list ($d, $row) = each ($array) by reference?

[Jochen Daum]

Hi !

I always thought that

while (list($d,$row) = each($array)){
$row = 5;
}

would operate by reference, so that $array is filled with 5 after
this.
Instead it only seems to work with

$array[$d] = 5;

Can I use a & somewhere to do that?

Jochen
--
Jochen Daum - CANS Ltd.
PHP DB Edit Toolkit -- PHP scripts for building
database editing interfaces.
http://sourceforge.net/projects/phpdbedittk/

[Jedi121]

"Jochen Daum" a écrit le 21/11/2003 :

Hi !

I always thought that

while (list($d,$row) = each($array)){
$row = 5;
}

would operate by reference, so that $array is filled with 5 after
this.
Instead it only seems to work with

$array[$d] = 5;

Can I use a & somewhere to do that?

Jochen

If you use a numeric array, consider using array_fill()
Otherwise I don't really know for an associative array and/or the by
ref method.

[Jochen Daum]

Hi Jedi!
On Fri, 21 Nov 2003 00:38:56 +0100, Jedi121
<je*********@free.fr.Removethis> wrote:

"Jochen Daum" a écrit le 21/11/2003 :

Hi !

I always thought that

while (list($d,$row) = each($array)){
$row = 5;
}

would operate by reference, so that $array is filled with 5 after
this.
Instead it only seems to work with

$array[$d] = 5;

Can I use a & somewhere to do that?

Jochen

If you use a numeric array, consider using array_fill()

It was rather for more complex things....
Jochen
--
Jochen Daum - CANS Ltd.
PHP DB Edit Toolkit -- PHP scripts for building
database editing interfaces.
http://sourceforge.net/projects/phpdbedittk/

[Chung Leong]

Oh, the mystery of PHP references! I don't have an answer to your question.
In a similar situations I would array_walk, just so I don't have to think
about whether I'm getting a reference or not.

http://www.php.net/manual/en/function.array-walk.php

Uzytkownik "Jochen Daum" <jo*********@cans.co.nz> napisal w wiadomosci
news:s3********************************@4ax.com...

Hi !

I always thought that

while (list($d,$row) = each($array)){
$row = 5;
}

would operate by reference, so that $array is filled with 5 after
this.
Instead it only seems to work with

$array[$d] = 5;

Can I use a & somewhere to do that?

Jochen
--
Jochen Daum - CANS Ltd.
PHP DB Edit Toolkit -- PHP scripts for building
database editing interfaces.
http://sourceforge.net/projects/phpdbedittk/