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php and mysql

sanjay123456
125 100+
sir

its give affected row zero tell me where is error in following code ?

<?php
$con = mysql_connect("localhost","root","123456");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("my_db", $con);

$username = “comp”;
$passwd = “comp”;



$sql = "SELECT * FROM per
WHERE user_id = '".$username."' AND password = '".$passwd."'";

$r=mysql_query($sql);


if (!r)
{
die('Error: ' . mysql_error());
exit();
}

echo mysql_num_rows($r);

$rs=mysql_num_rows($r);
if($rs==0)
{
print "wrong";
exit();
}
else{
print "right";
//proceed to perform website’s functionality – e.g. present information to the user
}

mysql_close($con)

?>


it will affected row 0 and wrong

sanjay
Oct 11 '06 #1
2 1129
sanjay123456
125 100+
hi friend ,


$sql = "SELECT * FROM per
WHERE user_id = '".$username."' AND password = '".$passwd."'";


if replace its by following


$sql = "SELECT * FROM per
WHERE user_id = 'comp' AND password = 'comp' ";



its gives right


sanjay
Oct 11 '06 #2
ronverdonk
4,258 Expert 4TB
Read the Posting Guidelines at the top of this forum about showing code in your thread.

You are using back-ticks when assigning values to userid and password"
[php]$username = “comp”;
$passwd = “comp”;[/php]
You must use quotation marks.

Ronald :cool:
Oct 11 '06 #3

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