PHP 4.3.3

[Wayne]

Ok I hope someone can clear this up for me because my laptop is going
in the bin or across the room soon.

I have installed versions:

MySQL 4.0.15
Apache 2.0.47
PHP 4.3.3

I have put the php4ts.dll in c:\winnt\system32\
I have changed the php.ini in c:\winnt\
I have changed the httpd.conf in c:\Program FIles\Apache
Group\Apache2\conf\

I have done bloody everything...

Apache I know works I can get the page up when I go localhost on
browser.
MySQL works because I have tried examples.
PHP seems to work with most things, but not with IF () statements!

for example:

<?php
if ($submit == "Go") {
echo("you wrote ".$you_wrote);
echo("<br>You could have written");
exit;
}
?>
<form action="<?php echo($PHP_SELF) ?>" method="POST" >
<p>Input a word <input type="text" size="20" name="you_wrote">
<input type="submit" name="Submit" value="Go"></p>
</form>

If I save this as php file and go to browser and call it up, I get
notice come up

"Notice: Undefined variable: submit in C:\Program Files\Apache
Group\Apache2\htdocs\test0.php on line 2"

Line being if ($submit == "Go") {

Can someone please tell me what needs doing please....

[Bert]

On 30 Sep 2003 07:32:18 -0700, w.*******@rchl.org.uk (Wayne) wrote:

Ok I hope someone can clear this up for me because my laptop is going
in the bin or across the room soon.

I have installed versions:

MySQL 4.0.15
Apache 2.0.47
PHP 4.3.3

I have put the php4ts.dll in c:\winnt\system32\
I have changed the php.ini in c:\winnt\
I have changed the httpd.conf in c:\Program FIles\Apache
Group\Apache2\conf\

I have done bloody everything...

Apache I know works I can get the page up when I go localhost on
browser.
MySQL works because I have tried examples.
PHP seems to work with most things, but not with IF () statements!

for example:

<?php
if ($submit == "Go") {
echo("you wrote ".$you_wrote);
echo("<br>You could have written");
exit;
}
?>
<form action="<?php echo($PHP_SELF) ?>" method="POST" >
<p>Input a word <input type="text" size="20" name="you_wrote">
<input type="submit" name="Submit" value="Go"></p>
</form>

If I save this as php file and go to browser and call it up, I get
notice come up

"Notice: Undefined variable: submit in C:\Program Files\Apache
Group\Apache2\htdocs\test0.php on line 2"

Line being if ($submit == "Go") {

Can someone please tell me what needs doing please....

Not sure, but did you try if ($_POST['submit'] == "Go") {...
B.

[Bert]

On Tue, 30 Sep 2003 14:40:12 GMT, Bert <be**@pandora.invalid> wrote:

Not sure, but did you try if ($_POST['submit'] == "Go") {...
B.

and change $PHP_SELF to $_SERVER['PHP_SELF'] while you're at it :)
B.

[Justin Koivisto]

Bert wrote:

On Tue, 30 Sep 2003 14:40:12 GMT, Bert <be**@pandora.invalid> wrote:

Not sure, but did you try if ($_POST['submit'] == "Go") {...
B.

and change $PHP_SELF to $_SERVER['PHP_SELF'] while you're at it :)
B.

Or if you don't want to edit tons of files, in php.ini:
register_globals = On

--
Justin Koivisto - sp**@koivi.com
PHP POSTERS: Please use comp.lang.php for PHP related questions,
alt.php* groups are not recommended.

[Phil Roberts]

With total disregard for any kind of safety measures
w.*******@rchl.org.uk (Wayne) leapt forth and uttered:

Ok I hope someone can clear this up for me because my laptop is
going in the bin or across the room soon.

I have installed versions:

MySQL 4.0.15
Apache 2.0.47
PHP 4.3.3

I have put the php4ts.dll in c:\winnt\system32\
I have changed the php.ini in c:\winnt\
I have changed the httpd.conf in c:\Program FIles\Apache
Group\Apache2\conf\

I have done bloody everything...

