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P: n/a
Hi ( and I'm sorry in advance ),
I have looked in but I can't figure out how it's done.
I want to show a list of the three latest inserted posts in a mysql-table.
The list is meant to be an apertizer and the users have to click on it to
see the whole output from the DB.
How do I make the link to open that exact post?

Here is what is working for now:


$link = mysql_connect("server", "user", "pass")
or die("Could not connect: " . mysql_error());
print ("Connected successfully");
$result = mysql_query("SELECT ID, tekst, DATE_FORMAT(dato, '%d %m %Y
kl. %H:%i')as dato FROM henriks ORDER BY ID desc LIMIT 0,3");
while ($raekke = mysql_fetch_array($result)){

echo"<P> ID: ".$raekke['ID']."<br>";
$text = $raekke['tekst'];

echo"Tekst: ".nl2br(substr($text,0,50))."....";
echo"<BR>Dato: ".$raekke['dato'];


Regards Ricki
Jul 16 '05 #1
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1 Reply

P: n/a

Create another php page that expects the ID as a GET variable
as you loop through your dataset (as per your code snippet) do
something like the following:

print "<a href='showpost.php?id={$raekke["ID"]}'>Some Text</a>";

Then showpost.php:

Offcourse; it seems obvious. Thank you!

Jul 16 '05 #2

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