Inconsistent type checking results

[Shelly]

(Also posted in dreamweaver forum)

I have two *.jpg files. They both display perfectly on my local system. I
have a check on the type of file in my upload where I check the first five
characters for "image".

One uploads and the other does not.
One passes the "image" test and the other has an empty string there, so it
fails the upload.

If I copy that one that fails to a location on the server using Dreamweaver
(outside of my php script) and then try to display it in my web page, it
displays perfectly.

Does anyone have a clue?

Shelly

[pfrank26]

There are two main types of jpg in the system - jpeg and pjpeg. One
solution is to use the PHP command getimagesize - see
http://uk2.php.net/manual/en/function.getimagesize.php . The array it
returns contains the type of image the supplied file is.

[Shelly]

<pf******@hotmail.com> wrote in message
news:11**********************@o13g2000cwo.googlegr oups.com...

There are two main types of jpg in the system - jpeg and pjpeg. One
solution is to use the PHP command getimagesize - see
http://uk2.php.net/manual/en/function.getimagesize.php . The array it
returns contains the type of image the supplied file is.

I'll try that (in a few weeks), but I am not sure I made myself clear to you
as to what my problem is. Let me clarify.

I use type=file in the html description of the field with a name of
name=filename. Then when I check the type from that one of the images is
"image" for the first five characters of the type, but the other is blank.
They are both jpg extensions. What I use is $_FILES['filename']['type'],
the global variable filled in by the file type textbox using the browse
button supplied.

Now from reading the documentation it seems to me that getimagesize() is a
server-side function to get the details on a file that is on the server. I
do the testing before actually uploading the file. This is standard
procedure. If the file is not of the proper type, the upload is not done.
Dos the getimagesize() work on a file on the user's system? I would think
not because that would allow the server to browse the user's system
indiscriminately, rather than merely looking at the supplied file -- a major
privacy breach.

Shelly

[John Dunlop]

Shelly wrote:

I have two *.jpg files. They both display perfectly on my local system. I
have a check on the type of file in my upload where I check the first five
characters for "image".
Is that check $_FILES['filename']['type']? As another poster
suggested, you could use getimagesize() to determine the type;
or mime_content_type(); or a mixture of all three.
$_FILES['filename']['type'], if given at all, is from the
browser, and so you can't rely on it being 100 % accurate.
One uploads and the other does not.
actually doesn't upload? If so, what error is reported?
One passes the "image" test and the other has an empty string there, so it
fails the upload.
...or it uploads but you discard it because of your "image"
test?
If I copy that one that fails to a location on the server using Dreamweaver
(outside of my php script) and then try to display it in my web page, it
displays perfectly.

Where are the jpegs, and I can try at my end. (I trust they
aren't dirty!?)

--
Jock

[Shelly]

"John Dunlop" <us*********@john.dunlop.name> wrote in message
news:MP************************@news.ntlworld.com. ..

Shelly wrote:

I have two *.jpg files. They both display perfectly on my local system.
I
have a check on the type of file in my upload where I check the first
five
characters for "image".

Is that check $_FILES['filename']['type']? As another poster
suggested, you could use getimagesize() to determine the type;
or mime_content_type(); or a mixture of all three.
$_FILES['filename']['type'], if given at all, is from the
browser, and so you can't rely on it being 100 % accurate.

Interesting.

One uploads and the other does not.

actually doesn't upload? If so, what error is reported?

None. I do checking and report my own message.

One passes the "image" test and the other has an empty string there, so
it
fails the upload.

...or it uploads but you discard it because of your "image"
test?

I don't know for sure. I assumed it didn't upload but maybe it did and I
threw it away. I thought the check was before it actually uploaded.

If I copy that one that fails to a location on the server using
Dreamweaver
(outside of my php script) and then try to display it in my web page, it
displays perfectly.

Where are the jpegs, and I can try at my end. (I trust they
aren't dirty!?)

Of course not. However, I am away on vacation and so I can't send them now
as they are on my home computer. Thanks anyway.

Shelly