Apache I know works I can get the page up when I go localhost on
browser.
MySQL works because I have tried examples.
PHP seems to work with most things, but not with IF ()
statements!

for example:

<?php
if ($submit == "Go") {
echo("you wrote ".$you_wrote);
echo("<br>You could have written");
exit;
}
?>
<form action="<?php echo($PHP_SELF) ?>" method="POST" >
<p>Input a word <input type="text" size="20" name="you_wrote">
<input type="submit" name="Submit" value="Go"></p>
</form>

If I save this as php file and go to browser and call it up, I
get notice come up

"Notice: Undefined variable: submit in C:\Program Files\Apache
Group\Apache2\htdocs\test0.php on line 2"

Line being if ($submit == "Go") {

Can someone please tell me what needs doing please....

You need to set the error reporting to suppress notices, it
explains how in php.ini

--
There is no signature.....

[Andy Hassall]

On Tue, 30 Sep 2003 12:14:55 -0500, Phil Roberts <ph*****@HOLYflatnetSHIT.net>
wrote:

You need to set the error reporting to suppress notices, it
explains how in php.ini

You could also close your eyes, that works too. Don't ignore warnings; they're
there for a reason!

In this case the OP seems to think that global variables will be defined for
form inputs; they aren't, unless you change the configuration, and there's good
reasons why you shouldn't.

Look up 'register_globals', the Predefined Variables section of the manual,
and the 4.1.0 and 4.2.0 release announcements on php.net.

--
Andy Hassall (an**@andyh.co.uk) icq(5747695) (http://www.andyh.co.uk)
Space: disk usage analysis tool (http://www.andyhsoftware.co.uk/space)

[medi]

"Wayne" <w.*******@rchl.org.uk> wrote in message
news:b4**************************@posting.google.c om...

Ok I hope someone can clear this up for me because my laptop is going
in the bin or across the room soon.

I have installed versions:

MySQL 4.0.15
Apache 2.0.47
PHP 4.3.3

I have put the php4ts.dll in c:\winnt\system32\
I have changed the php.ini in c:\winnt\
I have changed the httpd.conf in c:\Program FIles\Apache
Group\Apache2\conf\

I have done bloody everything...

Apache I know works I can get the page up when I go localhost on
browser.
MySQL works because I have tried examples.
PHP seems to work with most things, but not with IF () statements!

for example:

<?php
if ($submit == "Go") {
echo("you wrote ".$you_wrote);
echo("<br>You could have written");
exit;
}
?>
<form action="<?php echo($PHP_SELF) ?>" method="POST" >
<p>Input a word <input type="text" size="20" name="you_wrote">
<input type="submit" name="Submit" value="Go"></p>
</form>

If I save this as php file and go to browser and call it up, I get
notice come up

"Notice: Undefined variable: submit in C:\Program Files\Apache
Group\Apache2\htdocs\test0.php on line 2"

Line being if ($submit == "Go") {

That's because submit buttons never pass their name as variable (POST or
GET).
That's why hidden fields are used. Try this:

<?php

if (isset($_POST['status']))
{
if($_POST['status'] == "Go")
{
echo("you wrote ".$_POST['you_wrote']);
echo("<br>You could have written");
exit;
}
}

?>

<form action="<?php echo($_SERVER['PHP_SELF']) ?>" method="POST"><p>
Input a word <input type="text" size="20" name="you_wrote">
<input type="submit" name="submit" value="Go">
<input name="status" type="hidden" value="Go">
</form>

Hope this will help....

[Andy Hassall]

On Tue, 30 Sep 2003 23:36:30 +0200, "medi" <me**@spinter.net> wrote:

<input type="submit" name="Submit" value="Go"></p>
</form>

If I save this as php file and go to browser and call it up, I get
notice come up

"Notice: Undefined variable: submit in C:\Program Files\Apache
Group\Apache2\htdocs\test0.php on line 2"

Line being if ($submit == "Go") {

That's because submit buttons never pass their name as variable (POST or
GET).
That's why hidden fields are used. Try this:

Named submit controls can be successful controls:

<form method="get" action="">
<input type="submit" name="submitButton" value="whatever">
</form>
<pre>
<?php
var_dump($_GET);
?>
</pre>

Submit the form back to itself, output is:

array(1) {
["submitButton"]=>
string(8) "whatever"
}

http://www.w3.org/TR/html4/interact/...ssful-controls

"If a form contains more than one submit button, only the activated submit
button is successful. "

Therefore a submit button can be successful, and so sends a value.

--
Andy Hassall (an**@andyh.co.uk) icq(5747695) (http://www.andyh.co.uk)
Space: disk usage analysis tool (http://www.andyhsoftware.co.uk/space)