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Having trouble or possibly i am just TOO stupid to understand

57 New Member
I have created a form which is as Follow:


<form action="fleet-of-car.php" method="post">
<select name="FORM">
<option value="ALL CARS"/>All Cars
<br />
<input type="submit" value="Show INFO" />


Now what i am trying to achieve is as follow:

1: By submitting the first option in this case All cars, the form should connect to DB and run the query, which if i am not wrong is as follow:



//make a connection

mysql_connect(" server", "user", "password") ;
mysql_select_db ('db', $connection);

//Run the Sql
$results = mysql_query("SE LECT * FROM car



The question i have is, what happens if the user selcets option 2 or even 3? The query will be different since it will read from different Mysql table to get the result, but what is the script required for this type query.

I though by using IF(isset), i might get away with it but i am not too familiar with it and i have no idea even where to start, WHILE statement should do it but i am just getting more confused.

Any help would be great guys, and thx well in advance

Feb 16 '07 #1
1 1204
5,058 Recognized Expert Expert

If Im understanding you correctly, you would need to do something like this.


$option = $_POST['Name'];

// Find the selected option
if($option == "whatever")
$query = "SELECT * FROM table1";
else if($option == "somethingelse" )
$query = "SELECT * FROM table2";
// ....
$query = "";

// Run the query
if($query != "")
$DB = mysql_connect(" h", "u", "p") or die("omg it didnt work!");
mysql_select_db ("d", $DB) or die("aaah! so close!");

$result = mysql_query($qu ery) or die("<p>MySQL Error: <br />". mysql_error() ."</p>");

// Do something with results
// Error msg if the option is invalid
echo "Invalid option";


Hope this helps.
Feb 16 '07 #2

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