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Variable passing to script to fill html <img src="MyScript.Php?ImageName=KnownGoodData" >

Hello,

I'm trying to do the above in order to process an image and return the
result to an html image control. It fails and my key suspects are either
the variable that I'm passing in - ImageName - for processing, or the return
data which is done (or not as the case may be) by imagejpeg($img) in the
script, after header("Content-type: image/jpeg").

Any insights would be most welcome, especially debugging techniques and a
pointer to resources to help me get a better feel for this complex
landscape.

Many thanks,

Gregory
Jul 17 '05 #1
14 13017
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
I'm trying to do the above in order to process an image and return the
result to an html image control. It fails and my key suspects are either
the variable that I'm passing in - ImageName - for processing, or the
return data which is done (or not as the case may be) by imagejpeg($img)
in the
script, after header("Content-type: image/jpeg").


Hi Gregory,

It would help if you could post the relevant code and error messages.

Stab in the dark:

Do you use $_GET['ImageName'] to retrieve the value?

JOn
Jul 17 '05 #2
Hello Jon,

No, I wasn't, but it still doesn't work.

Here's part of the loop that prints details and tries to print the image:

<?php $FilNam = $row_PrpSummary['FileName']; ?>
<td><img src="mkimg.php?ImageName=$FilNam" ></td>
<td>

Then mkimg.php starts like this (and maybe there needs to be header info):

<?php
echo $_GET['ImageName']; //--- debug attempt!
$image_path = 'e:\property\\data\\images\\' . $_GET['ImageName'];

There are no error messages.

Many thanks,

Gregory.

"Jon Kraft" <jo*@jonux.co.uk> wrote in message
news:bn*************@ID-175424.news.uni-berlin.de...
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
I'm trying to do the above in order to process an image and return the
result to an html image control. It fails and my key suspects are either the variable that I'm passing in - ImageName - for processing, or the
return data which is done (or not as the case may be) by imagejpeg($img)
in the
script, after header("Content-type: image/jpeg").


Hi Gregory,

It would help if you could post the relevant code and error messages.

Stab in the dark:

Do you use $_GET['ImageName'] to retrieve the value?

JOn

Jul 17 '05 #3
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
"Jon Kraft" <jo*@jonux.co.uk> wrote in message
news:bn*************@ID-175424.news.uni-berlin.de...
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
> the variable that I'm passing in - ImageName - for processing, or the
> return data which is done (or not as the case may be) by
> imagejpeg($img) in the
> script, after header("Content-type: image/jpeg").


Do you use $_GET['ImageName'] to retrieve the value?


No, I wasn't, but it still doesn't work.

Here's part of the loop that prints details and tries to print the image:

<?php $FilNam = $row_PrpSummary['FileName']; ?>
<td><img src="mkimg.php?ImageName=$FilNam" ></td>
<td>


Hi Gregory,

The above should be:

<td><img src="mkimg.php?ImageName=<?php echo urlencode($FilNam); ?>" ></td>

HTH;
JOn
Jul 17 '05 #4
Gregory wrote:
Then mkimg.php starts like this (and maybe there needs to be header info):

<?php
echo $_GET['ImageName']; //--- debug attempt!
$image_path = 'e:\property\\data\\images\\' . $_GET['ImageName'];


I would assume then you are doing something like this to output the data:

mkimg.php:
==========
<?php
$image_path = 'e:\property\\data\\images\\' . $_GET['ImageName'];
$fp=fopen($image_path,'rb');
$data=fread($fp,filesize($image_path));
header("Content-type: image/jpeg");
echo $data;
?>

--
Justin Koivisto - sp**@koivi.com
PHP POSTERS: Please use comp.lang.php for PHP related questions,
alt.php* groups are not recommended.

Jul 17 '05 #5
Thanks Jon and Justin, but it still fails. Is there any way that I can
check for the value inside the scrip file? Both files are in the same
directory. When I test for $_GET['ImageName'] back in the main file,
nothing is displayed.

Gregory.
"Jon Kraft" <jo*@jonux.co.uk> wrote in message
news:bn*************@ID-175424.news.uni-berlin.de...
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
"Jon Kraft" <jo*@jonux.co.uk> wrote in message
news:bn*************@ID-175424.news.uni-berlin.de...
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:

> the variable that I'm passing in - ImageName - for processing, or the
> return data which is done (or not as the case may be) by
> imagejpeg($img) in the
> script, after header("Content-type: image/jpeg").

Do you use $_GET['ImageName'] to retrieve the value?


No, I wasn't, but it still doesn't work.

