Hi all,
I am struggling with understanding a small eregi problem in php4.
My code:
<?PHP
$htmlsource = '<img src="pics/hotdog.gif"> text text <img
src="pics/silly%20sausage.gif"> ';
eregi('(=")(pics/)([0-9a-zA-Z%/ ]+.[a-zA-z]..)(")',$htmlsource,$imagesintext);
?>
var_dump gives this, so I know it's working
Outputs
array(5) {
[0]=>
string(18) "="pics/hotdog.gif""
[1]=>
string(2) "=""
[2]=>
string(5) "pics/"
[3]=>
string(10) "hotdog.gif"
[4]=>
string(1) """
}
What I am trying to do is replace all images in the format ="pics/image.jpg"
with "image.jpg" and at the same time make a list of the files image.jpg.
The problem is how to pick up ALL the occurances, not just the first???
Also how to use replace to remove the pics/ bit of the string.
Thanks,
Nel. 4 2439
Nel wrote: <?PHP $htmlsource = '<img src="pics/hotdog.gif"> text text <img src="pics/silly%20sausage.gif"> '; eregi('(=")(pics/)([0-9a-zA-Z%/ ]+.[a-zA-z]..)(")',$htmlsource,$imagesintext); ?>
[...]
What I am trying to do is replace all images in the format ="pics/image.jpg" with "image.jpg" and at the same time make a list of the files image.jpg. The problem is how to pick up ALL the occurances, not just the first???
preg_match_all(). preg_match is described as an alternative to ereg()
and it stops searching after finding one match, so I assume ereg()
stops then too. http://www.php.net/manual/en/functio...-match-all.php
Also how to use replace to remove the pics/ bit of the string.
Replace them with the zero string. preg_replace(). http://www.php.net/manual/en/function.preg-replace.php
--
Jock
"John Dunlop" <us*********@john.dunlop.name> wrote in message
news:11**********************@g49g2000cwa.googlegr oups.com... Nel wrote:
<?PHP $htmlsource = '<img src="pics/hotdog.gif"> text text <img src="pics/silly%20sausage.gif"> '; eregi('(=")(pics/)([0-9a-zA-Z%/ ]+.[a-zA-z]..)(")',$htmlsource,$imagesintext);
Be aware that . matches any character: escape it with a \ if you want a
dot.
Also, the range A-z includes [\]^_` along the way. were you trying for this?
eregi('(=")(pics/)([0-9a-zA-Z_\-%/ ]+\.[jpgifpnJPGIFPN]{3})(")',$htmlsource,$imagesintext);
BTW, you should not allow spaces (%20) in filenames on a web site.
?> [...]
What I am trying to do is replace all images in the format ="pics/image.jpg" with "image.jpg" and at the same time make a list of the files image.jpg. The problem is how to pick up ALL the occurances, not just the first???
preg_match_all(). preg_match is described as an alternative to ereg() and it stops searching after finding one match, so I assume ereg() stops then too.
Try to tinker with preg_grep? http://www.php.net/manual/en/functio...-match-all.php
Also how to use replace to remove the pics/ bit of the string.
Replace them with the zero string. preg_replace().
http://www.php.net/manual/en/function.preg-replace.php
-- Jock
"Jim Michaels" <jm******@nospam.yahoo.com> wrote in message
news:27******************************@comcast.com. .. "John Dunlop" <us*********@john.dunlop.name> wrote in message news:11**********************@g49g2000cwa.googlegr oups.com... Nel wrote:
<?PHP $htmlsource = '<img src="pics/hotdog.gif"> text text <img src="pics/silly%20sausage.gif"> '; eregi('(=")(pics/)([0-9a-zA-Z%/ ]+.[a-zA-z]..)(")',$htmlsource,$imagesintext); Be aware that . matches any character: escape it with a \ if you want a dot. Also, the range A-z includes [\]^_` along the way. were you trying for this? eregi('(=")(pics/)([0-9a-zA-Z_\-%/ ]+\.[jpgifpnJPGIFPN]{3})(")',$htmlsource,$imagesintext);
can be further shortened:
eregi('(=")(pics/)([\d\w_\-%/ ]+\.[jpgifpnJPGIFPN]{3})(")',$htmlsource,$imagesintext);
BTW, you should not allow spaces (%20) in filenames on a web site. ?>
[...]
What I am trying to do is replace all images in the format ="pics/image.jpg" with "image.jpg" and at the same time make a list of the files image.jpg. The problem is how to pick up ALL the occurances, not just the first???
preg_match_all(). preg_match is described as an alternative to ereg() and it stops searching after finding one match, so I assume ereg() stops then too.
Try to tinker with preg_grep?
http://www.php.net/manual/en/functio...-match-all.php
Also how to use replace to remove the pics/ bit of the string.
Replace them with the zero string. preg_replace().
http://www.php.net/manual/en/function.preg-replace.php
-- Jock
On 2006-02-14, Jim Michaels <jm******@nospam.yahoo.com> wrote: "Jim Michaels" <jm******@nospam.yahoo.com> wrote in message news:27******************************@comcast.com. .. Be aware that . matches any character: escape it with a \ if you want a dot. Also, the range A-z includes [\]^_` along the way. were you trying for this? eregi('(=")(pics/)([0-9a-zA-Z_\-%/ ]+\.[jpgifpnJPGIFPN]{3})(")',$htmlsource,$imagesintext);
can be further shortened: eregi('(=")(pics/)([\d\w_\-%/ ]+\.[jpgifpnJPGIFPN]{3})(")',$htmlsource,$imagesintext);
yeah, both are equally non-functional.
I think what Jim intended was
eregi('(=")(pics/)([0-9A-Z_/\ %-]+\.[fgijnp]{3})(")'
,$htmlsource
,$imagesintext);
But thare's no law that images must have filenames that match that.
This: <img src="randompic.001.php">
is valid if the PHP sets content-type and emits a correctly formed inage...
Bye.
Jasen This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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