How to get which non-existend page led to error404.php

[Emre Sevinc]

Hi,

I have my error404.php page which includes
these lines:

echo "Document not found...";
echo $_SERVER['REDIRECT_URL'];

I also created a dummy link on another page, something
like

<a href=http://example.com/dummylinktogotoerrorpage>dummy</a>

When I click on the link I go to the error page
however all I see is:

Document not found.../error404.php

But I expected to see what caused the error, so that I can
record it to see if somebody is referring to some non-existent
pages on my site.

I used $_SERVER['REDIRECT_URL'] because of this O'Reilly
article: http://www.onlamp.com/pub/a/onlamp/2...avidsklar.html

Unfortunately either I miss something, or the article does not
give correct info (or something's stragen with the configuration
of the Apache at my hosting service).

Any ideas? What should I check? Why $_SERVER['REDIRECT_URL'] hold
the value "/error404.php"? How can I find the value
I'm looking for?

Thanks in advance.

--
Emre Sevinc

eMBA Software Developer Actively engaged in:
http:www.bilgi.edu.tr http://ileriseviye.org
http://www.bilgi.edu.tr http://fazlamesai.net
Cognitive Science Student http://cazci.com
http://www.cogsci.boun.edu.tr

[Janwillem Borleffs]

Emre Sevinc wrote:

Any ideas? What should I check? Why $_SERVER['REDIRECT_URL'] hold
the value "/error404.php"? How can I find the value
I'm looking for?

$_SERVER['REQUEST_URI']
JW

[Emre Sevinc]

"Janwillem Borleffs" <[e-mail]> writes:

Emre Sevinc wrote:

Any ideas? What should I check? Why $_SERVER['REDIRECT_URL'] hold
the value "/error404.php"? How can I find the value
I'm looking for?

$_SERVER['REQUEST_URI']

Modified the code:

echo "Document not found...\n<br>";
echo $_SERVER['REDIRECT_URL'] . "<br>";
echo $_SERVER['REQUEST_URI'] . "<br>";

Then clicked on a dummy linked on the same site to
reach the error page but I get this output:

Document not found...
/error404.php
/error404.php


--
Emre Sevinc

eMBA Software Developer Actively engaged in:
http:www.bilgi.edu.tr http://ileriseviye.org
http://www.bilgi.edu.tr http://fazlamesai.net
Cognitive Science Student http://cazci.com
http://www.cogsci.boun.edu.tr

[Janwillem Borleffs]

Emre Sevinc wrote:

Then clicked on a dummy linked on the same site to
reach the error page but I get this output:

Document not found...
/error404.php
/error404.php

Works for me with an .htaccess file with the ErrorDocument directive
pointing to a PHP file in which $_SERVER['REQUEST_URI'] is printed.

Check your server configuration or use the output of phpinfo() to examin the
environmental variables.
JW

[Emre Sevinc]

"Janwillem Borleffs" <[e-mail]> writes:

Emre Sevinc wrote:

Then clicked on a dummy linked on the same site to
reach the error page but I get this output:

Document not found...
/error404.php
/error404.php

Works for me with an .htaccess file with the ErrorDocument directive
pointing to a PHP file in which $_SERVER['REQUEST_URI'] is printed.

Check your server configuration or use the output of phpinfo() to examin the
environmental variables.

"echo"ing phpinfo() created an output like the one you can see
at the end of my message.

All I did was to use the web control panel of my hosting
service, enter the addres of my error404.php as the error page
and then enter the code that I described there and upload my newly
created error404.php file there. No matter what I did I couldn't get
the dummy link's name. Strange but that's what I have. Can it be something
with the configuration?

================================================== ======================
PHP Version 4.3.10

System Linux linux01 2.4.24 #1 SMP Tue Aug 10 00:10:23 EEST 2004 i686

Build Date Dec 22 2004 17:45:02

Configure Command './configure'
'--prefix=/sys/php-4.3.10-apache-1.3.33'
'--with-apxs=/sys/apache-1.3.33/bin/apxs'
'--with-mysql=/mysql/'
'--with-curl=/sys/curl-7.11.1/'
'--enable-ftp' '--enable-safe-mode'
'--with-gd' '--with-xpm-dir' '--with-ttf'
'--with-jpeg-dir' '--with-png-dir' '--enable-gd-native-ttf'
'--with-freetype-dir=/usr/include/freetype2/' '--with-xpm'
'--with-png-dir' '--with-zlib-dir'
'--with-zlib' '--enable-calendar'
'--with-gettext' '--enable-track-vars'
'--with-config-file-path=/apache/conf/' '--enable-exif'
'--enable-sockets' '--with-openssl'

Server API Apache
Virtual Directory Support disabled
Configuration File (php.ini) Path /sys/apache_standart/conf/php.ini
PHP API 20020918
PHP Extension 20020429
Zend Extension 20021010
Debug Build no
Thread Safety disabled
Registered PHP Streams php, http, ftp, https, ftps, compress.zlib
================================================== =========================
--
Emre Sevinc

eMBA Software Developer Actively engaged in:
http:www.bilgi.edu.tr http://ileriseviye.org
http://www.bilgi.edu.tr http://fazlamesai.net
Cognitive Science Student http://cazci.com
http://www.cogsci.boun.edu.tr

[Janwillem Borleffs]

Emre Sevinc wrote:

All I did was to use the web control panel of my hosting
service, enter the addres of my error404.php as the error page
and then enter the code that I described there and upload my newly
created error404.php file there. No matter what I did I couldn't get
the dummy link's name. Strange but that's what I have. Can it be
something with the configuration?

It sure has to do with the server configuration. Possibly, erroneous
requests are redirected with a regular 301/302 response code, which would
explain why you get the error page itself as the value of
$_SERVER['REQUEST_URI']. Ask your provider for more info.
JW