I have seen much, but this...

[jodleren]

I have 2 pieces of code, where one works, another does not, even they
should be the same

echo " <td$s $s2</td><td>$s-";
echo $s+$s2." </td></tr>\r\n";

which can be truncated to

echo " <td$s $s2</td><td>$s-".$s+$s2." </td></tr>\r\n";

All in one line, but then the first part in the "" will not be printed,
result: 45</td></tr- a funny table.
There should be no difference, but there is.

$s and $s2 are integer, the entire table is for debugging. The error is
known and I can work around this.

But i cannot explain it.

BR
Sonnich

[Moot]

jodleren wrote:

I have 2 pieces of code, where one works, another does not, even they
should be the same

echo " <td$s $s2</td><td>$s-";
echo $s+$s2." </td></tr>\r\n";

which can be truncated to

echo " <td$s $s2</td><td>$s-".$s+$s2." </td></tr>\r\n";

All in one line, but then the first part in the "" will not be printed,
result: 45</td></tr- a funny table.
There should be no difference, but there is.

$s and $s2 are integer, the entire table is for debugging. The error is
known and I can work around this.

But i cannot explain it.

BR
Sonnich

When doing math within a string concatenation, you need to use
parethesis.
So your second example becomes:
echo " <td$s $s2</td><td>$s-". ($s+$s2) ." </td></tr>\r\n";

[p.lepin]

jodleren wrote:

echo " <td$s $s2</td><td>$s-";
echo $s+$s2." </td></tr>\r\n";

which can be truncated to

echo " <td$s $s2</td><td>$s-".$s+$s2." </td></tr>\r\n";

Precedence. Try:

echo " <td$s $s2</td><td>$s-".($s+$s2)." </td></tr>\r\n";

There should be no difference, but there is.

Of course there *is* quite a difference. You just failed to
notice it.

--
Pavel Lepin