Here's part of the loop that prints details and tries to print the image:
<?php $FilNam = $row_PrpSummary['FileName']; ?>
<td><img src="mkimg.php?ImageName=$FilNam" ></td>
<td>


Hi Gregory,

The above should be:

<td><img src="mkimg.php?ImageName=<?php echo urlencode($FilNam); ?>"
</td>

HTH;
JOn

Jul 17 '05 #6
Justin Koivisto <sp**@koivi.com> wrote:
I would assume then you are doing something like this to output the data:

mkimg.php:
==========
<?php
$image_path = 'e:\property\\data\\images\\' . $_GET['ImageName']; ^ ^^

In a string created with single quotes, 1 \ is sufficient AFAIK. It's
been a while I used a MS OS but to play it save e:/foo/bar should work
well.
$fp=fopen($image_path,'rb');
$data=fread($fp,filesize($image_path));
Barf.

1) opening a file without checking if it exists.
2) why do it the hardway if you only going to push it to the client?
header("Content-type: image/jpeg");
echo $data;
?>


<?php

if(file_exists($image_path))
{
header("Content-type: image/jpeg");
readfile($image_path);
}
else
{
die("file does not exist: $image_path");
}
--

Daniel Tryba

Jul 17 '05 #7
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
Thanks Jon and Justin, but it still fails. Is there any way that I can
check for the value inside the scrip file? Both files are in the same
directory. When I test for $_GET['ImageName'] back in the main file,
nothing is displayed. Gregory.


I beleive, to pass parameters after I think php 4.2?
Default setting of register_globals is off instead
of on. Can you validate what version you are using?
This would explain you getting nothing back.

if so, contain the following in .htaccess
php_flag register_globals on

look at ..
http://us3.php.net/manual/en/languag...s.superglobals

Hope this helps.
-Walt
-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----
Jul 17 '05 #8
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
"Jon Kraft" <jo*@jonux.co.uk> wrote:
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
> "Jon Kraft" <jo*@jonux.co.uk> wrote:
>> Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
>>
>> > the variable that I'm passing in - ImageName - for processing, or
>> > the return data which is done (or not as the case may be) by
>> > imagejpeg($img) in the
>> > script, after header("Content-type: image/jpeg").
>>
>> Do you use $_GET['ImageName'] to retrieve the value?
>>
> No, I wasn't, but it still doesn't work.


Thanks Jon and Justin, but it still fails. Is there any way that I can
check for the value inside the scrip file? Both files are in the same
directory. When I test for $_GET['ImageName'] back in the main file,
nothing is displayed.


Which version of PHP are you running? If less than 4.2.x try using:

$HTTP_GET_VARS['ImageName'];

JOn
Jul 17 '05 #9
I don't think that the script is even being called.

I've tried
<td width="150"><img src="mkimg.php?ImageName=<?php echo urlencode($FilNam);
?>" ></td>
and
<td width="150"><img src="c:\InetPub\wwwroot\property\test.php" ></td>
and put a die statement as the first command, but it lives. Perhaps my set
up is wrong.

Thanks,

Gregory

"Jon Kraft" <jo*@jonux.co.uk> wrote in message
news:bn*************@ID-175424.news.uni-berlin.de...
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
"Jon Kraft" <jo*@jonux.co.uk> wrote:
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:

> "Jon Kraft" <jo*@jonux.co.uk> wrote:
>> Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
>>
>> > the variable that I'm passing in - ImageName - for processing, or
>> > the return data which is done (or not as the case may be) by
>> > imagejpeg($img) in the
>> > script, after header("Content-type: image/jpeg").
>>
>> Do you use $_GET['ImageName'] to retrieve the value?
>>
> No, I wasn't, but it still doesn't work.


Thanks Jon and Justin, but it still fails. Is there any way that I can
check for the value inside the scrip file? Both files are in the same
directory. When I test for $_GET['ImageName'] back in the main file,
nothing is displayed.


Which version of PHP are you running? If less than 4.2.x try using:

$HTTP_GET_VARS['ImageName'];

JOn

Jul 17 '05 #10
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:

"Jon Kraft" <jo*@jonux.co.uk> wrote:
>> >>
>> >> Do you use $_GET['ImageName'] to retrieve the value?
>> >>
>> > No, I wasn't, but it still doesn't work.
>
> Thanks Jon and Justin, but it still fails. Is there any way that I can
> check for the value inside the scrip file? Both files are in the same
> directory. When I test for $_GET['ImageName'] back in the main file,
> nothing is displayed.
Which version of PHP are you running? If less than 4.2.x try using:

I don't think that the script is even being called.

I've tried
<td width="150"><img src="mkimg.php?ImageName=<?php echo
urlencode($FilNam); ?>" ></td>
and
<td width="150"><img src="c:\InetPub\wwwroot\property\test.php" ></td>


The second line would be wrong; the first line should at least call the PHP
script. Make sure the PHP script does actually echo an appropriate image
header, like image/jpeg. We replied each other so many times, I think it'd
be good if you could post the whole mkimg.php?

