Variable assignment using OR operator?

[jerrygarciuh]

Hello,

I would like to set a variable to a default if 2 other vars are undef.
Obviously there are several ways to do this but I would like to do it as I
would in Perl:

$memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';

Is there acorrect way to do this in 1 line in PHP?

TIA,

jg

[Michael Fesser]

.oO(jerrygarciuh)

I would like to set a variable to a default if 2 other vars are undef.
Obviously there are several ways to do this but I would like to do it as I
would in Perl:

$memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';

Is there acorrect way to do this in 1 line in PHP?

$memberState = isset($_REQUEST['ms']) ? $_REQUEST['ms'] : 'Unapproved';

Try if that fits your needs ($_REQUEST contains both POST and GET
variables).

Micha

[jerrygarciuh]

Thanks!

jg
"Michael Fesser" <ne*****@gmx.net> wrote in message
news:8v********************************@4ax.com...

.oO(jerrygarciuh)

I would like to set a variable to a default if 2 other vars are undef.
Obviously there are several ways to do this but I would like to do it as I
would in Perl:

$memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';

Is there acorrect way to do this in 1 line in PHP?

$memberState = isset($_REQUEST['ms']) ? $_REQUEST['ms'] : 'Unapproved';

Try if that fits your needs ($_REQUEST contains both POST and GET
variables).

Micha

[Matt Mitchell]

"jerrygarciuh" <de*****@no.spam.nolaflash.com> wrote in message
news:QPMSd.4029$SF.1615@lakeread08...
: Hello,
:
: I would like to set a variable to a default if 2 other vars are undef.
: Obviously there are several ways to do this but I would like to do it as I
: would in Perl:
:
: $memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';
:
: Is there acorrect way to do this in 1 line in PHP?
:

I believe it would work just like that, you might want brackets though:

$memberState = ($_POST['ms'] || $_GET['ms'] || 'Unapproved');

otherwise, you'll get

if (!($memberState = $_POST['ms']))
{
$GET['ms'] or 'Unapproved';
}
which is probably not what you want

[jerrygarciuh]

Actually that performs as though it is a conditional:

echo $memberState = ($x || $y || 'Unapproved');

outputs 1

Surely there is a construct for this in PHP? Michaels solution, while
helpful in that case does not solve the over all problem of an elegant 1
liner which does this lovely trick.

Thanks for the reply!

jg

"Matt Mitchell" <m_****************************@metalsponge.net> wrote in
message news:b1********************@fe3.news.blueyonder.co .uk...

"jerrygarciuh" <de*****@no.spam.nolaflash.com> wrote in message
news:QPMSd.4029$SF.1615@lakeread08...
: Hello,
:
: I would like to set a variable to a default if 2 other vars are undef.
: Obviously there are several ways to do this but I would like to do it as
I
: would in Perl:
:
: $memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';
:
: Is there acorrect way to do this in 1 line in PHP?
:

I believe it would work just like that, you might want brackets though:

$memberState = ($_POST['ms'] || $_GET['ms'] || 'Unapproved');

otherwise, you'll get

if (!($memberState = $_POST['ms']))
{
$GET['ms'] or 'Unapproved';
}
which is probably not what you want

[Jan Pieter Kunst]

jerrygarciuh wrote:

an elegant 1
liner which does this lovely trick.

This is just my personal opinion, but since I started writing large
programs that have to be maintainable and understandable to myself and
others, I have really come to dislike 'elegant one liners'.

If I understood your problem correctly, I would simply write this:
(combining $_POST and $_GET in S_REQUEST):
if (isset($_REQUEST['ms']))
$memberState = $_REQUEST['ms'];
else
$memberState = 'Unapproved';
I'd rather have four lines which are immediately obvious than one line
which is a puzzle, however elegant it may be.

But to each his own, YMMV, etc.

JP

--
Sorry, <de*****@cauce.org> is a spam trap.
Real e-mail address unavailable. 5000+ spams per month.