cannot access inc files from a function

[bettina]

I have the following piece of code (symplified)

require("lang.{$lang}.inc.php"); // I include the inc. files
....
function decodify($technique) { // functions that give me back the
value in inc.file
switch ($technique) {
case 'C':
echo $charcoal;
break;
case 'O':
echo $oil;
break;
case 'A':
echo $acrylic;
break;
}
}
.....
Somewhere I call the function ....decodify($myTechnique)

But it doen't print the content from $charcoal, $oil or, etc.
Do I have to declare the function global or something like that. In
that case, how should I do it??
Many thanks. Bettina

[DXTrim]

Hallo Bettina,

What is the exact name of the file you are trying to include. Your construct
is very weird, if the file is "lang.EN.inc.php" for example, try:

require("lang.$lang.inc.php");

Also, could you post the code of that included file so we can see if the
values are really there.

Hope this helps,

DXTrim
<be*****@coaster.ch> wrote in message
news:11**********************@g49g2000cwa.googlegr oups.com...

I have the following piece of code (symplified)

require("lang.{$lang}.inc.php"); // I include the inc. files
...
function decodify($technique) { // functions that give me back the
value in inc.file
switch ($technique) {
case 'C':
echo $charcoal;
break;
case 'O':
echo $oil;
break;
case 'A':
echo $acrylic;
break;
}
}
....
Somewhere I call the function ....decodify($myTechnique)

But it doen't print the content from $charcoal, $oil or, etc.
Do I have to declare the function global or something like that. In
that case, how should I do it??
Many thanks. Bettina

[Giannis Vrentzos]

be*****@coaster.ch wrote:

I have the following piece of code (symplified)

require("lang.{$lang}.inc.php"); // I include the inc. files
...
function decodify($technique) { // functions that give me back the
value in inc.file
switch ($technique) {
case 'C':
echo $charcoal;
break;
case 'O':
echo $oil;
break;
case 'A':
echo $acrylic;
break;
}
}
....
Somewhere I call the function ....decodify($myTechnique)

But it doen't print the content from $charcoal, $oil or, etc.
Do I have to declare the function global or something like that. In
that case, how should I do it??
Many thanks. Bettina

You cannot access a variable that is outside of a function unless you
write global $var; inside the function. The other way is to include the
lang file inside the function.

Gvre

[bettina]

Hi DXTrim,

the values are really there since I use the references outside the
function and it work ok. I think it has something to do with what says
Giannis regarding the global variable. I'll try that. Thank you.

DXTrim schrieb:

Hallo Bettina,

What is the exact name of the file you are trying to include. Your construct
is very weird, if the file is "lang.EN.inc.php" for example, try:

require("lang.$lang.inc.php");

Also, could you post the code of that included file so we can see if the
values are really there.

Hope this helps,

DXTrim
<be*****@coaster.ch> wrote in message
news:11**********************@g49g2000cwa.googlegr oups.com...

I have the following piece of code (symplified)

require("lang.{$lang}.inc.php"); // I include the inc. files
...
function decodify($technique) { // functions that give me back the
value in inc.file
switch ($technique) {
case 'C':
echo $charcoal;
break;
case 'O':
echo $oil;
break;
case 'A':
echo $acrylic;
break;
}
}
....
Somewhere I call the function ....decodify($myTechnique)

But it doen't print the content from $charcoal, $oil or, etc.
Do I have to declare the function global or something like that. In
that case, how should I do it??
Many thanks. Bettina

[bettina]

How should I define the global variable inside this function? What must
be global is the lang.{$lang}.inc.php so that it can be read inside the
function, isn't it?. I tried including the lang file in the function
but I receive an error.

require("lang.{$lang}.inc.php");
function technique($t) {
switch ($t) {
case 'C':
echo $charcoal;
break;
case 'O':
echo $oil;
break;
case 'A':
echo $acrylic;
break;
}
}

<? technique($myTechnik ?>

[jamen]

be*****@coaster.ch wrote:

How should I define the global variable inside this function? What must
be global is the lang.{$lang}.inc.php so that it can be read inside the
function require("lang.{$lang}.inc.php");
function technique($t) {
switch ($t) {
case 'C':
echo $charcoal;
...

