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Rexed replace with a list- Can I do this in PHP?

$string="The third letter of the alpabet is %%2%% and the second is
$string = preg_replace('/[%]{2}(.*?)[%]{2}/', '$ar[$1]', $string);
echo $string;

I want to see: "The third letter of the alphabet is c and the second
is b."
But what I see instead is: "The third letter of the alphabet is
$ar[$1] and the second is $ar[$1]." I tried double quotes, I tried no

The php.net page for preg_replace has some examples in the feedback
that SAY to to this, but go try running them yourself and changing the
numbers- all they really doing is printing the first element, every
time. (In the above example they'd be the equivalent of:
$string = preg_replace('/[%]{2}(.*?)[%]{2}/', $ar[0], $string);)

In perl I could do this easy:

How would I do this in PHP?
Jul 17 '05 #1
2 1667
mrbog wrote:
$string="The third letter of the alpabet is %%2%% and the second is
$string = preg_replace('/[%]{2}(.*?)[%]{2}/', '$ar[$1]', $string);
echo $string;

I want to see: "The third letter of the alphabet is c and the second
is b." How would I do this in PHP?

Use the /e modifier to evaluate the replaced part

$string = preg_replace('/[%]{2}(.*?)[%]{2}/e', '$ar[$1]', $string);
--= my mail box only accepts =--
--= Content-Type: text/plain =--
--= Size below 10001 bytes =--
Jul 17 '05 #2
Thanks much Pedro.
Jul 17 '05 #3

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