I am trying to put the following math formula in php, but I know to little
of math to do it I guess, maybe somebody can help me out.
This is the formula:
x = (-ln(1) - ln(y/100))*100*z
The values for y and z will be submitted via a form.
Any help is greatly apreciated.
Wim 5 6433
On 2005-04-08, Wim Smit <wi*@vdhosting.nl> wrote: I am trying to put the following math formula in php, but I know to little of math to do it I guess, maybe somebody can help me out.
This is the formula:
x = (-ln(1) - ln(y/100))*100*z
The values for y and z will be submitted via a form. Any help is greatly apreciated.
Start by learning how to submit a variable through a form. Then move on
to processing the variable. The PHP manual will tell you how to do this.
--
Cheers
- Jacob Atzen
Wim Smit wrote: I am trying to put the following math formula in php, but I know to little of math to do it I guess, maybe somebody can help me out.
This is the formula:
x = (-ln(1) - ln(y/100))*100*z
The values for y and z will be submitted via a form. Any help is greatly apreciated.
Wim
The PHP function for natural logarithms is log(), not ln(). Variable names
start with a $ symbol, e.g.:
$x = $_GET['x'];
$y = $_GET['y'];
Fix that, put a semicolon at the end and it should work.
BTW, ln(1) is equal to zero, so you can delete it from your equation.
--
phil [dot] ronan @ virgin [dot] net http://vzone.virgin.net/phil.ronan/
Thanks for the quick reply.
I tried to use this code now:
$x = (- log(1) - log(0.06/100))*100*673356;
The value of $x is 499534596.235
However the value of $x should be 4645225.
U sure log() in PHP does the same as ln()?
Wim
"Philip Ronan" <in*****@invalid.invalid> schreef in bericht
news:BE7C1758.2E294%in*****@invalid.invalid... Wim Smit wrote:
I am trying to put the following math formula in php, but I know to little of math to do it I guess, maybe somebody can help me out.
This is the formula:
x = (-ln(1) - ln(y/100))*100*z
The values for y and z will be submitted via a form. Any help is greatly apreciated.
Wim
The PHP function for natural logarithms is log(), not ln(). Variable names start with a $ symbol, e.g.:
$x = $_GET['x']; $y = $_GET['y'];
Fix that, put a semicolon at the end and it should work.
BTW, ln(1) is equal to zero, so you can delete it from your equation.
-- phil [dot] ronan @ virgin [dot] net http://vzone.virgin.net/phil.ronan/
Submitting a variable won't be the problem, it is getting PHP to do the
formula correctly.
ln() does not show up in the manual, likely there is a way around that, but
I know to little of math on how to solve that. :).
Wim
"Jacob Atzen" <ja***@aub.dk> schreef in bericht
news:sl*******************@tank.aub.dk... On 2005-04-08, Wim Smit <wi*@vdhosting.nl> wrote: I am trying to put the following math formula in php, but I know to little of math to do it I guess, maybe somebody can help me out.
This is the formula:
x = (-ln(1) - ln(y/100))*100*z
The values for y and z will be submitted via a form. Any help is greatly apreciated.
Start by learning how to submit a variable through a form. Then move on to processing the variable. The PHP manual will tell you how to do this.
-- Cheers - Jacob Atzen
Wim Smit wrote: Thanks for the quick reply.
I tried to use this code now:
$x = (- log(1) - log(0.06/100))*100*673356;
The value of $x is 499534596.235
That is correct
However the value of $x should be 4645225.
That is incorrect U sure log() in PHP does the same as ln()?
log() is a natural logarithm function. That's what you want, isn't it?
Use log10() if you want base 10 logarithms
Take a look at <http://uk.php.net/log> and <http://uk.php.net/log10>
--
phil [dot] ronan @ virgin [dot] net http://vzone.virgin.net/phil.ronan/ This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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