PHP select form

[dujmovicv]

I'm new in PHP programming, I suppose that my problem will be a child's-play for experts....
I need to write a PHP script with a "select" input form, which will offer 4 languages to chose between. When the user clicks on an item in the select list, the menu (buttons), some pictures shall change on the page regarding to the choice.
Please if exists, send me an example or good links for building web pages in PHP.
Thank You!

[iam_clint]

<?
$language = $_GET["language"];
?>
if ($language = 1) {
?>
this picture changes cause language is set to English
<?
}
if ($language = 2) {
?>
this picture is something cause the language is set to chinese
<?
}
?>
<select onchange="window.location='whatever.php?language='+this.value">
<option value="1">English</option>
<option value="2">Chinese</option>
</select>
 

small sample of how this would be done whatever.php = the page your on.

[dujmovicv]

Thank you for your quick help!

There are some errors in your script, I managed to correct some things, but it still doesn't work...

<?
$language = $_GET["language"];

if ($language == 1) {
?>
English
<?
}
if ($language == 2) {
?>
Chinese
<?
}
?>
<select onchange="window.location='select.php?language='+t his.value">
<option value="1">English</option>
<option value="2">Chinese</option>
</select>

The script prints "Chinese" when you select "Chinese", but in the select field is still "English", and when click on "English", nothing happens....

[iam_clint]

you need a better javascript then what i gave you it was an example

<select onchange="window.location='select.php?language='+this.value">
<option value="0">- Select Language -</option>
<option value="1" <?if ($language == 1) {?>selected<?}?>>English</option>
<option value="2" <?if ($language == 2) {?>selected<?}?>>Chinese</option>
</select>
 

i am trying to refrain from giving you code without trial and error you will never know exactly what you did wrong.. anymore that needs to be done to this script you can code and i can check your code.

[dujmovicv]

Hello iam_clint!

I'm back again with my probleme....

So, as I mentioned I've tried to combine php and java to build a dynamic menu with select form. Here is my code (example), I wonder if I'm going on the right way....
Please help if U have some good ideas... ;-)

<script language="JavaScript">

function jumpmenu(selLang)
{
var s = selLang;
echo "<img src=$s.gif>";
}

</script>

<?
print <<<HERE
<select name="select" onchange="jumpmenu(this)">
<option value="1" selected>Srpski</option>
<option value="2">Magyar</option>
<option value="3">English</option>
<option value="4">Deutsch</option>
</select>
HERE;
?>

As you can suppose it doesn't works...

[dujmovicv]

I managed to echo a select drop-down menu with 4 languages with an array:

[php]
<?php
$language = $_GET["language"];
?>
<select onchange="window.location='select.php?language='+t his.value">
<?php
$language = array(
"",
"English",
"Deutsch",
"Magyar",
"Srpski");
for ($i = 1; $i <= 4; $i++)
{
print "<option value=$i>$language[$i]</option>";
print "<h3>Language is : $language[$i]</h3>";
}
?>
</select>
[/php]

I can't see my mistake : in the select field always stays "English" and don't change to the selecteg language... The other question: the script doesn't prints the text in <h3> tag. Why is that?

[iam_clint]

<?php
$lang = $_GET["language"];
?>
<select onchange="window.location='select.php?language='+this.value">
<?php
$language = array(
    "-- Make A Selection --",
    "English",
    "Deutsch",
    "Magyar",
    "Srpski");
for ($i = 1; $i <= 4; $i++)
{
?>
<option value="<?=$i?>" <?if ($lang==$language[$i]) { print "selected"; }><?=$language[$i]?></option>
<?
}
?>
</select>
<h3>Language is : <?=$lang?></h3>
 

This should fix your problems, hope this is helping you learn :).
You can see the changes i made. It didn't print in h3 tags because you were still in the select tag.

[iam_clint]

<?php
$lang = $_GET["language"];
?>
<select onchange="window.location='select.php?language='+this.value">
<?php
$language = array(
    "-- Make A Selection --",
    "English",
    "Deutsch",
    "Magyar",
    "Srpski");
for ($i = 1; $i <= 4; $i++)
{
?>
<option value="<?=$i?>" <?if ($lang==$i) { print "selected"; }><?=$language[$i]?></option>
<?
}
?>
</select>
<h3>Language is : <?=$lang?></h3>
 

my bad changed one thing. if ($lang==$language[$i]) { needed to be if ($lang==$i)

[dujmovicv]

Thank you for your efforts, you helped me a lot to learn PHP. With some corrections in your code, I have solved the problem. :)
Now I have another question, hope I'm not boring....
How to set the $language to 1 by default (when the page is being loaded for the first time)?
[php]
<?php
$lang = $_GET["language"];
?>
<select onchange="window.location='select.php?language='+t his.value">
<?php
$language = array(
"",
"English",
"Deutsch",
"Magyar",
"Srpski");
for ($i = 1; $i <= 4; $i++)
{
?>
<option value="<?=$i?>" <? if ($lang == $i) { print "SELECTED";}?>> <?=$language[$i]?></option>
<?
}
?>
</select>
<br>
<img src = " <?=$lang?>.gif" width="40" height="20">
[/php]

In that case, the field for the *.gif image is empty when the page is loaded, and after the user choice the script loads the appropriate image. How to load the 1.gif image at the start?

Best regards

[iam_clint]

ok to set it as 1 by default

<?php 
$lang = $_GET["language"]; 
if ($lang=="") {
    $lang = 1;
}
?> 
 

for the image you would do this on your page where you want the image

<? if ($lang==1) { ?>
what ever here for the image
<? } ?>