what's this? '->'

[gmac63]

All,

I know that '->' is used in object oriented PHP, but I saw this in the
Moodle code (www.moodle.org)

$CFG->dbtype = 'mysql'; // mysql or postgres7 (for now)
$CFG->dbhost = 'localhost'; // eg localhost or db.isp.com
$CFG->dbname = 'moodle'; // database name, eg moodle
$CFG->dbuser = 'root'; // your database username
$CFG->dbpass = 'mypassword'; // your database password
$CFG->prefix = 'mdl_'; // Prefix to use for all table names

You can "echo $CFG->dbtype;" and get "mysql"

This isn't calling functions from an object, rather seems to be
applying properties to a new "object"??? There is no $something = new
ClassName, so This is what I figure.

Its been a while since I cooded PHP and have never seen this. This
seems like a realy good way to apply a number of atttribs to a
"variable" without having to create an array -- unless that is a
shorthand way of creating an array...

Thanks

-Wes Yates

[Mark]

gm****@charter.net wrote:

All,

I know that '->' is used in object oriented PHP, but I saw this in the
Moodle code (www.moodle.org)

$CFG->dbtype = 'mysql'; // mysql or postgres7 (for now)
$CFG->dbhost = 'localhost'; // eg localhost or db.isp.com
$CFG->dbname = 'moodle'; // database name, eg moodle
$CFG->dbuser = 'root'; // your database username
$CFG->dbpass = 'mypassword'; // your database password
$CFG->prefix = 'mdl_'; // Prefix to use for all table names

You can "echo $CFG->dbtype;" and get "mysql"

This isn't calling functions from an object, rather seems to be
applying properties to a new "object"??? There is no $something = new
ClassName, so This is what I figure.

Its been a while since I cooded PHP and have never seen this. This
seems like a realy good way to apply a number of atttribs to a
"variable" without having to create an array -- unless that is a
shorthand way of creating an array...

you need to read this:

http://www.php.net/manual/en/language.oop5.basic.php
they're member variables, which you can also define and get/set on an
object.
mark.

--
I am not an ANGRY man. Remove the rage from my email to reply.

[Wayne]

On 11 Feb 2005 09:15:55 -0800, gm****@charter.net wrote:

You can "echo $CFG->dbtype;" and get "mysql"

This isn't calling functions from an object, rather seems to be
applying properties to a new "object"??? There is no $something = new
ClassName, so This is what I figure.
If you use a variable as an object PHP automatically creates an object
(I believe this behavior is depreciated in PHP5). There's an implicit
"$something = new stdClass;" if you use a variable as an object.
This
seems like a realy good way to apply a number of atttribs to a
"variable" without having to create an array -- unless that is a
shorthand way of creating an array...

Yeah, I use this all the time. It works with any class...

class SomeClass()
{
}

$test = new SomeClass();
$test->newVar = 'hello';

echo $test->newVar; // prints 'hello';

[gmac63]

WOW! Now that _is_ cool. I figures as much that it creates an object.
The "->" is what PHP uses in oop. Saaaa-wweeeeeet!

Thanks all!

-Wes

Wayne wrote:

On 11 Feb 2005 09:15:55 -0800, gm****@charter.net wrote:

You can "echo $CFG->dbtype;" and get "mysql"

This isn't calling functions from an object, rather seems to be
applying properties to a new "object"??? There is no $something = newClassName, so This is what I figure.
If you use a variable as an object PHP automatically creates an

object (I believe this behavior is depreciated in PHP5). There's an implicit "$something = new stdClass;" if you use a variable as an object.

This
seems like a realy good way to apply a number of atttribs to a
"variable" without having to create an array -- unless that is a
shorthand way of creating an array...

Yeah, I use this all the time. It works with any class...

class SomeClass()
{
}

$test = new SomeClass();
$test->newVar = 'hello';

echo $test->newVar; // prints 'hello';