Nested loops help please?

[tzuriel]

Hello all,

I think nested loops will do what I want, but I can't seem to get them
right.

I have two tables, members and casts. I run a query as follows:

$sql_query="SELECT DISTINCT casts.yearID, members.memberName"
. " FROM members INNER JOIN casts ON members.memberID =
casts.memberID"
. " WHERE (((casts.yearID) In (SELECT DISTINCT yearID FROM
casts WHERE memberID='$id')) AND ((casts.memberID)<>'$id'));";
Which gets me the data I want to display using the following php:

$result=mysql_query($sql_query);

$num=mysql_numrows($result);

echo "Cast data for: <b>$castmember</b>"; ID:$id<br>";
$year =mysql_result($result,$i,"yearID");

echo " 1st season: <b>$year</b><p>";

//set up table for $result
print "<table width=200 border=0>\n";
print "\t<td><font face=arial size=1/><b>Cast Member</font></td>\n";
print "\t<td><font face=arial size=1/><b>Season</font></b></td>\n";

//loop through $result
$i=0;
while ($i < $num) {

$member=mysql_result($result,$i,"memberName");
$year =mysql_result($result,$i,"yearID");
print "<tr>\n";
print "\t<td><font face=arial size=1/>$member</font></td>\n";
print "\t<td><font face=arial size=1/>$year</font></td>\n";
print "</tr>\n";
$i++;

}
print "</table>\n";
?>
<?php echo "Cast data for: <b>",$castmember; ?><br></b>

However, the data is just one long list in the table with the two
columns Cast Member and Season. What I want to do is have a separate
table for each Season so that when yearID changes from, for example,
1980 to 1981, the rows that show the cast members for 1980 are in one
table and those members from 1981 are in another.

Can this be done with nested loops? Do I need another query? Please
help if you can. I've struggled with this for a couple days and being
very new, have run out of stuff to try!

Thanks!

Tzuriel

[frothpoker]

two queries would be easier but obviously has a bigger overhead.

You could do the following:

Set $CurrentYear as the yearID from the first row

on each time through the loop, check YearID against $CurrentYear and if
it is not the same then end the table and start a new one before
setting $CurrentYear to the yearID of the current row.

tzuriel wrote:

Hello all,

I think nested loops will do what I want, but I can't seem to get them
right.

I have two tables, members and casts. I run a query as follows:

$sql_query="SELECT DISTINCT casts.yearID, members.memberName"
. " FROM members INNER JOIN casts ON members.memberID =
casts.memberID"
. " WHERE (((casts.yearID) In (SELECT DISTINCT yearID FROM
casts WHERE memberID='$id')) AND ((casts.memberID)<>'$id'));";
Which gets me the data I want to display using the following php:

$result=mysql_query($sql_query);

$num=mysql_numrows($result);

echo "Cast data for: <b>$castmember</b>"; ID:$id<br>";
$year =mysql_result($result,$i,"yearID");

echo " 1st season: <b>$year</b><p>";

//set up table for $result
print "<table width=200 border=0>\n";
print "\t<td><font face=arial size=1/><b>Cast Member</font></td>\n";
print "\t<td><font face=arial size=1/><b>Season</font></b></td>\n";

//loop through $result
$i=0;
while ($i < $num) {

$member=mysql_result($result,$i,"memberName");
$year =mysql_result($result,$i,"yearID");
print "<tr>\n";
print "\t<td><font face=arial size=1/>$member</font></td>\n";
print "\t<td><font face=arial size=1/>$year</font></td>\n";
print "</tr>\n";
$i++;

}
print "</table>\n";
?>
<?php echo "Cast data for: <b>",$castmember; ?><br></b>

However, the data is just one long list in the table with the two
columns Cast Member and Season. What I want to do is have a separate
table for each Season so that when yearID changes from, for example,
1980 to 1981, the rows that show the cast members for 1980 are in one
table and those members from 1981 are in another.

Can this be done with nested loops? Do I need another query? Please
help if you can. I've struggled with this for a couple days and being
very new, have run out of stuff to try!

Thanks!

Tzuriel

[tzuriel]

Thanks for the suggestion. Would you be able to offer some code for
consideration? I tried something like this at one point but couldn't
get it to work.

Thanks,

Tzuriel
frothpoker wrote:

two queries would be easier but obviously has a bigger overhead.

You could do the following:

Set $CurrentYear as the yearID from the first row

on each time through the loop, check YearID against $CurrentYear and if
it is not the same then end the table and start a new one before
setting $CurrentYear to the yearID of the current row.

[frothpoker]

// your query
$sql_query="SELECT DISTINCT casts.yearID, members.memberName"
. " FROM members INNER JOIN casts ON members.memberID =
casts.memberID"
. " WHERE (((casts.yearID) In (SELECT DISTINCT yearID FROM
casts WHERE memberID='$id')) AND ((casts.memberID)<>'$id'));";

$CurrentYear = 0;

while($result=mysql_query($sql_query); )
{
if ($CurrentYear == $result[1])
{
$string = $string .
"</TABLE><P><TABLE><TR><TD>$result[1]</TD></TR>";
$CurrentYear = $result[1]; // sets $CurrentYear to the same as
this record
} //end if statement
$string = $string . "<TR><TD>$result[2]</TD></TR>";
} // end while statement

print $string
-- code ends --

Obviously you will need to output table headers before the first record
and put some checking in so that you don't close the table if this is
the first record in the loop, but if i did it all for you....

Please note that I have not checked this for spelling or syntax (i am
notorious for leaving semi-colons off...)

Obiron

tzuriel wrote:

Thanks for the suggestion. Would you be able to offer some code for
consideration? I tried something like this at one point but couldn't
get it to work.

Thanks,

Tzuriel
frothpoker wrote:

two queries would be easier but obviously has a bigger overhead.

You could do the following:

Set $CurrentYear as the yearID from the first row

on each time through the loop, check YearID against $CurrentYear and if
it is not the same then end the table and start a new one before
setting $CurrentYear to the yearID of the current row.