JOn
Jul 17 '05 #11
VVVVVVVVVVVVVVVVV

Key question has been asked several times WHAT VERSION of
php are you running? Your question is pivotal on 4.2!

-Walt

Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
I don't think that the script is even being called. I've tried
<td width="150"><img src="mkimg.php?ImageName=<?php echo urlencode($FilNam);
?>" ></td>
and
<td width="150"><img src="c:\InetPub\wwwroot\property\test.php" ></td>
and put a die statement as the first command, but it lives. Perhaps my set
up is wrong. Thanks, Gregory


Which version of PHP are you running? If less than 4.2.x try using:

$HTTP_GET_VARS['ImageName'];

JOn


--
Reply to innkeepATcapitalDOTnet to email questions.
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-----== Over 100,000 Newsgroups - 19 Different Servers! =-----
Jul 17 '05 #12
Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
Hello Jon, No, I wasn't, but it still doesn't work. Here's part of the loop that prints details and tries to print the image: <?php $FilNam = $row_PrpSummary['FileName']; ?>
<td><img src="mkimg.php?ImageName=$FilNam" ></td>
<td>
Ahhhh this should read ..... ?ImageName={$FilNam}" .........

don't you agree?

-Walt
Then mkimg.php starts like this (and maybe there needs to be header info): <?php
echo $_GET['ImageName']; //--- debug attempt!
$image_path = 'e:\property\\data\\images\\' . $_GET['ImageName'];


-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----
Jul 17 '05 #13
PenguinsAnonymous wrote:
I beleive, to pass parameters after I think php 4.2?
Default setting of register_globals is off instead
of on. Can you validate what version you are using?
This would explain you getting nothing back. if so, contain the following in .htaccess
php_flag register_globals on look at ..
http://us3.php.net/manual/en/languag...s.superglobals

Also it turns out this was bad advice...
On rereading the doc I pointed to several times I
had missed a subtlty.
enablement of register_globals leaves the passed
&xxx variables in a global space. This clutter
was abandoned in 4.2 with the super global usage
of $_GET. (internal to php)
so it is a deprecated functionality
also $HTTP_GET_VARS is deprecated.
check the missing '{}' I pointed to bet that works.

Sorry to confuse :)
-Walt
-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----
Jul 17 '05 #14
Hi Walt, Jon and Daniel,

Sorry to be slow on that. I had to attend to some other things, and I also
have cleaned up the examples that I'm sending here. It's php 4.3.3. Global
vars in the ini are set to off as recommended in the ini file itself, but
does not the $_GET function allow access to variables? - Ah I've just seen
your new post re globals. I'll have to re-read the manual.

Ok, here's the main file, which does display the original images. I've left
that functionality in to show that it works. I used dreamweaver to create
it in the first place, but the trial period's run out and I haven't decided
wherther or not to buy it yet.

<?php require_once('Connections/connProperty.php'); ?>
<?php
# Constants
//define(IMAGE_BASE, '/var/www/html/mbailey/images');
define(MAX_WIDTH, 150);
define(MAX_HEIGHT, 150);

$maxRows_PrpSummary = 9;
$pageNum_PrpSummary = 0;
if (isset($_GET['pageNum_PrpSummary'])) {
$pageNum_PrpSummary = $_GET['pageNum_PrpSummary'];
}
$startRow_PrpSummary = $pageNum_PrpSummary * $maxRows_PrpSummary;

mysql_select_db($database_connProperty, $connProperty);
$query_PrpSummary = "SELECT Prp.PreStreet House, Str.Name Street, sCi.Name
Borough, Cit.Name City,
ssC.Name District, sCy.Name County, Cry.Name
Country, PcX.Pic PcXPic,
Pic.Id PicId, Pic.FileName FileName,
Pic.FileLocation Location
FROM Property AS Prp
Left Outer Join Country Cry On Cry.Id = Prp.Cry
Left Outer Join sCountry sCy On sCy.Id = Prp.sCy
Left Outer Join ssCountry ssC On ssC.Id = Prp.ssC
Left Outer Join City Cit On Cit.Id = Prp.Cit
Left Outer Join sCity sCi On sCi.Id = Prp.sCi
Left Outer Join Street Str On Str.Id = Prp.Str
Left Outer Join PicToX PcX On PcX.TargetId =
Prp.Id And PcX.TargetType = 21
And PcX.Priority = 1
Left outer join Picture Pic On Pic.Id = PcX.Pic
";
$query_limit_PrpSummary = sprintf("%s LIMIT %d, %d", $query_PrpSummary,
$startRow_PrpSummary, $maxRows_PrpSummary);
$PrpSummary = mysql_query($query_limit_PrpSummary, $connProperty) or
die(mysql_error());
$row_PrpSummary = mysql_fetch_assoc($PrpSummary);

if (isset($_GET['totalRows_PrpSummary'])) {
$totalRows_PrpSummary = $_GET['totalRows_PrpSummary'];
} else {
$all_PrpSummary = mysql_query($query_PrpSummary);
$totalRows_PrpSummary = mysql_num_rows($all_PrpSummary);
}
$totalPages_PrpSummary = ceil($totalRows_PrpSummary/$maxRows_PrpSummary)-1;
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Untitled Document</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<meta http-equiv="Content-Type" content="image/jpeg; charset=iso-8859-1">
</head>

