having trouble with string replacement

[laredotornado]

Hello,

I have strings on my page of the form

param1=abcd&agency_id=1234&param2=dex

I want to write a PHP expression to take strings similar to the above,
and output

param1=abcd&agency_id=<?php echo $LTON; ?>&param2=dex

How can I do this?

Thanks, - Dave

[maarten.laurs]

You just did!

I don't get it. What's the problem?

[Erwin Moller]

la***********@zipmail.com wrote:

Hello,

I have strings on my page of the form

param1=abcd&agency_id=1234&param2=dex

I want to write a PHP expression to take strings similar to the above,
and output

param1=abcd&agency_id=<?php echo $LTON; ?>&param2=dex

How can I do this?

Thanks, - Dave

Hi Dave,

Looks fine to me.
What is your problem?

What does it produce that you didn't expect?
Does $LTON have a value?

Regards,
Erwin Moller

[laredotornado]

I actually want the result string (what is printed to the browser) to
look like

param1=abcd&agency_id=<?php echo $LTON; ?>&param2=dex

This PHP code:

<?php
$str = "&mine=20&agency_id=234&test=abc";
$search = "/agency_id=\\d+/i";
$replace = "agency_id=<?php echo \$LTON; ?>";
$retVal = preg_replace($search, $replace, $str);
print $retVal;
?>

regrettably produces the wrong result

&mine=20&agency_id=&test=abc

How can I heal the pain? Thanks, - Dave

[Erwin Moller]

la***********@zipmail.com wrote:

I actually want the result string (what is printed to the browser) to
look like

param1=abcd&agency_id=<?php echo $LTON; ?>&param2=dex

This PHP code:

<?php
$str = "&mine=20&agency_id=234&test=abc";
$search = "/agency_id=\\d+/i";
$replace = "agency_id=<?php echo \$LTON; ?>";
$retVal = preg_replace($search, $replace, $str);
print $retVal;
?>

regrettably produces the wrong result

&mine=20&agency_id=&test=abc

How can I heal the pain? Thanks, - Dave

Hi Dave,

The answer is actually very simple:
Your desired line:
param1=abcd&agency_id=<?php echo $LTON; ?>&param2=dex

is not a legal url.

You should urlencode all paramvalues before using them in an URL.

So try something like:
$theURL = "?param1=".urlencode("abcd");
// not very usefull, but you should do it with values
// that possible contain difficult character.

$theURL .= "&agency_id=".urlencode("<?php echo $LTON; ?>");

$theURL .= "&param2=".urlencode("abc");
That should work.
Check your results by starting your script with:

<pre>
<? print_r($_GET); ?>
</pre>
It will spit out all name/value-pairs.

Good luck,
Erwin Moller

[laredotornado]

Thanks for your reply. However, know that what is happening is that
the result of the search and replace will be output to another PHP
file, which will then be interpreted. So

param1=abcd&agency_id=<?php echo $LTON; ?>&param2=dex

is the output that I want to go to the PHP file. That file will then
be interpreted, and the legal URL will be formed from that.

Sorry I didn't mention that earlier. Thanks for any further
assistance, - Dave

[frizzle]

Just try to put what you want directly into the address bar,
and you'll see (most ?) browsers will translate it to an url-safe
address, which means
<?php echo $LTON; ?>
becomes
%3C?php%20echo%20$LTON;%20?%3E

Greetings Frizzle.

[feed_sheep]

<la***********@zipmail.com> wrote in message
news:11**********************@f14g2000cwb.googlegr oups.com...

<?php
$str = "&mine=20&agency_id=234&test=abc";
$search = "/agency_id=\\d+/i";
$replace = "agency_id=<?php echo \$LTON; ?>";
$retVal = preg_replace($search, $replace, $str);
print $retVal;
?>

I can't see how you have it set up, but if a previous page does not pass the
variable $LTON, it will of course equal nothing. Also, you are putting
<?php ?> instead of <?php ?> tags.

This code works:

<?php
$LTON = 1;
$str = "&mine=20&agency_id=234&test=abc";
$search = "/agency_id=\d+/i";
$replace = "agency_id=" . $LTON;
$retVal = preg_replace($search, $replace, $str);
print $retVal;
?>

David

[feed_sheep]

> I can't see how you have it set up, but if a previous page does not pass

the variable $LTON, it will of course equal nothing. Also, you are
putting <?php ?> instead of <?php ?> tags.

^^^ I meant "inside".