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How to display image from mysql

selvasoft
34 New Member
i am doing a site for spinning mills
i need to display all the products that the company offers
Am using mysql database and word press (CMS)

i want to display my images with code number as like my attachment
Attached Images
File Type: jpg shade.jpg (11.9 KB, 609 views)
Mar 9 '10 #1
19 9290
Atli
5,058 Recognized Expert Expert
Hey.

What have you done so far?
And what are you having trouble with?
Mar 9 '10 #2
selvasoft
34 New Member
i want to display my images with that code. and also i want upload tat scanned images in our database.that time i want group that image color vise.
Mar 9 '10 #3
selvasoft
34 New Member
hey
Am doing that manual not writing any queries
Mar 9 '10 #4
Atli
5,058 Recognized Expert Expert
Ok. What have you done so far?

I don't know much about the specifics of WordPress, but I do know that in plain PHP this should be a simple matter of querying the data from the database, looping through the results and printing each one.

@selvasoft
What do you mean? If you plan on interacting with a MySQL database, you will have to write a few queries.
Mar 9 '10 #5
selvasoft
34 New Member
Expand|Select|Wrap|Line Numbers
  1. <?
  2. $dbcnx = @mysql_connect("localhost", "root", "red");
  3.  
  4. if (!$dbcnx)
  5. {
  6. echo( "connection to database server failed!" );
  7. exit();
  8. }
  9.  
  10. if (! @mysql_select_db("my_db") )
  11. {
  12. echo( "Image Database Not Available!" );
  13. exit();
  14. }
  15.  
  16. $img = $_REQUEST["img"];
  17. $result = @mysql_query("SELECT * FROM images WHERE imgid=" . $img . "");
  18.  
  19. if (!$result)
  20. {
  21. echo("Error performing query: " . mysql_error() . "");
  22. exit();
  23. }
  24.  
  25. while ( $row = mysql_fetch_array($result) )
  26. {
  27. $imgid = $row["imgid"];
  28. }
  29.  
  30. echo base64_decode($encodeddata);
  31. ?>


this is not work what problem in that
Mar 9 '10 #6
Atli
5,058 Recognized Expert Expert
I'm not surprised, seeing as this code was copy/pasted from an online tutorial (yes I can use Google too), one that was not meant to be put as-is into a working product. - It's meant to teach, not to be used.

You won't get a working solution by copy/paste alone. You need to actually know, or learn, PHP and MySQL to get this working. - And we will most certainly not be doing it for you.

If you want our help, tell us specifically what you are having trouble with. We aren't just going to take code you copied from some random tutorial and fix it up so you can copy it back into your project.
Mar 9 '10 #7
selvasoft
34 New Member
dear Atli

Please help me. When we want to display our images from database that time we start our script like
<img src="filename.p hp?id="imageid" >
what is the use of this..
and where that image id will retrieve. I think that is our table id. is it correct or not.
Mar 10 '10 #8
Atli
5,058 Recognized Expert Expert
The "imageid" there is the ID of an image from your database, which the "filename.p hp" script takes and retrieves, returning it to the <img>
Mar 10 '10 #9
selvasoft
34 New Member
i cant store my image to database
please check the following code is correct or not because that code did not return any
Expand|Select|Wrap|Line Numbers
  1. <?php
  2. $connection=mysql_connect("localhost","root","mypassword");
  3. if(!$connection)
  4. {
  5.  
  6. die('Not connect'.mysql_error());
  7. }
  8. // Create table
  9. mysql_select_db("my_db", $connection);
  10. $sql = "CREATE TABLE myimage
  11. (
  12. id int(5) NOT NULL auto_increment. ,
  13. image longblob NOT NULL,
  14. description char(50)
  15. )";
  16. mysql_query($sql,$connection);
  17. echo "table Created";
  18. mysql_select_db("my_db",$connection);
  19.  
  20.     $imgdata = file_get_contents($_FILES['fimage']['tmp_name']);
  21.     $fpo      = fopen($imgdata, 'r'); 
  22.     $imgdata1 = fread($fpo, filesize($imgdata));
  23.     $imgdata1 = mysql_real_escape_string($imgdata1 );
  24.  
  25. $sql = "INSERT INTO myimage (image,description) VALUES 
  26. ('$_POST['fdescription']','$imgdata1')";
  27. if (!mysql_query($sql,$connection))
  28. {
  29.  
  30.  die('Error'.mysql_error());
  31. }
  32. print ="Description;$fdescription";
  33. mysql_close($connection);
  34. ?>
Mar 10 '10 #10

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