executing php blocks in a string

[JS]

From the examples I've seen, I don't think eval() works for this, or
if it does, I'm not sure how. Here's the setup. I'm storing web page
content in a database. 95% of the time, all the php takes outside of
the content area, setting up menus and footers, that sort of thing.
But some web pages have php code in the middle.
So I'll have a variable, $content, that looks like this:

$content = "<p>I'm content</p>\n\n<?php print \"hello world\n"; ?>
<p>More content</p>";

How can I get php to execute the code inside the code blocks in the
variable?

Thanks,

[Pedro Graca]

JS wrote:

So I'll have a variable, $content, that looks like this:

$content = "<p>I'm content</p>\n\n<?php print \"hello world\n"; ?>
<p>More content</p>";

How can I get php to execute the code inside the code blocks in the
variable?

This works for me:

<?php
$content = "<p>I'm content</p>\n\n<?php print \"hello world\n\";
?><p>More content</p>";
// you were missing a backslash here ________________________^__

// use '?>' to "get out" of PHP mode :)
eval('?>' . $content);
?>

I also tried the more logical
eval('?>' . $content . '<?php');
but that gives me a parse error
--
--= my mail box only accepts =--
--= Content-Type: text/plain =--
--= Size below 10001 bytes =--

[Pedro Graca]

Pedro Graca wrote:

This works for me:

<?php
$content = "<p>I'm content</p>\n\n<?php print \"hello world\n\";
?><p>More content</p>";
// you were missing a backslash here ________________________^__

// use '?>' to "get out" of PHP mode :) Except for the line above

The ?> ends the comment and the rest gives a parse error

When I tested it I didn't have the comments in :)
eval('?>' . $content);
?>

--
--= my mail box only accepts =--
--= Content-Type: text/plain =--
--= Size below 10001 bytes =--

[Chung Leong]

eval("?>$content<?");

Uzytkownik "JS" <jd***@hotmail.com> napisal w wiadomosci
news:b0**************************@posting.google.c om...

From the examples I've seen, I don't think eval() works for this, or
if it does, I'm not sure how. Here's the setup. I'm storing web page
content in a database. 95% of the time, all the php takes outside of
the content area, setting up menus and footers, that sort of thing.
But some web pages have php code in the middle.
So I'll have a variable, $content, that looks like this:

$content = "<p>I'm content</p>\n\n<?php print \"hello world\n"; ?>
<p>More content</p>";

How can I get php to execute the code inside the code blocks in the
variable?

Thanks,

[JS]

Thanks, that worked exactly as I hoped once I got my typos out.

Pedro Graca <he****@hotpop.com> wrote in message news:<c1*************@ID-203069.news.uni-berlin.de>...

Pedro Graca wrote:

This works for me:

<?php
$content = "<p>I'm content</p>\n\n<?php print \"hello world\n\";
?><p>More content</p>";
// you were missing a backslash here ________________________^__

// use '?>' to "get out" of PHP mode :)

Except for the line above

The ?> ends the comment and the rest gives a parse error

When I tested it I didn't have the comments in :)

eval('?>' . $content);
?>