$charcoal is local to your function. You can do it in two ways..

1.
function technique($t) {
global $charcoal;

switch ($t) {
case 'C':
echo $charcoal;

2.
function technique($t) {
switch ($t) {
case 'C':
echo $GLOBAL['charcoal'];

[Giannis Vrentzos]

be*****@coaster.ch wrote:

How should I define the global variable inside this function? What must
be global is the lang.{$lang}.inc.php so that it can be read inside the
function, isn't it?. I tried including the lang file in the function
but I receive an error.

require("lang.{$lang}.inc.php");
function technique($t) {
switch ($t) {
case 'C':
echo $charcoal;
break;
case 'O':
echo $oil;
break;
case 'A':
echo $acrylic;
break;
}
}

<? technique($myTechnik ?>

function technique($t) {
global $lang; // here we are using the global var $lang
$incFile = "lang.{$lang}.inc.php";

if ( file_exists($incFile) )
include ($incFile);
else
return;

switch ($t) {
case 'C':
echo $charcoal;
break;
case 'O':
echo $oil;
break;
case 'A':
echo $acrylic;
break;
}
}

Gvre

ps. To OP. You can put all strings in file "lang.{$lang}.inc.php" in an
array and access it like this. If you do it like this you don't have to
change the function technique($t) every time you put a new var in lang file.

// vars file
$strings = array (
"C" => "charcoal",
"O" => "oil",
"A" => "acrylic"
);
// index ? file
$incFile = "lang.{$lang}.inc.php";
if ( file_exists($incFile) )
include ($incFile);
else
return; // or any other action

// functions file
function technique($t) {
global $strings;

if (array_key_exists($t, $strings))
echo $strings[$t];

}

[bettina]

Thank you, the first option works ok!

[bettina]

Hallo Giannis, that of putting everything in my lang file so that I
don't have to change the function every time I add a new variable works
fine! Thank you for the tip!

Giannis Vrentzos schrieb:

be*****@coaster.ch wrote:

How should I define the global variable inside this function? What must
be global is the lang.{$lang}.inc.php so that it can be read inside the
function, isn't it?. I tried including the lang file in the function
but I receive an error.

require("lang.{$lang}.inc.php");
function technique($t) {
switch ($t) {
case 'C':
echo $charcoal;
break;
case 'O':
echo $oil;
break;
case 'A':
echo $acrylic;
break;
}
}

<? technique($myTechnik ?>

function technique($t) {
global $lang; // here we are using the global var $lang
$incFile = "lang.{$lang}.inc.php";

if ( file_exists($incFile) )
include ($incFile);
else
return;

switch ($t) {
case 'C':
echo $charcoal;
break;
case 'O':
echo $oil;
break;
case 'A':
echo $acrylic;
break;
}
}

Gvre

ps. To OP. You can put all strings in file "lang.{$lang}.inc.php" in an
array and access it like this. If you do it like this you don't have to
change the function technique($t) every time you put a new var in lang file.

// vars file
$strings = array (
"C" => "charcoal",
"O" => "oil",
"A" => "acrylic"
);
// index ? file
$incFile = "lang.{$lang}.inc.php";
if ( file_exists($incFile) )
include ($incFile);
else
return; // or any other action

// functions file
function technique($t) {
global $strings;

if (array_key_exists($t, $strings))
echo $strings[$t];

}

[Jasen Betts]

> But it doen't print the content from $charcoal, $oil or, etc.

Do I have to declare the function global or something like that. In
that case, how should I do it??
Many thanks. Bettina

to combine some of the ideas in this thread...
replace the whole case block with:

echo $GLOBAL[array('C'=>'charcoal','O'=>'oil','A'=>'acrylic')[$technique]];
Bye.
Jasen