SWFShape::drawArc confusion

[CptDondo]

Can anyone tell me what 'degrees' this method uses?

The docs say

void SWFShape::drawArc(float $r, float $startAngle, float $endAngle)

I am trying to draw an arc at a radius of 1100, and 0.0 to 90.0 gives me
a tiny dot. To get an arc that is 1/4 of a circle (90 degrees) I have
to tell it something like 1100, 0, 5000 - i.e. there are 20,000
'degrees' around the circle....

I can't come up with some reasonable combination of numbers that would
make that work out....

--Yan

[Jeremy]

CptDondo wrote:

Can anyone tell me what 'degrees' this method uses?

The docs say

void SWFShape::drawArc(float $r, float $startAngle, float $endAngle)

I am trying to draw an arc at a radius of 1100, and 0.0 to 90.0 gives me
a tiny dot. To get an arc that is 1/4 of a circle (90 degrees) I have
to tell it something like 1100, 0, 5000 - i.e. there are 20,000
'degrees' around the circle....

I can't come up with some reasonable combination of numbers that would
make that work out....

--Yan

If the parameter were specified in minutes (1/60th of a degree) then it
would make sense - there are 21,600 minutes in a full circle. Try
converting your angle to minutes (*= 60) and see if that makes things
work out a little better.

Disclaimer: I know nothing about SWFShape. Never used it or heard about
it before.

Jeremy

[CptDondo]

Jeremy wrote:

CptDondo wrote:

>Can anyone tell me what 'degrees' this method uses?

The docs say

void SWFShape::drawArc(float $r, float $startAngle, float $endAngle)

I am trying to draw an arc at a radius of 1100, and 0.0 to 90.0 gives
me a tiny dot. To get an arc that is 1/4 of a circle (90 degrees) I
have to tell it something like 1100, 0, 5000 - i.e. there are 20,000
'degrees' around the circle....

I can't come up with some reasonable combination of numbers that would
make that work out....

--Yan

If the parameter were specified in minutes (1/60th of a degree) then it
would make sense - there are 21,600 minutes in a full circle. Try
converting your angle to minutes (*= 60) and see if that makes things
work out a little better.

I bet you're right... I kept trying to play around with radians, but I
like your theory much better....

--Yan