Implode an array of multiple variables

[ben3003]

I am trying to put a date in my database in the form dd-mm-yyy, as for
my PHP page is returns 3 variables $date, $month, $year. is ther a way
to put these together? i have tried imploding them but i can't seem to
get them into an array!

here is my code:

$array = array();
$array[] = $Day;
$array[] = $month;
$array[] = $year;

$comma_separated = implode("-", $array);

Thanks

Ben

[Janwillem Borleffs]

ben3003 wrote:

I am trying to put a date in my database in the form dd-mm-yyy, as for
my PHP page is returns 3 variables $date, $month, $year. is ther a way
to put these together? i have tried imploding them but i can't seem to
get them into an array!

here is my code:

$array = array();
$array[] = $Day;
$array[] = $month;
$array[] = $year;

$comma_separated = implode("-", $array);

What do you mean? You are constructing a string from an array and want
to construct an array from that string? Using explode instead of implode
does this, but your intension is unclear to me...
JW

[ben3003]

sorry JW,
I have 3 variables arrive at this page through a POST from a form. it
is a date. However it is in the form 3 variables rater than 1 variable.
the 3 variables are day, month, and year. form here i want to insert
the values into one filed of my MySQL database in the form dd-mm-yyy.
Does this make it clear?
i presumed that an implode function would be best for this.
Ben

[Colin McKinnon]

ben3003 wrote:

I am trying to put a date in my database in the form dd-mm-yyy, as for
my PHP page is returns 3 variables $date, $month, $year. is ther a way
to put these together? i have tried imploding them but i can't seem to
get them into an array!

here is my code:

$array = array();
$array[] = $Day;
$array[] = $month;
$array[] = $year;

$comma_separated = implode("-", $array);

Ugly, but it should have worked. This is neater:

$dash_separated = implode("-", array($day,$month,$year));

but this is better:

$dash_separated = sprintf("%02d-%02d-%04d",$day,$month,$year);

C.

[BKDotCom]

Perhaps register-globals is off (like it shoud be)?
$dash_separated = implode("-",
array($_POST['day'],$_POST['month'],$_POST['year']));

[Jan Pieter Kunst]

ben3003 wrote:

I have 3 variables arrive at this page through a POST from a form. it
is a date. However it is in the form 3 variables rater than 1 variable.
the 3 variables are day, month, and year. form here i want to insert
the values into one filed of my MySQL database in the form dd-mm-yyy.

Is there a compelling reason to not store the date in the standard SQL
format 'YYYY-MM-DD'?

$datestring = "$year-$month-$Day";

Or "$Day-$month-$year" if you really want that order.

JP

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[Michael Fesser]

.oO(Jan Pieter Kunst)

Is there a compelling reason to not store the date in the standard SQL
format 'YYYY-MM-DD'?

$datestring = "$year-$month-$Day";

It could be necessary to use sprintf() to add leading zeros.

Micha

[ben3003]

ok well i am using:
$day = $_POST['StartDay'];
$month = $_POST['StartMn'];
$year = $_POST['StartYr'];

$dash_separated = sprintf("%d-%d-%d",$day,$month,$year);

echo $dash_separated;

and for some reason i am getting the folowing output:
13-0-0
This should be:
13-01-2001
any one?
Ben

[ben3003]

$day = $_POST['StartDay'];
$month = $_POST['StartMn'];
$year = $_POST['StartYr'];

$dash_separated = sprintf("%d-%d-%d",$day,$month,$year);

echo $dash_separated;

this currently is returning
13-00-00
when i would like
13-01-2005

any ideas? thanks ben