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Var in PHP 5 question

Hi all,
I've written a large system for PHP4 that declares class variables
using the 'var' keyword. I'm now upgrading to PHP5, and it seems I have
to change 'var' to private / public / protected, which don't work in
PHP4. Is there anyway to make my system compatible with both versions?

Cheers,
Paul.

Jul 24 '05 #1
2 15360
pf******@hotmail.com wrote:
I've written a large system for PHP4 that declares class variables
using the 'var' keyword. I'm now upgrading to PHP5, and it seems I
have to change 'var' to private / public / protected, which don't
work in PHP4. Is there anyway to make my system compatible with both
versions?


The var keyword is supported in PHP5, albeit deprecated. If you want your
code to be both backwards compatible and take advantage of PHP5's
declaration style, the best thing you can do is to write classes for both
versions and apply them conditionally:

if (PHP_VERSION < 5) {
include "php4class.php";
} else {
include "php5class.php";
}

$obj = new MyClass;
JW

Jul 24 '05 #2
In PHP 5 this is reported as a warning, not an error, so it will still run
OK. I know because I have encountered the same situation with code that I
use which needs to run under both PHP 4 and PHP 5.

--
Tony Marston

http://www.tonymarston.net

<pf******@hotmail.com> wrote in message
news:11*********************@g44g2000cwa.googlegro ups.com...
Hi all,
I've written a large system for PHP4 that declares class variables
using the 'var' keyword. I'm now upgrading to PHP5, and it seems I have
to change 'var' to private / public / protected, which don't work in
PHP4. Is there anyway to make my system compatible with both versions?

Cheers,
Paul.

Jul 25 '05 #3

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