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Converting argv to variable

I've taken a year off (or so) using Python and the first thing I run
into utterly stumped me. Been too long and none of the searches I've
done seems to have helped any.

Basically, I'm trying to create a little script which will make a new
directory, using the argument passed to it to give the directory a
name:

#!/usr/bin/python

import sys, os

newDirectory = str(sys.argv[1:])

currentPath = str(os.getcwd())

create = currentPath + '/' + newDirectory

print create

# os.mkdir(create)

Now, in a perfect universe I would get an output something like the
following (if I run the script with the argument 'python':

/Volumes/Home/myuser/python

However, Python still hangs on to all the fluff and prints out
something else:

/Volumes/Home/myuser/['python']

I know there must be some way to convert the argument to a 'normal'
variable, but it escapes me how to do so. Any pointers?

Thanks!

tom

Jul 22 '06 #1
2 1455
tgiles wrote:
I know there must be some way to convert the argument to a 'normal'
variable, but it escapes me how to do so. Any pointers?
Perhaps try a python newsgroup? PHP != Python...
JW
Jul 22 '06 #2
Janwillem Borleffs wrote:
tgiles wrote:
I know there must be some way to convert the argument to a 'normal'
variable, but it escapes me how to do so. Any pointers?

Perhaps try a python newsgroup? PHP != Python...
JW
This is the wrong newsgroup. My apologies.

Cheers,

tom

Jul 22 '06 #3

This thread has been closed and replies have been disabled. Please start a new discussion.

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