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regex - everthing between quotes

ab
Hi,

I'm trying to get a preg_replace to replace wihhin a large string
variable, only words that are NOT preceded by a " or a >. For
instance, in:
While this sentence <em>does</em> serve as a useful example, it is
otherwise uninteresting, and does stand much of a chance, however
"useful" it might be, of publication.

I want the expression to replace the does that is not in em tags, and
the useful that is not in quotes.

Any assitance would be great.
Jul 17 '05 #1
1 2206
ab wrote:
I want the expression to replace the does that is not in em tags, and
the useful that is not in quotes.


$sentence = preg_replace(
array(
'#(?<!")useful(?!")#',
'#(?<!<em>)does(?!</em>)#'
),
"",
$sentence
);
JW

Jul 17 '05 #2

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