Adding fields to an object in PHP 4

[jerrygarciuh]

Hello,

I have an object that looks like this:

shelterrental Object
(
[connectionError] =>
[changedVals] => Array ( )
[dbh] => Resource id #2
[id] => 1 [shelter] => 1
[renter] => Kevin Shakakhnopolis
[contact] => 504-899-4028
[date] => 2005-04-11
)

I would like to add a field or two under certain circumstances. I have
tried

$obj->newfield = 'xxx';
$obj->{'newfield'} = 'yyy';
$obj['newfield'] = 'zzz';

None of these methods work.

What is the correct syntax to add a field to an object in PHP 4?

TIA!

jg

[Janwillem Borleffs]

jerrygarciuh wrote:

I would like to add a field or two under certain circumstances. I
have tried

$obj->newfield = 'xxx';
$obj->{'newfield'} = 'yyy';

Both of these should work fine, do you get any error messages?

It would also be useful to see some of the code that generates the initial
object.
JW

[jerrygarciuh]

"Janwillem Borleffs" <[e-mail]> wrote in message
news:42**********************@news.euronet.nl...

jerrygarciuh wrote:

I would like to add a field or two under certain circumstances. I
have tried

$obj->newfield = 'xxx';
$obj->{'newfield'} = 'yyy';

Both of these should work fine, do you get any error messages?

It would also be useful to see some of the code that generates the initial
object.
JW

JW,

Thank you for your rapid reply! Here is the function that builds the
objects from mySQL records. I am thinking my problem is actually caused by
using foreach on the array of objects and in PHP 4 I can't pass reference
like foreach ($arr as &$v).

Any advice most welcome!

jg

function &buildObj($result, $classname) {
if ($result) {
while($row = mysql_fetch_assoc($result)) {
if ($row === null) return null;

/* Create the object */
$obj =& new $classname;

/* Explode the array and set the objects's instance data
*/
foreach($row as $key => $value)
{
$obj->{$key} = $value;
}
$objs[] = $obj;
}
return $objs;
} // end if ($result)
}

[jerrygarciuh]

"jerrygarciuh" <de*****@no.spam.nolaflash.com> wrote in message
news:IDg6e.965$H53.255@lakeread05...

"Janwillem Borleffs" <[e-mail]> wrote in message
news:42**********************@news.euronet.nl...

jerrygarciuh wrote:

I would like to add a field or two under certain circumstances. I
have tried

$obj->newfield = 'xxx';
$obj->{'newfield'} = 'yyy';

Both of these should work fine, do you get any error messages?

It would also be useful to see some of the code that generates the
initial object.
JW

JW,

Thank you for your rapid reply! Here is the function that builds the
objects from mySQL records. I am thinking my problem is actually caused
by using foreach on the array of objects and in PHP 4 I can't pass
reference like foreach ($arr as &$v).

Any advice most welcome!

jg

function &buildObj($result, $classname) {
if ($result) {
while($row = mysql_fetch_assoc($result)) {
if ($row === null) return null;

/* Create the object */
$obj =& new $classname;

/* Explode the array and set the objects's instance data
*/
foreach($row as $key => $value)
{
$obj->{$key} = $value;
}
$objs[] = $obj;
}
return $objs;
} // end if ($result)
}

My tests confirm that my problem is that foreach operates on a copy and i
need to pass by reference or use while().

[Janwillem Borleffs]

jerrygarciuh wrote:

Thank you for your rapid reply! Here is the function that builds the
objects from mySQL records. I am thinking my problem is actually
caused by using foreach on the array of objects and in PHP 4 I can't
pass reference like foreach ($arr as &$v).

Passing arguments by reference to foreach would only be a benefit if you
want to modify them.

The problem is probably that you are doing something like:

$obj = buildObj($result, "stdClass");
$obj->foo = 'bar';

This obviously doesn't work, because buildObj isn't returning an object, but
an array of objects.

If you would do something like the following, it should work fine:

$obj[0]->foo = 'bar';
JW

[jerrygarciuh]

"jerrygarciuh" <de*****@no.spam.nolaflash.com> wrote in message
news:rNg6e.967$H53.934@lakeread05...

"jerrygarciuh" <de*****@no.spam.nolaflash.com> wrote in message
news:IDg6e.965$H53.255@lakeread05...

"Janwillem Borleffs" <[e-mail]> wrote in message
news:42**********************@news.euronet.nl...

jerrygarciuh wrote:
I would like to add a field or two under certain circumstances. I
have tried

$obj->newfield = 'xxx';
$obj->{'newfield'} = 'yyy';
Both of these should work fine, do you get any error messages?

It would also be useful to see some of the code that generates the
initial object.
JW

JW,

Thank you for your rapid reply! Here is the function that builds the
objects from mySQL records. I am thinking my problem is actually caused
by using foreach on the array of objects and in PHP 4 I can't pass
reference like foreach ($arr as &$v).

Any advice most welcome!

jg

function &buildObj($result, $classname) {
if ($result) {
while($row = mysql_fetch_assoc($result)) {
if ($row === null) return null;

/* Create the object */
$obj =& new $classname;

/* Explode the array and set the objects's instance
data */
foreach($row as $key => $value)
{
$obj->{$key} = $value;
}
$objs[] = $obj;
}
return $objs;
} // end if ($result)
}

My tests confirm that my problem is that foreach operates on a copy and i
need to pass by reference or use while().

function forDate($date) { // $date = Y-m-d
$shelters = $this->retrieve("facility = '$_SESSION[facility]'");
$srObj = new ShelterRental;
if ($shelters) {
while ($s = current($shelters) ){
// retrieve today's rentals by shelter
$where = array("date = '$date'", "shelter = '$s->id'");
$rentals = $srObj->retrieve($where);
if ($rentals) {
echo $s->id;
foreach ($rentals as $r) {
$s->renter = $r->renter;
$s->contact = $r->contact;
$s->rentalid = $r->id;
} // foreach
} // if
$rentalInfo[] = $s;
next($shelters);
} // while
} // if
return $rentalInfo;
} // end forDate()