.</p>";
 }
 }
 $row['zip'] = $plz;
// $row['city'] = $city;
// $row['state'] = $stadt;
 $stadt=$row['state'];
 $city=$row['city'];
 
  echo '<a href="cust_card.php?andatum='.$andatum.'&abdatum='.$abdatum.'&plz='.$plz.'&city='.$city.'&stadt='.$stadt.'&zimmer='.$zimmer.'&eingabe=1'.'">Continue to enter address</a>';
?>
 
 

[ronverdonk]

When you have a url string and you don't know if there are any funny characters or blanks in it, you better use the url encode function, so:

$url = "?andatum=$andatum&abdatum=$abdatum&plz=$plz&city=$city&stadt=$stadt&zimmer=$zimmer&eingabe=1";
$url = urlencode($url);
echo "<a href='cust_card.php$url'>Continue to enter address</a>";

Ronald :cool:

[cassbiz]

I put that the urlencode in and the output is now

cust_kartei.php%3Fandatum%3D1162573200%26abdatum%3D1162616400%26plz%3D97526%26city%3D%26stadt%3D%26zimmer%3DSpace+2%26eingabe%3D1

no longer using the "&"

Still back to the same problem. In that final string, the city and stadt variables are not carrying over.

When you have a url string and you don't know if there are any funny characters or blanks in it, you better use the url encode function, so:

$url = "?andatum=$andatum&abdatum=$abdatum&plz=$plz&city=$city&stadt=$stadt&zimmer=$zimmer&eingabe=1";
$url = urlencode($url);
echo "<a href='cust_card.php$url'>Continue to enter address</a>";

Ronald :cool:

[cassbiz]

The fix for the error that I had was to enter in the $stadt and $city right below the 'echo' for the output.

 echo "<p> Your billing Zip Code is <b>{$row['zip']}</b> which is located in <b>{$row['city']},   {$row['state']}</b>.  Please press the continue button to enter your information.</p>";
 $stadt=$row['state'];
 $city=$row['city'];
 

Again, I want to thank everyone who helped.