<body>
<table width="487" border="2" align="left" bgcolor="#99FFCC" frame="below">
<tr><td width="291">Address</td></tr>
<?php do { ?>
<tr>
<td height="107">
<?php echo $row_PrpSummary['House']; ?><br>
<?php echo $row_PrpSummary['Street']; ?><br>
<?php echo $row_PrpSummary['Borough']; ?><br>
<?php echo $row_PrpSummary['City']; ?><br>
<?php echo $row_PrpSummary['District']; ?><br>
<?php echo $row_PrpSummary['County']; ?> <?php echo
$row_PrpSummary['Country']; ?>
</td>
<td> <! Orig image.
<img src="<?php echo 'e:\\property\\data\\images\\' .
$row_PrpSummary['FileName'];?>">
</td>
<td> <! Try to call mkimg.php.
<img src="mkimg.php?ImageName=<?php echo 'e:\\property\\data\\images\\'
.. $row_PrpSummary['FileName'];?>" >
</td>
<td>
<?php echo 'e:\\property\\data\\images\\' .
$row_PrpSummary['FileName'];?> <! testing that data's ok.
</td>
</tr>
<?php } while ($row_PrpSummary = mysql_fetch_assoc($PrpSummary)); ?>
</table>
</body>
</html>
<?php
mysql_free_result($PrpSummary);
?>
And here is the script to make a smaller image. Again, this worked in it's
original form. I tested it with a single known image and it worked, but I
haven't tested it since messing around with it. I don't think that it's
actually being called, as it won't even die().

<?php
define(MAX_WIDTH, 150);
define(MAX_HEIGHT, 150);
die('here I am');
echo $image_path = 'e:\\property\\data\\images\\' . $_GET['ImageName'];
$img = null;
$ext = strtolower(end(explode('.', $image_path)));
if ($ext == 'jpg' || $ext == 'jpeg') {
$img = @imagecreatefromjpeg($image_path);
} else if ($ext == 'png') {
$img = @imagecreatefrompng($image_path);
# Only if your version of GD includes GIF support
} else if ($ext == 'gif') {
$img = @imagecreatefrompng($image_path);
}

# If an image was successfully loaded, test the image for size
if ($img) {
# Get image size and scale ratio
$width = imagesx($img);
$height = imagesy($img);
$scale = min(MAX_WIDTH/$width, MAX_HEIGHT/$height);

# If the image is larger than the max shrink it
if ($scale < 1) {
$new_width = floor($scale*$width);
$new_height = floor($scale*$height);

# Create a new temporary image
$tmp_img = imagecreatetruecolor($new_width, $new_height);

# Copy and resize old image into new image
imagecopyresized($tmp_img, $img, 0, 0, 0, 0,
$new_width, $new_height, $width, $height);
imagedestroy($img);
$img = $tmp_img;
}
}

# Create error image if necessary
if (!$img) {
$img = imagecreate(MAX_WIDTH, MAX_HEIGHT);
imagecolorallocate($img,0,0,0);
$c = imagecolorallocate($img,70,70,70);
imageline($img,0,0,MAX_WIDTH,MAX_HEIGHT,$c2);
imageline($img,MAX_WIDTH,0,0,MAX_HEIGHT,$c2);
}

header("Content-type: image/jpeg");
imagejpeg($img);
?>

Thanks,

Gregory.

<PenguinsAnonymous> wrote in message news:3f********@corp.newsgroups.com...
VVVVVVVVVVVVVVVVV

Key question has been asked several times WHAT VERSION of
php are you running? Your question is pivotal on 4.2!

-Walt

Gregory <php at neutrino-soft @@@ ware.co.uk> wrote:
I don't think that the script is even being called.

I've tried
<td width="150"><img src="mkimg.php?ImageName=<?php echo urlencode($FilNam);
?>" ></td>
and
<td width="150"><img src="c:\InetPub\wwwroot\property\test.php" ></td>
and put a die statement as the first command, but it lives. Perhaps my set up is wrong.

Thanks,

Gregory


Which version of PHP are you running? If less than 4.2.x try using:

$HTTP_GET_VARS['ImageName'];

JOn


--
Reply to innkeepATcapitalDOTnet to email questions.
-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----

Jul 17 '05 #15

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