Pass Through Variable

[krunkelgarten]

Hi there,

I'm trying to create an image gallery, with (of course) for every
picture
the same javascript-pop-up. Because i use the same javascript, i only
want
to tell it the number of the image... Below is what i have, and it
works:

<?php $pic="01";list($width, $height, $type, $attr) =
getimagesize("./pix/$pic.jpg");
echo "<a href=\"javascript:MM_openBrWindow('foto.php?naam=$ pic&pic=./pix/$pic.jpg','dames3','width=$width,height=$height')\ "><img
src=\"./tmb/$pic.gif\" height=\"90\" width=\"90\" alt=\"$pic\"
/></a>";
?>

But when i copy it, and change $pic="01" to $pic="02", i get an error.
(Which
makes sense) But how can i tell the same script to take another
number..

The best would be something like <?php $pic="01"; print $script;
$pic="02"; print $script;
etc...
?>
$script would be everything of the earlier mentioned coding except for
'$pic = "..."' So you'd have to include it, but i can't even get that
to
work.. (I can't find a way to include php-script by calling it: echo
$script)

Hope you understand, thanks in advance..

Krunkelgarten

[CountScubula]

"krunkelgarten" <kr***********@hotmail.com> wrote in message
news:87**************************@posting.google.c om...

Hi there,

I'm trying to create an image gallery, with (of course) for every
picture
the same javascript-pop-up. Because i use the same javascript, i only
want
to tell it the number of the image... Below is what i have, and it
works:

<?php $pic="01";list($width, $height, $type, $attr) =
getimagesize("./pix/$pic.jpg");
echo "<a href=\"javascript:MM_openBrWindow('foto.php?naam=$ pic&pic=./pix/$pic.jpg','d
ames3','width=$width,height=$height')\"><img src=\"./tmb/$pic.gif\" height=\"90\" width=\"90\" alt=\"$pic\"
/></a>";
?>

But when i copy it, and change $pic="01" to $pic="02", i get an error.
(Which
makes sense) But how can i tell the same script to take another
number..

The best would be something like <?php $pic="01"; print $script;
$pic="02"; print $script;
etc...
?>
$script would be everything of the earlier mentioned coding except for
'$pic = "..."' So you'd have to include it, but i can't even get that
to
work.. (I can't find a way to include php-script by calling it: echo
$script)

Hope you understand, thanks in advance..

Krunkelgarten

you can't put script in a variable (dont even mention my tools, thats
another story)

2 simple ways to do this:

1: wrap the script you mention info a function
<?php
bla...
bla...
bla...

showStuff("01");
showStuff("02");
showStuff("03");
function showStuff($pic)
{

(put all that code here)

}

?>
2: put it in an include file, and inlude it over and over

<?php
bla...
bla...
bla...

$pic = "01";
include("mystuff.php");
$pic = "02";
include("mystuff.php");
$pic = "03";
include("mystuff.php");

?>
--

Mike Bradley
http://www.gzentools.com -- free online php tools

[krunkelgarten]

Hi there Count Scubula,

Is there any way i can contact you on this, and the image gallery?
Because it always takes so long to do it via Google.
I tried to mail you, but i get an error, could you please mail me
, you can se the right adress..

I'd greatly appreciate it..

Greetings Krunkelgarten

[Shawn Wilson]

krunkelgarten wrote:

Hi there,

I'm trying to create an image gallery, with (of course) for every
picture
the same javascript-pop-up. Because i use the same javascript, i only
want
to tell it the number of the image... Below is what i have, and it
works:

<?php $pic="01";list($width, $height, $type, $attr) =
getimagesize("./pix/$pic.jpg");
echo "<a href=\"javascript:MM_openBrWindow('foto.php?naam=$ pic&pic=./pix/$pic.jpg','dames3','width=$width,height=$height')\ "><img
src=\"./tmb/$pic.gif\" height=\"90\" width=\"90\" alt=\"$pic\"
/></a>";
?>

But when i copy it, and change $pic="01" to $pic="02", i get an error.
(Which
makes sense) But how can i tell the same script to take another
number..

The best would be something like <?php $pic="01"; print $script;
$pic="02"; print $script;
etc...
?>
$script would be everything of the earlier mentioned coding except for
'$pic = "..."' So you'd have to include it, but i can't even get that
to
work.. (I can't find a way to include php-script by calling it: echo
$script)

Hope you understand, thanks in advance..

<?PHP

function print_link($pic) {
if (!file_exists("./pix/$pic.jpg") || !file_exists("./tmb/$pic.gif"))
return false;
list($width, $height, $type, $attr) = getimagesize("./pix/$pic.jpg");
echo "<a href = \"javascript:MM_openBrWindow(
'foto.php?naam=$pic&pic=./pix/$pic.jpg',
'dames3','width=$width,height=$height')\"><img
src=\"./tmb/$pic.gif\" height=\"90\" width=\"90\" alt=\"$pic\"/></a>";
return true;
}
?>

Then call whatever you want:

print_link("01");
print_link("02");

or read the directory:

if ($dir = opendir("./pix/")):
$files = array();
while ($file = readdir($dir)) {
if (preg_match("/.+\.jpg$/", $file))
array_push($files, preg_replace("/^(.+)\.jpg$/", "\\1", $file));
}
closedir($dir);
sort($files);
foreach($files as $pic) {
print_link($pic);
}
else:
echo "Directory does not exist.";
endif;
Regards,
Shawn

--
Shawn Wilson
sh***@glassgiant.com
http://www.glassgiant.com

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